125876 + Interview Questions in General QA Page 588 InterviewSolution

29351.	कृश्नचंदर जी की मृत्यु ई. सन् ……………. में हुई थी।(A) 1914(B) 1998(C) 1977(D) 1923
Answer» सही विकल्प है (C) 1977

Discussion

29352.	कृश्नचंदर जी का जन्म ई. सन् ….. ….. में हुआ था।।(A) 1914(B) 1920(C) 1718(D) 1912
Answer» सही विकल्प है (A) 1914

Discussion

29353.	कृश्नचंदर जी की प्राथमिक शिक्षा . …… में हुई।(A) पुंछ(B) श्रीनगर(C) लद्दाख(D) बल्तिस्तान
Answer» सही विकल्प है (A) पुंछ

Discussion

29354.	कबीरदास के अनुसार किसकी जाति नहीं पूछनी चाहिए?
Answer» कबीरदास के अनुसार साधु (सज्जन) की जाति नहीं पूछनी चाहिए।

Discussion

29355.	कबीर के दोनों ओर कौन खड़े हैं?
Answer» कबीर के दोनों ओर गुरू और गोविंद खड़े हैं।

Discussion

29356.	रात को माली ने दबे हुए आदमी को ……………. खिलाया।(A) दाल-भात(B) पकवान(C) खिचड़ी(D) सब्जी-रोटी
Answer» सही विकल्प है (A) दाल-भात

Discussion

29357.	पल में क्या हो जाएगा?
Answer» पल में परलै (प्रलय – सर्वनाश) हो जाएगा।

Discussion

29358.	साधु से क्या पूछना चाहिए?
Answer» साधु से ज्ञान पूछना चाहिए।

Discussion

29359.	किसका मोल करना चाहिए?
Answer» तलवार का मोल करना चाहिए।

Discussion

29360.	एक दिन माटी किसे रौंदेगी?
Answer» एक दिन माटी तुझे (मनुष्य के अहंकार को) रौंदेगी।

Discussion

29361.	दोहे का भावार्थःजाति न पूछो साधु की, पूछ लीजिये ज्ञान ।मोल करो तलवार का, पड़ा रहन दो म्यान ॥ १०॥
Answer» कबीरदास कहते हैं कि संतजन (साधु) की जाति मत पूछो, यदि पूछना ही है तो उनके ज्ञान के बारे में पूछ लो। तलवार को खरीदते समय सिर्फ तलवार का ही मोल-भाव करो, उस समय . तलवार रखने के कोष को पड़ा रहने दो। उसका मूल्य नहीं किया जाता।

Discussion

29362.	निन्दक की कुटी कहाँ बनानी चाहिए?
Answer» निन्दक की कुटी घर के आँगन में बनानी चाहिए।

Discussion

29363.	दोहे का भावार्थःकाल करै सो आज कर, आज करै सो अब्ब।पल में परलै होयगा, बहुरि करैगा कब्ब ॥८॥
Answer» कबीर का कहना है कि हमें जो काम कल करना है, उसे आज ही कर लें और जो आज करना है, उसे तुरन्त अभी कर लें क्योंकि इस क्षण-भंगुर संसार का तो कुछ भी निश्चय नहीं है और क्षण भर में प्रलय होने की आशंका है। इस प्रकार प्रलय होने पर तो किसी भी कार्य को करने का अवसर ही न मिलेगा। अतः आज का काम आज ही करना अच्छा है।

Discussion

29364.	कस्तूरी मृग के द्वारा कबीर कौन सी सीख देते हैं?
Answer» कस्तूरी मृग की नाभि में सुगंध होती है लेकिन वह उसे जंगल में खोजता फिरता है। उसी तरह लोग भी ईश्वर को मन्दिर-मस्जिद में खोजते फिरते है लेकिन ईश्वर तो सबके हृदय में निवास करता है। कबीर कहते हैं हमें ईश्वर को बाहर नहीं भीतर खोजना चाहिए।

