100525 + Interview Questions in GENERAL QA IN GENERAL AWARENESS Page 100 InterviewSolution

4951.	The nuclear charge (`Ze`) is non uniformlly distribute with in a nucleus of radius `r`. The charge density `rho(r)` (charge per unit volume) is dependent only on the radial distance r form the centre of the nucleus s shown in figure. The electric field is only along the radial direction. For a=0 the value of d (maximum value of `rho` as shown in the figure) is A. `(3Ze)/(4piR^3)`B. `(3Ze)/(piR^3)`C. `(4Ze)/(3piR^3)`D. `(Ze)/(3piR^3)`
Answer» Net charge within `rltR` is constant, hence , electric field is independent of a. `q=int_(0)^(R)(d)/(R)(R-x)4pix^(2)dx=Ze` `d=(3Ze)/(piR^(3))` if within a phere `rho` is constant then `Epropr`

Discussion

4952.	The nuclear charge (`Ze`) is non uniformlly distribute with in a nucleus of radius `r`. The charge density `rho(r)` (charge per unit volume) is dependent only on the radial distance r form the centre of the nucleus s shown in figure. The electric field is only along the radial direction. For a=0 the value of d (maximum value of `rho` as shown in the figure) is A. `(3Ze)/(4piR^(3))`B. `(3Ze)/(piR^(3))`C. `(4Ze)/(3piR^(3))`D. `(Ze)/(3piR^(3))`
Answer» Correct Answer - B

Discussion

4953.	A heavy but uniform rope of lenth L is suspended from a ceiling. (a) Write the velocity of a transverse wave travelling on the string as a function of the distance from the lower end. (b) If the rope is given a sudden sideways jerk at the bottom, how long will it take for the pulse to reach teh celling ? (c ) A particle is dropped from the ceiling at the instant the bottom end is given the jerk where will the particle meet the pulse ?A. at a distance `(2L)/(3)` from the bottomB. at a distance `(L)/(3)` from the bottomC. at a distance `(3L)/(4)` from the bottomD. none of the above
Answer» Correct Answer - B `v = sqrt(gh) :. (dh)/(dt) = sqrt(gh) :. T = int_(o)^(h) (dh)/(sqrt(gh))` or `t = 2 sqrt((h)/(g))` Now at the time of meeting, Time of fall of particle `=` time of wave pulse on reaching up to these `sqrt((2(L - h))/(g)) = 2 sqrt((h)/(g)) :. h = (L)/(3)`

Discussion

4954.	A proton and a ionized deuterium are initially at rest and are accelerated through the same potential difference. Which of the following is false concerning the final properties of the two particles ?
Answer» Correct Answer - B The mass of deuteron is twice, so momentum is different.

Discussion

4955.	The nuclear charge (`Ze`) is non uniformlly distribute with in a nucleus of radius r. The charge density `rho(r)` (charge per unit volume) is dependent only on the radial distance r form the centre of the nucleus s shown in figure. The electric field is only along the radial direction. The electric field at `r=R` isA. Independent of aB. Directly proportional to aC. Directly proportional to `a^(2)`D. Inversely proportional to a
Answer» Correct Answer - A `E(4pi R^(2))=((Ze))/in_(0)rArr E=(Ze)/(4pi in_(0) R^(2))` `rArr` Independent of a

Discussion

4956.	A man in a balloon rising vertically with an acceleration of 5ms−2 releases a ball 2 second after the balloon is let go from the ground. The greatest height above the ground reached by the ball is :
Answer» Height traveled by ball (with balloon) in 2 sec h₁=1/2at²=1/2×5×2²= 10 m Velocity of the balloon after 2 sec v = at = 5×2 = 10 m/s Now if the ball is released from the balloon then it acquire same velocity in upward direction. Let it move up to maximum height h₂ v²=u²−2gh₂ => 0=(10)²−2×(10)×h₂ ∴ h₂ = 5m Greatest height above the ground reached by the ball = h₁+h₂= 10+5 = 15 m

4956.

