1.

Calculate the molality of solution containing 5.3 gm of sodium carbonate in 400 gm of water.

Answer»

Given, weight of Na2CO3 =5.3g

           weight of water = 400g = 0.4kg

Gram molecular weight of Na2CO3 is 106g

=> Number of moles of Na2CO3= 5.3/106

                                                          =1/20        

   molality = number of moles of solute/ mass of solvent(in kg)

 =>molality=(1/20)/(0.4)=0.125



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