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The normality of H2SO4 in the solution obtained on mixing 100 mL of 0.1 M H2SO4 with 50 mL of 0.1 M NaOH is _____×10–1 N. (Nearest Integer) |
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Answer» No. of equivalents of H2SO4 = 100 × 0.1 × 2 = 20 No. of equivalents of NaOH = 50 × 0.1 = 5 No. of equivalents of H2SO4 left = 20 – 5 = 15 ⇒ \(150 \times x = 15\) \(x = \frac 1{100} = 0.1 N = 1 \times 10^{-1}N\) |
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