A man in a balloon rising vertically with an acceleration of 5ms−2 releases a ball 2 second after the balloon is let go from the ground. The greatest height above the ground reached by the ball is :

Answer»

Height traveled by ball (with balloon) in 2 sec

h₁=1/2at²=1/2×5×2²= 10 m

Velocity of the balloon after 2 sec

v = at = 5×2 = 10 m/s

Now if the ball is released from the balloon then it acquire same velocity in upward direction.

Let it move up to maximum height h₂

v²=u²−2gh₂

=> 0=(10)²−2×(10)×h₂

∴ h₂ = 5m

Greatest height above the ground reached by the ball = h₁+h₂= 10+5 = 15 m

Discussion

4957.	To be effective, the ideas of inclusive nationalism had to be built into the .......... a) Constitution b) Parliament c) Supreme Court d) Legislature
Answer» (a) Constitution

Discussion

4958.	A system consists of two coaxial current carrying circular loops as shown in Fig. The self inductance of loop 1 is `L_(1)` and self inductance of loop 2 is `L_(2)`. Magnitude of mutual inductance is M. If at any instant current flowing through loop 1 and loop 2 are `i_(1) and i_(2)` respectively, then total magnetic energy of the system is A. `1/2 L_(1)i_(1)^(2)+1/2L_(2)i_(2)^(2)-\|M\|i_(1)i_(2)`B. `1/2 L_(1)i_(1)^(2)+1/2L_(2)i_(2)^(2)+\|M\|i_(1)i_(2)`C. `1/2 L_(1)i_(2)^(2)+1/2L_(2)i_(2)^(1)-\|M\|i_(1)i_(2)`D. `1/2 L_(1)i_(1)^(2)+1/2L_(2)i_(2)^(2)`
Answer» Correct Answer - A Notice that meganetic field due to left coil is towards left. Since magnetic field due to right coil is also towards left, so it increases flux associated with left coil. To oppose it, induced flux associated with left coil. To oppose it, induced current due to mutual induction opposes the original current in left coil.

Discussion

4959.	In frequency modulation, amplitude of modulated wave is A. positive B. negative C. constant D. zero
Answer» C. constant.

Discussion

4960.	Geostationary satellite has period A. twice of Earth B. same as Earth C. half of Earth D. quarter of Earth
Answer» B. same as Earth

Discussion

4961.	Each digit in a binary number is known as a A. bit B. byte C. number D. digit
Answer» The Correct option is A. bit

Discussion

4962.	Phenomena in which signal transmitted in one circuit creates undesired effect in other circuit is known as A. crosstalk B. signal attenuation C. sampling D. crosslinking
Answer» D. crosslinking

Discussion

4963.	Value of sampled signal is used to produce a A. binary number B. decimal number C. octal number D. all of above
Answer» A. binary number

Discussion

4964.	Digital number 9 can be represented in binary number as A. 110 B. 1001 C. 1010 D. 1011
Answer» The Correct option is B. 1001

Discussion

4965.	High quality music only needs frequencies up to A. 10 Hz B. 15 Hz C. 20 kHz D. 15 kHz
Answer» The Correct option is D. 15 kHz

Discussion

4966.	Binary system has base A. 10 B. 11 C. 1 D. 2
Answer» The Correct option is D. 2

Discussion

4967.	Unwanted signal that distorts a transmitted signal is called A. analogue B. noise C. digital D. tuning
Answer» The Correct option is B. noise

Discussion

4968.	In FM, frequency of modulated wave varies with A. amplitude B. time C. wavelength D. energy
Answer» The Correct option is B. time

Discussion

4969.	In a detector, output circuit consists of `R = 10kOmega and C = 100 p F.` Calculate the frequency of carrier signal it can detect.A. `gt gt 1MHz`B. `0.1 kHz`C. `gt gt 1GHz`D. `10^(3) Hz`
Answer» Correct Answer - A Here `R = 10 kOmega = 10^(4) Omega` `C = 100 pF = 10^(-10) F` Time constant of the circuit `tau = RC = 10^(4) xx 10^(-10) = 10^(-6) s` For demodualation, `(1)/(f_(c)) lt lt RC` or `f_(c) gt gt (1)/(RC)` or `f_(c) gt gt (1)/(10^(-6)) = 10^(6) Hz` Therefore, frequency of carrier singnal must be much greater than `1 MHz`.

