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Calculate the molality of solution containing 5.3 gm of sodium carbonate in 400 gm of water. |
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Answer» Given, weight of Na2CO3 =5.3g weight of water = 400g = 0.4kg Gram molecular weight of Na2CO3 is 106g => Number of moles of Na2CO3= 5.3/106 =1/20 molality = number of moles of solute/ mass of solvent(in kg) =>molality=(1/20)/(0.4)=0.125 |
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