1.

The normality of H2SO4 in the solution obtained on mixing 100 mL of 0.1 M H2SO4 with 50 mL of 0.1 M NaOH is _____×10–1 N. (Nearest Integer)

Answer»

No. of equivalents of H2SO4 = 100 × 0.1 × 2 = 20

No. of equivalents of NaOH = 50 × 0.1 = 5

No. of equivalents of H2SO4 left = 20 – 5 = 15

⇒ \(150 \times x = 15\)

\(x = \frac 1{100} = 0.1 N = 1 \times 10^{-1}N\)



Discussion

No Comment Found

Related InterviewSolutions