Discussion

4970.	A communication channel with additive white Gaussian nose, has a bandwidth of 4 kHz and SNR of 15. Its channel capacity is1. 1.6 kbps2. 16 kbps3. 32 kbps4. 256 kbps
Answer» Correct Answer - Option 2 : 16 kbps Channel capacity, \({\rm{C}} = {\rm{B}}{\log _2}\left( {1 + {\rm{SNR}}} \right)\;bits/sec\) \(\begin{array}{l}\Rightarrow {\rm{C}} = 4{\log _2}\left( {1 + 15} \right){\rm{kbits}}/{\rm{sec}}\\\Rightarrow {\rm{C}} = 16{\rm{\;kbps}}\end{array}\)

4970.

A communication channel with additive white Gaussian nose, has a bandwidth of 4 kHz and SNR of 15. Its channel capacity is1. 1.6 kbps2. 16 kbps3. 32 kbps4. 256 kbps

Answer» Correct Answer - Option 2 : 16 kbps

Channel capacity, \({\rm{C}} = {\rm{B}}{\log _2}\left( {1 + {\rm{SNR}}} \right)\;bits/sec\)

\(\begin{array}{l}\Rightarrow {\rm{C}} = 4{\log _2}\left( {1 + 15} \right){\rm{kbits}}/{\rm{sec}}\\\Rightarrow {\rm{C}} = 16{\rm{\;kbps}}\end{array}\)

Discussion

4971.	The output voltage of a CE amplifier is a. Amplified b. Inverted c. 180 degrees out of phase with the input d. All of the above
Answer» (d) All of the above

Discussion

4972.	The voltage across the load resistor of a CE amplifier is a. Dc and ac b. DC only c. AC only d. Neither dc nor ac
Answer» The correct answer is: (c) AC only

Discussion

4973.	The capacitor that produces an ac ground is called a a. Bypass capacitor b. Coupling capacitor c. Dc open d. Ac open
Answer» (a) Bypass capacitor

Discussion

4974.	The emitter of a CE amplifier has no ac voltage because of the a. DC voltage on it b. Bypass capacitor c. Coupling capacitor d. Load resistor
Answer» (b) Bypass capacitor

Discussion

4975.	An op amp has an open base resistor. The output voltage will be a. Zero b. Slightly different from zero c. Maximum positive or negative d. An amplified sine wave
Answer» (c) Maximum positive or negative

Discussion

4976.	In an ac amplifier using an op amp with coupling and bypass capacitors, the output offset voltage is a. Zero b. Minimum c. Maximum d. Unchanged
Answer» The correct answer is: (b) Minimum

Discussion

4977.	What is minimum and maximum mode system configuration of 8086 ?
Answer» 8086 SYSTEM CONFIGURATION IN MINIMUM MODE:- As shown in figure interfacing of 8286 bus transceiver 8284 clock generator , the 8282 latch with 8086 microprocessor in minimum mode . The MN/MX’ pin is mode high to support minimum mode. The 8282 latch is used to DE multiplex the address /Data bus line to separate address and data bus . The ALE (Address Latch Enable) Signal is used to latch the address from address and data lines. The 8284 clock generator is used to provide the CLK, READY, signals to the 8086 microprocessor. The 8284 generates the ready signal in synchronization with clock based on input at RDY1 pin. The RDY2 pin is connected in this configuration. The reset the 8086 microprocessor the reset pin remain high for 50ms. The data bus is bidirectional in nature. To create a separate data bus from address/data bus two Intel 8286 bidirectional bus Transceiver is used. DT/R’ and DEN’ signal output of8086 microprocessor or are connected to 8086 as T and OE’ respectively. 8086 SYSTEM CONFIGURATION IN MAXIMUM MODE:- As shown in figure the interfacing of 8286 bus transceiver , 8284 clock generator , 8282 latch with 8086 microprocessor in this case the MN/MX’ is made low to support the maximum mode operation. The ALE ,DT/R’ and DEN’ signal are generated by 8288 bus controller. The IOB pin is grounded .it indicates that the 8288 is operating in system bus in which all the signals are active. S2’,S1’,S0’ status signal of 8086 microprocessor are input to the 8288 which decodes them and generates INTA’ , MRDC’ ,IORC’ , IOWC’ , ANWC’, and AIOWC, signals .These signal are used for interfacing the 8086 microprocessor to memory and I/O device.

