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In a detector, output circuit consists of `R = 10kOmega and C = 100 p F.` Calculate the frequency of carrier signal it can detect.A. `gt gt 1MHz`B. `0.1 kHz`C. `gt gt 1GHz`D. `10^(3) Hz` |
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Answer» Correct Answer - A Here `R = 10 kOmega = 10^(4) Omega` `C = 100 pF = 10^(-10) F` Time constant of the circuit `tau = RC = 10^(4) xx 10^(-10) = 10^(-6) s` For demodualation, `(1)/(f_(c)) lt lt RC` or `f_(c) gt gt (1)/(RC)` or `f_(c) gt gt (1)/(10^(-6)) = 10^(6) Hz` Therefore, frequency of carrier singnal must be much greater than `1 MHz`. |
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