Discussion

29365.	ससंदर्भ भाव स्पष्ट कीजिए:निंदक नियरे राखिये, आँगन कुटी छबाय।बिन पानी, साबुन बिना निर्मल करै सुभाय॥
Answer» प्रसंग : प्रस्तुत दोहा हमारी पाठ्य पुस्तक ‘साहित्य वैभव’ के ‘कबीरदास के दोहे’ से लिया गया है। इसके रचयिता कबीरदास हैं। संदर्भ : यहाँ कबीर कहते हैं कि आलोचना करने वाले का हमें सदैव सम्मान करना चाहिए। स्पष्टीकरण : कबीर के अनुसार हमें अपनी निंदा करनेवाले अर्थात आलोचना करनेवाले को अपने समीप रखना चाहिए। हमें उसकी कड़वी, बुरी लगनेवाली बातों से नाराज नहीं होना चाहिए। कड़वी लगने वाली बातों में हमारी भलाई की, हमारे कल्याण का भाव निहित होता है। कबीर कहते हैं ऐसे व्यक्ति को घर में जगह देनी चाहिए। उसके पास रहने से हमको यह लाभ होगा कि वह बिना पानी-साबुन के हमारे स्वभाव को स्वच्छ बना देगा अर्थात् हम उसके द्वारा निन्दा होने के डर से कोई बुरा कार्य नहीं करेंगे। आशय यह है कि निंदको की निंदा भरी बातें सुन-सुनकर हमें आत्मसुधार करने का मौका मिलता है।

29365.

ससंदर्भ भाव स्पष्ट कीजिए:निंदक नियरे राखिये, आँगन कुटी छबाय।बिन पानी, साबुन बिना निर्मल करै सुभाय॥

Answer»

प्रसंग : प्रस्तुत दोहा हमारी पाठ्य पुस्तक ‘साहित्य वैभव’ के ‘कबीरदास के दोहे’ से लिया गया है। इसके रचयिता कबीरदास हैं।
संदर्भ : यहाँ कबीर कहते हैं कि आलोचना करने वाले का हमें सदैव सम्मान करना चाहिए।

स्पष्टीकरण : कबीर के अनुसार हमें अपनी निंदा करनेवाले अर्थात आलोचना करनेवाले को अपने समीप रखना चाहिए। हमें उसकी कड़वी, बुरी लगनेवाली बातों से नाराज नहीं होना चाहिए। कड़वी लगने वाली बातों में हमारी भलाई की, हमारे कल्याण का भाव निहित होता है। कबीर कहते हैं ऐसे व्यक्ति को घर में जगह देनी चाहिए। उसके पास रहने से हमको यह लाभ होगा कि वह बिना पानी-साबुन के हमारे स्वभाव को स्वच्छ बना देगा अर्थात् हम उसके द्वारा निन्दा होने के डर से कोई बुरा कार्य नहीं करेंगे। आशय यह है कि निंदको की निंदा भरी बातें सुन-सुनकर हमें
आत्मसुधार करने का मौका मिलता है।

Discussion

29366.	ससंदर्भ भाव स्पष्ट कीजिए:कस्तूरी कुंडलि बसै, मृग ढूँढे बन मांहि।ऐसे घटि घटि राम हैं, दुनिया देखै नांहि॥
Answer» प्रसंग : प्रस्तुत दोहा हमारी पाठ्य पुस्तक ‘साहित्य वैभव’ के ‘कबीरदास के दोहे’ से लिया गया है। इसके रचयिता कबीरदास हैं। संदर्भ : यहाँ कबीरदास जी कहते हैं कि हमें प्रत्येक प्राणी के साथ प्रेमपूर्वक व्यवहार करना चाहिए, सच्ची भक्ति के साथ जीवन को सार्थक बनाना चाहिए, क्योंकि वही सच्ची भक्ति है। स्पष्टीकरण : संत कवि कहते हैं कि मनुष्य ईश्वर को पाने के लिए इधर-उधर भटकता है, जब कि ईश्वर उसी के अन्दर या उसी के पास है। जैसे कि – कस्तूरी मृग की नाभि में ही है, पर मृग नहीं जानता और भ्रमित होकर सारे वन में उसे ढूँढ़ता फिरता है। इसी प्रकार घट-घट में राम समाया हुआ है, पर मानव उसे भ्रम के कारण देख नहीं पाता।