4977.

What is minimum and maximum mode system configuration of 8086 ?

Answer»

8086 SYSTEM CONFIGURATION IN MINIMUM MODE:-

As shown in figure interfacing of 8286 bus transceiver 8284 clock generator , the 8282 latch with 8086 microprocessor in minimum mode .

The MN/MX’ pin is mode high to support minimum mode. The 8282 latch is used to DE multiplex the address /Data bus line to separate address and data bus .
The ALE (Address Latch Enable) Signal is used to latch the address from address and data lines.
The 8284 clock generator is used to provide the CLK, READY, signals to the 8086 microprocessor. The 8284 generates the ready signal in synchronization with clock based on input at RDY1 pin. The RDY2 pin is connected in this configuration.
The reset the 8086 microprocessor the reset pin remain high for 50ms.
The data bus is bidirectional in nature. To create a separate data bus from address/data bus two Intel 8286 bidirectional bus Transceiver is used.
DT/R’ and DEN’ signal output of8086 microprocessor or are connected to 8086 as T and OE’ respectively.

8086 SYSTEM CONFIGURATION IN MAXIMUM MODE:-

As shown in figure the interfacing of 8286 bus transceiver , 8284 clock generator , 8282 latch with 8086 microprocessor in this case the MN/MX’ is made low to support the maximum mode operation.

The ALE ,DT/R’ and DEN’ signal are generated by 8288 bus controller.
The IOB pin is grounded .it indicates that the 8288 is operating in system bus in which all the signals are active.
S2’,S1’,S0’ status signal of 8086 microprocessor are input to the 8288 which decodes them and generates INTA’ , MRDC’ ,IORC’ , IOWC’ , ANWC’, and AIOWC, signals .These signal are used for interfacing the 8086 microprocessor to memory and I/O device.

Discussion

4978.	Camber is ______if the tilt is outwards at the topa) Minimum b) Maximum c) Positive d) Negative
Answer» Camber is Positive if the tilt is outwards at the top.

Discussion

4979.	Which of the following process represents a `gamma- decay`?A. `._(X)^(A)X+gamma rarr ._(Z-1)^(A)X+a+b`B. `._(Z)^(A)X+_(0)^(1)nrarr_(Z-2)^(A-3)X+c`C. `._(Z)^(A)X rarr _(Z)^(A)X + f`D. `._(Z)^(A)X+_(-1)^(0)e rarr _(Z-1)^(A)X+g`
Answer» Correct Answer - C

Discussion

4980.	shows a circuit used in an experiment to detrmine the emf and interanl resistance of the battery C. A graph was plotted of the potential difference V between the terminals of the battery against the current I, which was varied by adjusting the rheostat. The graph is shown in x and y are the intercepts of the graph with the axes as shown. What is the internal resistance of the battery? A. xB. yC. x/yD. y/x
Answer» Correct Answer - D d. As `V = epsilon - Ir` From graph it is clear that slope `= -r = -y//x` or `r = y//x`.

Discussion

4981.	Molality of pure gas A is `(50)/(1.2)m`. Then molar mass (in gm/mol) of gas will be:
Answer» `m=(n_(A)xx1000)/(W_(A)(gm))=(W_(A))/(M.Wt._(A))xx(1000)/(W_(A))=(1000)/(M.Wt._(A))` `(50)/(12)=(1000)/(M.Wt._(A))=(24)/(3)=8`

Discussion

4982.	The potential energy of electron in fourth shell of `He^(oplus)` ion is `:-`A. `-(RCh)/(4)`B. `-(RCh)/(2)`C. `(RCh)/(2)`D. `-(RCh)/(8)`
Answer» Correct Answer - B

Discussion

4983.	Calculate the molality of solution containing 5.3 gm of sodium carbonate in 400 gm of water.
Answer» Given, weight of Na₂CO₃=5.3g weight of water = 400g = 0.4kg Gram molecular weight of Na₂CO₃ is 106g => Number of moles of Na₂CO₃= 5.3/106 =1/20 molality = number of moles of solute/ mass of solvent(in kg) =>molality=(1/20)/(0.4)=0.125

4983.

