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Find the sum of all integers of 3 digits that are divisible by 11. (a) 49,335 (b) 41,338 (c) 44,550 (d) 47,300 |
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Answer» Correct option(c) 44,550 Explanation: The required sum would be given by the sum of the series 110, 121, 132, .... 990. The number of terms in this series = (990 − 110)/11 + 1 = 80 + 1 = 81. The sum of the series = 81 × 550 (average of 110 and 990) = 44,550. |
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