Discussion

29367.	मृग बन में क्या ढूँढ़ता है?
Answer» मृग बन में कस्तूरी ढूँढ़ता है।

Discussion

29368.	ससंदर्भ भाव स्पष्ट कीजिए:दुःख में सुमिरन सब करे, सुख में करै न कोय।जो सुख में सुमिरन करे, तो दुःख काहे होय॥
Answer» प्रसंग : प्रस्तुत दोहा हमारी पाठ्य पुस्तक ‘साहित्य वैभव’ के ‘कबीरदास के दोहे’ से लिया गया है। इसके रचयिता कबीरदास हैं। संदर्भ : यहाँ कबीरदास जी कहते हैं कि ईश्वर का हमेशा स्मरण करते रहना चाहिए। स्पष्टीकरण : कबीरदास के अनुसार हम दुःख-तकलीफ में ईश्वर को याद करते है परन्तु सुख में ईश्वर को भूल जाते है। मनुष्य केवल अपने स्वार्थ के लिए ईश्वर को याद करता है। कबीर का मत है कि जिस दिन मनुष्य सुख में ईश्वर का ध्यान करेगा उस दिन से उसे दुःख का सामना नहीं करना पड़ेगा। ईश्वर के स्मरण से मिलने वाली शक्ति द्वारा उसका दुःख सुख में परिवर्तित हो जायेगा।

Discussion

29369.	Assertion (A) : Taylor insists that each job performed in the organisation should be based on intuition and not on scientific enquiry. Reason (R) Taylor insists that standard time for a job should be set up scientifically by performing time study in the organisation and then the day’s target should be fixed.(a) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation ofAssertion (A).(b) Both Assertion (A) and Reason (R) are true but Reason (R) is not correct explanation ofAssertion (A)(c) Assertion (A) is true but reason (R) is false.(d) Assertion (A) is false but reason (R) is true
Answer» Correct option is (d) Assertion (A) is false but reason (R) is true

Discussion

29370.	Upvedas are (a) 3 (b) 4 (c) 5 (d) 6
Answer» Correct Answer is : (b) 4

Discussion

29371.	While purchasing a bottle of medicine and a packet of biscuits, which symbol or instruction would you look for? Why?
Answer» We would look for mark of ISI on medicines and Agmark on biscuit packet. These marks assure that the quality of the product is checked, verified and certified.

29371.

While purchasing a bottle of medicine and a packet of biscuits, which symbol or instruction would you look for? Why?

Answer»

We would look for mark of ISI on medicines and Agmark on biscuit packet.

These marks assure that the quality of the product is checked, verified and certified.

Discussion

29372.	Ramana bought a cycle for ₹ 1200 and sold it to his friend Rehman for ₹ 900, then what is Ramanas profit or loss percentage?
Answer» Here Ramana’s Cost price = ₹ 1200 Selling price = ₹ 900 S.P < C.P, then Ramana got loss Loss = C.P – S.P = 1200 – 900 = ₹ 300 Loss percentage = 300/1200 x100 = 25%

29372.

Ramana bought a cycle for ₹ 1200 and sold it to his friend Rehman for ₹ 900, then what is Ramanas profit or loss percentage?

Answer»

Here Ramana’s Cost price = ₹ 1200

Selling price = ₹ 900

S.P < C.P, then Ramana got loss

Loss = C.P – S.P = 1200 – 900 = ₹ 300

Loss percentage = 300/1200 x100 = 25%

Discussion

29373.	Ajay bought a TV for ₹ 15000 and sold it for ₹141 00. Find the loss percent?
Answer» C.P of the TV = ₹ 15,000 .P of the TV = ₹ 14100 As S.P < C.P Loss = C.P – S.P= 15,000 – 14,100 = ₹ 900 ∴ Loss percent = \(\frac {900}{15000}\)× 100 = 6%

29373.

Ajay bought a TV for ₹ 15000 and sold it for ₹141 00. Find the loss percent?

Answer»

C.P of the TV = ₹ 15,000

.P of the TV = ₹ 14100

As S.P < C.P

Loss = C.P – S.P= 15,000 – 14,100 = ₹ 900

∴ Loss percent = \(\frac {900}{15000}\)× 100 = 6%

Discussion

29374.	Find the missing number in the box [ ] in the proportion:16/36 = [ ]/63 = 36/[ ] = [ ]/117
Answer» Consider the first two ratios 16/36 = [ ]/63 Let us assume the missing number be P Then, 16/36 = P/63 By cross multiplication we get, P = (16 × 63)/36 P = 1008/36 Divide both numerator and denominator by 36. P = 28 Therefore, 16/36 = [28]/63 Now, consider the middle two ratios, 28/63 = 36/[ ] Let us assume the missing number be Q, Then, 28/63 = 36/Q By cross multiplication we get, Q = (36 × 63)/28 Q = 2268/28 Divide both numerator and denominator by 28. Q = 81 Therefore, 28/63 = 36/[81] Consider the last two ratios 36/81 = [ ]/117 Let us assume the missing number be R Then, 28/63 = R/117 By cross multiplication we get, P = (28 × 117)/63 P = 3276/63 Divide both numerator and denominator by 63. P = 52 Therefore, 36/81 = [52]/117 So, 16/36 = [28]/63 = 36/[81] = [52]/117

29374.