Calculate the molality of solution containing 5.3 gm of sodium carbonate in 400 gm of water.

Answer»

Given, weight of Na₂CO₃=5.3g

weight of water = 400g = 0.4kg

Gram molecular weight of Na₂CO₃ is 106g

=> Number of moles of Na₂CO₃= 5.3/106

=1/20

molality = number of moles of solute/ mass of solvent(in kg)

=>molality=(1/20)/(0.4)=0.125

Discussion

4984.	If radius of second shell of `Li^(+2)` ion is `R` `A`, then the radius of its third shell will be `:-`A. `(9R)/(4)`B. `(4R)/(9)`C. `(3R)/(2)`D. `(2R)/(3)`
Answer» Correct Answer - A

Discussion

4985.	It `100 mL` of `0.6 N H_(2)SO_(4)` and `200 mL` of `0.3 N HCl` are mixed together, the normality of the resulting solution will beA. `(2N)/(5)`B. `(N)/(10)`C. `(N)/(5)`D. `(N)/(20)`
Answer» Correct Answer - C

Discussion

4986.	The normality of H2SO4 in the solution obtained on mixing 100 mL of 0.1 M H2SO4 with 50 mL of 0.1 M NaOH is _____×10–1 N. (Nearest Integer)
Answer» No. of equivalents of H₂SO₄ = 100 × 0.1 × 2 = 20 No. of equivalents of NaOH = 50 × 0.1 = 5 No. of equivalents of H₂SO₄ left = 20 – 5 = 15 ⇒ \(150 \times x = 15\) \(x = \frac 1{100} = 0.1 N = 1 \times 10^{-1}N\)

4986.

The normality of H2SO4 in the solution obtained on mixing 100 mL of 0.1 M H2SO4 with 50 mL of 0.1 M NaOH is _____×10–1 N. (Nearest Integer)

Answer»

No. of equivalents of H₂SO₄ = 100 × 0.1 × 2 = 20

No. of equivalents of NaOH = 50 × 0.1 = 5

No. of equivalents of H₂SO₄ left = 20 – 5 = 15

⇒ \(150 \times x = 15\)

\(x = \frac 1{100} = 0.1 N = 1 \times 10^{-1}N\)

Discussion

4987.	In extraction of iron, limestone is used forA. Formation of slagB. Reduction of Fe oreC. Purification of Fe formedD. Oxidation of Fe ore
Answer» Correct Answer - A Limestone acts as flux

Discussion

4988.	Chlorination of ethane is carried out in presence ofA. anhydrous `AlBr_(3)`B. mercuric chlorideC. ultraviolet lightD. zinc chloride
Answer» Correct Answer - C Chlorination of alkane is free radical substition reaction, hence it is carried out in the presence of ultra violet light.

Discussion

4989.	Identify the equation in which change in enthalpy is equal to change in internal energyA. `2H_(2) O_(2)(l) to 2H_(2)O(l) + O_(2)(g)`B. `C(s) + O_(2) (g) to CO_(2) (g)`C. `PCl_(5)(g) to PCl_(3)(g) + Cl_(2)(g)`D. `N_(2)(g) +3H_(2)(g) to 2NH_(3)(g)`
Answer» Correct Answer - B `Delta H = Delta U + Delta n_(g) RT` In the given options (a) `2H_(2) O_(2) (l) to 2H_(2) O (l) + O_(2) (g) Delta n_(g) = 1` `:. Delta H = Delta U + RT` (b) `C (s) + O_(2) (g) to CO_(2) (g)` `Delta n_(g) - 1 - 1 = 0` `:. Delta H = Delta U` (c ) `PCI_(5) (g) to PCI_(3)(g) + CI_(2)(g)` `Delta n_(g) = 2 - 1 = 1` `:. Delta H = Delta U + RT` (d) `N_(2) (g) + 3H_(2) (g) to 2NH_(3) (g)` `Delta n_(g) RT = 2 - 3 = - 1` `:. Delta H = Delta U - RT` Equation given in option (b) has enthalpy change equal to internal change.

