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Molality of pure gas A is `(50)/(1.2)m`. Then molar mass (in gm/mol) of gas will be: |
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Answer» `m=(n_(A)xx1000)/(W_(A)(gm))=(W_(A))/(M.Wt._(A))xx(1000)/(W_(A))=(1000)/(M.Wt._(A))` `(50)/(12)=(1000)/(M.Wt._(A))=(24)/(3)=8` |
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