Find the missing number in the box [ ] in the proportion:16/36 = [ ]/63 = 36/[ ] = [ ]/117

Answer»

Consider the first two ratios 16/36 = [ ]/63

Let us assume the missing number be P

Then, 16/36 = P/63

By cross multiplication we get,

P = (16 × 63)/36

P = 1008/36

Divide both numerator and denominator by 36.

P = 28

Therefore, 16/36 = [28]/63

Now, consider the middle two ratios, 28/63 = 36/[ ]

Let us assume the missing number be Q,

Then, 28/63 = 36/Q

By cross multiplication we get,

Q = (36 × 63)/28

Q = 2268/28

Divide both numerator and denominator by 28.

Q = 81

Therefore, 28/63 = 36/[81]

Consider the last two ratios 36/81 = [ ]/117

Let us assume the missing number be R

Then, 28/63 = R/117

By cross multiplication we get,

P = (28 × 117)/63

P = 3276/63

Divide both numerator and denominator by 63.

P = 52

Therefore, 36/81 = [52]/117

So, 16/36 = [28]/63 = 36/[81] = [52]/117

Discussion

29375.	Find the missing number in the box [ ] in the proportion:3/5 = [ ]/20
Answer» Let us assume the missing number be y. Then, (3/5) = (y/20) By cross multiplication we get, (3 × 20)/5 = y Y = 60/5 Divide both numerator and denominator by 5. Y = 12 Therefore, 3/5 = [12]/20

29375.

Find the missing number in the box [ ] in the proportion:3/5 = [ ]/20

Answer»

Let us assume the missing number be y.

Then, (3/5) = (y/20)

By cross multiplication we get,

(3 × 20)/5 = y

Y = 60/5

Divide both numerator and denominator by 5.

Y = 12

Therefore, 3/5 = [12]/20

Discussion

29376.	Find the missing number in the box [ ] in the proportion: [ ]/18 = 2/9
Answer» Let us assume the missing number be y. Then, y/18 = 2/9 By cross multiplication we get, Y = (2 × 18)/9 Y = 36/9 Divide both numerator and denominator by 9. Y = 4 Therefore, [4]/18 = 2/9

29376.

Find the missing number in the box [ ] in the proportion: [ ]/18 = 2/9

Answer»

Let us assume the missing number be y.

Then, y/18 = 2/9

By cross multiplication we get,

Y = (2 × 18)/9

Y = 36/9

Divide both numerator and denominator by 9.

Y = 4

Therefore, [4]/18 = 2/9

Discussion

29377.	Find the missing number in the box [ ] in the proportion:8/[ ] = 3.2/4
Answer» Let us assume the missing number be y. Then, 8/y = 3.2/4 By cross multiplication we get, Y = (8 × 4)/3.2 y = 32/3.2 y = 320/32 Divide both numerator and denominator by 32. y = 10 Therefore, 8/[10] = 3.2/4

29377.

Find the missing number in the box [ ] in the proportion:8/[ ] = 3.2/4

Answer»

Let us assume the missing number be y.

Then, 8/y = 3.2/4

By cross multiplication we get,

Y = (8 × 4)/3.2

y = 32/3.2

y = 320/32

Divide both numerator and denominator by 32.

y = 10

Therefore, 8/[10] = 3.2/4

Discussion

29378.	One item was bought for ₹ 400 and sold it for ₹ 336 then the loss percentage is ………….. A) 13% B) 12%C) 15% D) 16%
Answer» Correct option is (D) 16% Loss = Rs (336 - 400) = Rs 64 Loss percentage \(=\frac{Loss}{\text{Cost Price}}\times100\%\) \(=\frac{64}{400}\times100\%\) \(=\frac{64}4\%=16\%\) Correct option is D) 16%

29378.