Discussion

4990.	Limestone is used as a flux in the extraction ofA. ironB. aluminiumC. zincD. copper
Answer» Correct Answer - A Limestone is used as a flux in the extraction of iron because it decomposes in hot furnace to form calcium oxide and carbon dioxide. The formed calcium oxide actually acts as flux and combined with silica to form fusible calcium silicate slag.

Discussion

4991.	Which among the following sets of compounds is used as raw material for the preparation of sodium carbonate by Solvay process?A. `NaOH,HCl,CO_(2)`B. `NH_(4)Cl,H_(2)O,NaCl`C. `NaCl,NH_(3),Ca(OH)_(2)`D. `NaCL,CaCO_(3),H_(2)SO_(4)`
Answer» Correct Answer - C For the preparation of sodium carbonate by Solvay process, raw materials used are NaCl,`NH_(3)` and `Ca(OH)_(2)` (for `CO_(2)`). The process involves the following reactions. `NH_(3)+H_(2)O+CO_(2)toNH_(4)NO_(3)` `CaCO_(3)overset(Delta)toCaO+CO_(2)` `NaCl+NH_(4)HCO_(3)toNaHCO_(3)+NH_(4)Cl` `CaO+H_(2)OtoCa(OH)_(2)` `2NH_(4)Cl+Ca(OH)_(2)toCaCl_(2)+2NH_(3)+2H_(2)O` `2NaHCO_(3)overset(Delta)toNa_(2)CO_(3)+H_(2)O+CO_(2)` Most of the `NH_(3)` can be recovered in the process.

Discussion

4992.	For the conversion of oxygen to ozone in the atmosphere, nitric oxide in gaseous phase acts asA. enzyme catalystB. inhibitorC. homogeneous catalystD. heterogeneous catalyst
Answer» Correct Answer - C For the conversion of oxygen to ozone in the atmosphere, nitric oxide in gaseous phase acts as a homogeneous catalyst. This is because, both reactant and the catalyst are in the same phase (i.e. gas).

Discussion

4993.	chlorination of ethane is carried out in the presence ofA. anhydrous `AIBr_(3)`B. mercuric chloride `ultraviolet lightC. zincD. chloride
Answer» Correct Answer - c Chlorination of ethane is carried out in the presence of ultravioledt light resulting free radical reaction forming ethyl chloirde `C_(2)H_(6) overset(CI_(2))underset(hv)rarr C_(2)H_(5)CI`

Discussion

4994.	Which among the following metals is refined by electrolytic method ?A. aluminiumB. BismuthC. TinD. Lead
Answer» Correct Answer - A Metals like Na, Mg , Ca ,Al etc., are reduced by electrolytic method.

Discussion

4995.	which amoung the following metals is refined by electrolytic method?A. AlyminiumB. BismuthC. TinD. Lead
Answer» Correct Answer - A Metals like Na , K , Mg , Cl , Al etc , are reduced by electrolytic method .

Discussion

4996.	Ozone is present as a chief constituent in which region of te atmosphere ?A. TroposphereB. StratosphereC. MesosphereD. Thermosphere
Answer» Correct Answer - B Stratosphere lies between `18*50` km above sea level . In this region , at about 20-40 km , there is a part of relatively high ozone concentration called the ozone layer .

Discussion

4997.	`underset(("Black"))(X)overset(Dil.H_(2)SO_(4))tounderset(("gas"))(Y)overset(Dil.HNO_(3))to` Colloidal sulphur identify X?A. CuSB. FeSC. `As_(2)S_(3)`D. `CdS`
Answer» Correct Answer - B `underset(("Black"))(FeS)overset(Dil.H_(2)SO_(4))toH_(2)Soverset(Dil.HNO_(3))tounderset("colloidal sulphur")(S)+NO_(2)+2H_(2)O`

Discussion

4998.	What happens when hydrated ferric oxide and arsenious sulphide sols are mixed in almost equal proportions ?
Answer» [Hint : Mutual precipitation/coagulation took place.]

Discussion

4999.	A sample consisting of chocolate-brown poweder of `PbO_2` is allowed to react with excess of Kl and iodine liberated is reacted with `N_2H_4` in another container. The volume of gas liberated from this second container at STP was measured out to be 1.12 litre.Find out volume of decimolar NaOH required to dissolve `PbO_2` completely. (Assume all reactions are 100% complete). Give your answer divide by 100.
Answer» Correct Answer - 20 `PbO_2+4KItoPbI_2+I_2+2K_2O` `N_2H_2+2I_2toN_2+4HI` moles of `N_2` liberated `=11.2/22.4=5xx10^(-2)` mole mole of `PbO_2` reacted `=10^(-1)` mole `PbO_2+2H_2OtoPb(OH)_4` `pb(OH)_4+2NaOHtoNa_2[Pb(OH)_6] or Na_2PbO_2` mole of NaOH required `=10^(-1)xx2` `Vxx1/10xx10^3=2xx10^(-1) " " V=2/10^(-3)=2000` ml

Discussion

5000.	How many moles of methyl alcohol is obtained when 1 mole of hydrated ferric chloride (i.e. `FeCl_3 . 6H_2O)` is made anhydrous by reacting with 6 moles of 2,2 dimethoxypropane.
Answer» Correct Answer - 12 `FeCl_3. 6H_2O+6CH_3-underset(OCH_3)underset(\|)oversetoverset(OCH_3)(\|)C-CH_3toFeCl_3+12CH_3OH+6CH_3COCH_3`

Discussion

Explore topic-wise InterviewSolutions in .

A proton and a ionized deuterium are initially at rest and are accelerated through the same potential difference. Which of the following is false concerning the final properties of the two particles ?

A man in a balloon rising vertically with an acceleration of 5ms−2 releases a ball 2 second after the balloon is let go from the ground. The greatest height above the ground reached by the ball is :

To be effective, the ideas of inclusive nationalism had to be built into the .......... a) Constitution b) Parliament c) Supreme Court d) Legislature

In frequency modulation, amplitude of modulated wave is A. positive B. negative C. constant D. zero

Geostationary satellite has period A. twice of Earth B. same as Earth C. half of Earth D. quarter of Earth

Each digit in a binary number is known as a A. bit B. byte C. number D. digit

Phenomena in which signal transmitted in one circuit creates undesired effect in other circuit is known as A. crosstalk B. signal attenuation C. sampling D. crosslinking

Value of sampled signal is used to produce a A. binary number B. decimal number C. octal number D. all of above

Digital number 9 can be represented in binary number as A. 110 B. 1001 C. 1010 D. 1011

High quality music only needs frequencies up to A. 10 Hz B. 15 Hz C. 20 kHz D. 15 kHz

Binary system has base A. 10 B. 11 C. 1 D. 2

Unwanted signal that distorts a transmitted signal is called A. analogue B. noise C. digital D. tuning

In FM, frequency of modulated wave varies with A. amplitude B. time C. wavelength D. energy

In a detector, output circuit consists of `R = 10kOmega and C = 100 p F.` Calculate the frequency of carrier signal it can detect.A. `gt gt 1MHz`B. `0.1 kHz`C. `gt gt 1GHz`D. `10^(3) Hz`

A communication channel with additive white Gaussian nose, has a bandwidth of 4 kHz and SNR of 15. Its channel capacity is1. 1.6 kbps2. 16 kbps3. 32 kbps4. 256 kbps

The output voltage of a CE amplifier is a. Amplified b. Inverted c. 180 degrees out of phase with the input d. All of the above

The voltage across the load resistor of a CE amplifier is a. Dc and ac b. DC only c. AC only d. Neither dc nor ac

The capacitor that produces an ac ground is called a a. Bypass capacitor b. Coupling capacitor c. Dc open d. Ac open

The emitter of a CE amplifier has no ac voltage because of the a. DC voltage on it b. Bypass capacitor c. Coupling capacitor d. Load resistor

An op amp has an open base resistor. The output voltage will be a. Zero b. Slightly different from zero c. Maximum positive or negative d. An amplified sine wave

In an ac amplifier using an op amp with coupling and bypass capacitors, the output offset voltage is a. Zero b. Minimum c. Maximum d. Unchanged

What is minimum and maximum mode system configuration of 8086 ?