One item was bought for ₹ 400 and sold it for ₹ 336 then the loss percentage is ………….. A) 13% B) 12%C) 15% D) 16%

Answer»

Correct option is (D) 16%

Loss = Rs (336 - 400) = Rs 64

Loss percentage \(=\frac{Loss}{\text{Cost Price}}\times100\%\)

\(=\frac{64}{400}\times100\%\)

\(=\frac{64}4\%=16\%\)

Correct option is D) 16%

Discussion

29379.	P is the principle, R% is rate and time period is T, Simple Interest S and Compound Interest is C then observe the following cases. (i) C > S (ii) C = S (iii) C < S A) Only (i) is true B) Either (i) or (ii) is true C) Either (ii) or (iii) is true D) Only (ii) is true
Answer» A) Only (i) is true

Discussion

29380.	Divide 96 chocolates between Raju and Ravi in the ratio 5 : 7
Answer» Given ratio = 5 : 7 Sum of the terms of the ratio = 5 + 7 = 12 Total chocolates = 96 ∴ Raju's share 5/12 x 96 = 40 Ravi is share 7/12 x 96 = 56

29380.

Divide 96 chocolates between Raju and Ravi in the ratio 5 : 7

Answer»

Given ratio = 5 : 7

Sum of the terms of the ratio = 5 + 7 = 12

Total chocolates = 96

∴ Raju's share 5/12 x 96 = 40

Ravi is share 7/12 x 96 = 56

Discussion

29381.	Find the missing number in the blank following proportion: ____ : 8 :: 12 : 32
Answer» 12:32= 12/32= 3x4/8x4= 3/8 3:8 We have, : 8 = 3 : 8 (Given) So, the missing number in is 3.

Discussion

29382.	20 tons of iron costs Rs 600000. Find the cost of 560kg of iron.
Answer» 1 ton = 1000kg Therefore, 20 tons = 20000kg Now, cost of 20000kg iron = Rs 600000 Therefore, cost of 1kg iron = Rs 600000/20000 = Rs 30 Therefore, cost of 560kg iron = Rs 30 × 560 = Rs 16800

29382.

20 tons of iron costs Rs 600000. Find the cost of 560kg of iron.

Answer»

1 ton = 1000kg

Therefore, 20 tons = 20000kg

Now, cost of 20000kg iron = Rs 600000

Therefore, cost of 1kg iron = Rs 600000/20000 = Rs 30

Therefore, cost of 560kg iron = Rs 30 × 560 = Rs 16800

Discussion

29383.	The MP of an item is ₹ 80 and it is sold for Rs 76 then the discount percentage is ……………………. A) 6% B) 5% C) 15% D) 20%
Answer» Correct option is B) 5% Correct option is (B) 5% Discount = MP - Selling price = Rs (80 - 76) = Rs 4 Discount percentage \(=\frac{Discount}{MP}\times100\%\) \(=\frac4{80}\times100\%\) \(=\frac{100}{20}\%=5\%\)

29383.

The MP of an item is ₹ 80 and it is sold for Rs 76 then the discount percentage is ……………………. A) 6% B) 5% C) 15% D) 20%

Answer»

Correct option is B) 5%

Correct option is (B) 5%

Discount = MP - Selling price

= Rs (80 - 76)

= Rs 4

Discount percentage \(=\frac{Discount}{MP}\times100\%\)

\(=\frac4{80}\times100\%\)

\(=\frac{100}{20}\%=5\%\)

Discussion

29384.	Income of Rahim is Rs 12000 per month and that of Ami is Rs 191520 per annum. If the monthly expenditure of each of them is Rs 9960 per month find the ratio of their savings.
Answer» Savings of Rahim per month = Rs (12000 – 9960) = Rs 2040 Monthly income of Ami = Rs 191520/12 = Rs 15960 Savings of Ami per month = Rs (15960 – 9960) = Rs 6000 Therefore, ratio of savings of Rahim and Ami = 2040 : 6000 = 17:50

Discussion

29385.	Rahim made 48 runs in 8 overs and Kabir made. 54 runs in 6 overs. Who made more runs per over?
Answer» Rahim made in 8 overs = 48 Runs or Rahim made in 1 over = (48/8) = 6 Runs Similarly, Kabir made in 6 overs = 54 Runs or Kabir made in 1 over = (54/6) = 9 Runs Thus, Kabir mad more runs per over.

29385.

Rahim made 48 runs in 8 overs and Kabir made. 54 runs in 6 overs. Who made more runs per over?

Answer»

Rahim made in 8 overs = 48 Runs

or Rahim made in 1 over = (48/8) = 6 Runs

Similarly, Kabir made in 6 overs = 54 Runs

or Kabir made in 1 over = (54/6) = 9 Runs

Thus, Kabir mad more runs per over.

Discussion

29386.	After allowing a discount of 20% the cost of a shirt is ₹ 1,120 then the MP is ………………A) ₹ 1400 B) ₹ 1410 C) ₹ 2310 D) ₹ 1443
Answer» Correct option is A) ₹ 1400 Correct option is (A) ₹ 1400 Let the marked price is Rs x. Discount = 20% of x \(=Rs\frac{20}{100}\times x=Rs\frac x5\) \(\therefore\) The selling price of the shirt = MP - discount \(=Rs(x-\frac x5)=Rs\frac{4x}5\) But the selling price of the shirt = Rs 1120 \(\therefore\) \(\frac{4x}5\) = 1120 \(\Rightarrow\) \(x=\frac{5\times1120}4=5\times280\) = 1400 \(\therefore\) MP = Rs x = Rs 1400

29386.

After allowing a discount of 20% the cost of a shirt is ₹ 1,120 then the MP is ………………A) ₹ 1400 B) ₹ 1410 C) ₹ 2310 D) ₹ 1443

Answer»

Correct option is A) ₹ 1400

Correct option is (A) ₹ 1400

Let the marked price is Rs x.

Discount = 20% of x \(=Rs\frac{20}{100}\times x=Rs\frac x5\)

\(\therefore\) The selling price of the shirt = MP - discount

\(=Rs(x-\frac x5)=Rs\frac{4x}5\)

But the selling price of the shirt = Rs 1120

\(\therefore\) \(\frac{4x}5\) = 1120

\(\Rightarrow\) \(x=\frac{5\times1120}4=5\times280\) = 1400

\(\therefore\) MP = Rs x = Rs 1400

Discussion

29387.	Sudha has ₹ 5. Money with Radha is 3 times the money with Sudha. How much money does Radha have? (i) What is the ratio of Radha’s money and Sudha’s money? (ii) What is the ratio of Sudha’s money and Radha’s money?
Answer» Money with Sudha = 5 ∴ Money with Radha = 3 times Sudha = 3 × ₹5 = ₹ 15 i) Radha : Sudha 15 : 5 15/5 = 3/1 = 3:1 ii) Sudha : Radha = ₹ 5 : ₹ 15 = 5 : 15 = 5/15 = 1 : 3

29387.

Sudha has ₹ 5. Money with Radha is 3 times the money with Sudha. How much money does Radha have? (i) What is the ratio of Radha’s money and Sudha’s money? (ii) What is the ratio of Sudha’s money and Radha’s money?

Answer»

Money with Sudha = 5

∴ Money with Radha = 3 times

Sudha = 3 × ₹5 = ₹ 15

i) Radha : Sudha 15 : 5

15/5 = 3/1

= 3:1

ii) Sudha : Radha = ₹ 5 : ₹ 15

= 5 : 15

= 5/15

= 1 : 3

Discussion

29388.	The cost of a scooter is ₹ 42,000 and the depreciation value for every year is 8% then the value of scooter after 1 year is ……………….A) ₹ 18,600 B) ₹ 38,640 C) ₹ 39,469 D) ₹ 18,460
Answer» Correct option is B) ₹ 38,640 Correct option is (B) ₹ 38,640 Value of scooter after 1 year = Rs (42000 - 8% of 42000) = Rs (42000 - \(\frac{8\times42000}{100})\) = Rs (42000 - 3360) = Rs 38640

29388.