Camber is ______if the tilt is outwards at the topa) Minimum b) Maximum c) Positive d) Negative

Which of the following process represents a `gamma- decay`?A. `._(X)^(A)X+gamma rarr ._(Z-1)^(A)X+a+b`B. `._(Z)^(A)X+_(0)^(1)nrarr_(Z-2)^(A-3)X+c`C. `._(Z)^(A)X rarr _(Z)^(A)X + f`D. `._(Z)^(A)X+_(-1)^(0)e rarr _(Z-1)^(A)X+g`

Molality of pure gas A is `(50)/(1.2)m`. Then molar mass (in gm/mol) of gas will be:

The potential energy of electron in fourth shell of `He^(oplus)` ion is `:-`A. `-(RCh)/(4)`B. `-(RCh)/(2)`C. `(RCh)/(2)`D. `-(RCh)/(8)`

Calculate the molality of solution containing 5.3 gm of sodium carbonate in 400 gm of water.

If radius of second shell of `Li^(+2)` ion is `R` `A`, then the radius of its third shell will be `:-`A. `(9R)/(4)`B. `(4R)/(9)`C. `(3R)/(2)`D. `(2R)/(3)`

It `100 mL` of `0.6 N H_(2)SO_(4)` and `200 mL` of `0.3 N HCl` are mixed together, the normality of the resulting solution will beA. `(2N)/(5)`B. `(N)/(10)`C. `(N)/(5)`D. `(N)/(20)`

The normality of H2SO4 in the solution obtained on mixing 100 mL of 0.1 M H2SO4 with 50 mL of 0.1 M NaOH is _____×10–1 N. (Nearest Integer)

In extraction of iron, limestone is used forA. Formation of slagB. Reduction of Fe oreC. Purification of Fe formedD. Oxidation of Fe ore

Chlorination of ethane is carried out in presence ofA. anhydrous `AlBr_(3)`B. mercuric chlorideC. ultraviolet lightD. zinc chloride

Identify the equation in which change in enthalpy is equal to change in internal energyA. `2H_(2) O_(2)(l) to 2H_(2)O(l) + O_(2)(g)`B. `C(s) + O_(2) (g) to CO_(2) (g)`C. `PCl_(5)(g) to PCl_(3)(g) + Cl_(2)(g)`D. `N_(2)(g) +3H_(2)(g) to 2NH_(3)(g)`

Limestone is used as a flux in the extraction ofA. ironB. aluminiumC. zincD. copper

Which among the following sets of compounds is used as raw material for the preparation of sodium carbonate by Solvay process?A. `NaOH,HCl,CO_(2)`B. `NH_(4)Cl,H_(2)O,NaCl`C. `NaCl,NH_(3),Ca(OH)_(2)`D. `NaCL,CaCO_(3),H_(2)SO_(4)`

For the conversion of oxygen to ozone in the atmosphere, nitric oxide in gaseous phase acts asA. enzyme catalystB. inhibitorC. homogeneous catalystD. heterogeneous catalyst

chlorination of ethane is carried out in the presence ofA. anhydrous `AIBr_(3)`B. mercuric chloride `ultraviolet lightC. zincD. chloride

Which among the following metals is refined by electrolytic method ?A. aluminiumB. BismuthC. TinD. Lead

which amoung the following metals is refined by electrolytic method?A. AlyminiumB. BismuthC. TinD. Lead

Ozone is present as a chief constituent in which region of te atmosphere ?A. TroposphereB. StratosphereC. MesosphereD. Thermosphere

`underset(("Black"))(X)overset(Dil.H_(2)SO_(4))tounderset(("gas"))(Y)overset(Dil.HNO_(3))to` Colloidal sulphur identify X?A. CuSB. FeSC. `As_(2)S_(3)`D. `CdS`

What happens when hydrated ferric oxide and arsenious sulphide sols are mixed in almost equal proportions ?

How many moles of methyl alcohol is obtained when 1 mole of hydrated ferric chloride (i.e. `FeCl_3 . 6H_2O)` is made anhydrous by reacting with 6 moles of 2,2 dimethoxypropane.