The cost of a scooter is ₹ 42,000 and the depreciation value for every year is 8% then the value of scooter after 1 year is ……………….A) ₹ 18,600 B) ₹ 38,640 C) ₹ 39,469 D) ₹ 18,460

Answer»

Correct option is B) ₹ 38,640

Correct option is (B) ₹ 38,640

Value of scooter after 1 year = Rs (42000 - 8% of 42000)

= Rs (42000 - \(\frac{8\times42000}{100})\)

= Rs (42000 - 3360)

= Rs 38640

Discussion

29389.	The length and breadth of a steel tape are 10m and 2.4cm, respectively. The ratio of the length to the breadth is (A) 5 : 1.2 (B) 25: 6 (C) 625: 6 (D) 1250: 3
Answer» The correct answer is (D) 1250: 3 ( Hint: 10m = 10 × 100cm)

Discussion

29390.	Income of Rahim is Rs 12000 per month and that of Ami is Rs 191520 per annum. If the monthly expenditure of each of them is Rs 9960 per month find the ratio of their savings
Answer» Savings of Rahim per month = Rs (12000 – 9960) = Rs 2040 Monthly income of Ami = Rs 191520/12 = Rs 15960 Savings of Ami per month = Rs (15960 – 9960) = Rs 6000 Therefore, ratio of savings of Rahim and Ami = 2040 : 6000 = 17:50

29390.

Income of Rahim is Rs 12000 per month and that of Ami is Rs 191520 per annum. If the monthly expenditure of each of them is Rs 9960 per month find the ratio of their savings

Answer»

Savings of Rahim per month = Rs (12000 – 9960) = Rs 2040

Monthly income of Ami = Rs 191520/12 = Rs 15960

Savings of Ami per month = Rs (15960 – 9960) = Rs 6000

Therefore, ratio of savings of Rahim and Ami = 2040 : 6000 = 17:50

Discussion

29391.	What is the ratio of ₹ 100 and ₹ 10? Express your answer in the simplest form.
Answer» Ratio of ₹ 100 and ₹ 10 = 100 : 10 = 100/10 = 10/1 = 10 :1 Simplest form = 10 : 1.

29391.

What is the ratio of ₹ 100 and ₹ 10? Express your answer in the simplest form.

Answer»

Ratio of ₹ 100 and ₹ 10 = 100 : 10 =

100/10 = 10/1 = 10 :1

Simplest form = 10 : 1.

Discussion

29392.	Navya bought a scooter for ₹ 36,450 and paid a tax of 9% then how much amount she paid in total ? A) ₹ 19,370 B) ₹ 39,170.5 C) ₹ 39,0470D) ₹ 39,730.5
Answer» Correct option is D) ₹ 39,730.5 Correct option is (D) ₹ 39,730.5 Tax = 9% of Rs 36450 = \(Rs(\frac9{100}\times36450)\) = Rs 3280.5 Total paying price after tax = cost price + tax = Rs (36450 + 3280.5) = Rs 39730.5 Thus, Navya paid Rs 39730.5 in total.

29392.

Navya bought a scooter for ₹ 36,450 and paid a tax of 9% then how much amount she paid in total ? A) ₹ 19,370 B) ₹ 39,170.5 C) ₹ 39,0470D) ₹ 39,730.5

Answer»

Correct option is D) ₹ 39,730.5

Correct option is (D) ₹ 39,730.5

Tax = 9% of Rs 36450

= \(Rs(\frac9{100}\times36450)\) = Rs 3280.5

Total paying price after tax = cost price + tax

= Rs (36450 + 3280.5)

= Rs 39730.5

Thus, Navya paid Rs 39730.5 in total.

Discussion

29393.	The length and breadth of a steel tape are 10m and 2.4cm, respectively. The ratio of the length to the breadth is (A) 5 : 1.2 (B) 25: 6 (C) 625: 6 (D) 1250: 3
Answer» Correct answer is (D) 1250 : 3. 10 m = 10 × 100 cm

29393.

The length and breadth of a steel tape are 10m and 2.4cm, respectively. The ratio of the length to the breadth is (A) 5 : 1.2 (B) 25: 6 (C) 625: 6 (D) 1250: 3

Answer»

Correct answer is (D) 1250 : 3.

10 m = 10 × 100 cm

Discussion

29394.	Fill in the blanks: If two ratios are ______, then they are in proportion.
Answer» Equal/same. If two ratios are Equal/same then they are in proportion.

29394.

Fill in the blanks: If two ratios are ______, then they are in proportion.

Answer»

Equal/same.

If two ratios are Equal/same then they are in proportion.

Discussion

29395.	State whether the given statements are true or false: (a) 12 : 18 = 28 : 56 (b) 25 persons : 130 persons = 15kg : 78kg
Answer» (a) False, Because 12:18 = 12/18 = 2/3 2:3 and 28:56 = 28/56 = 1/2 = 1:2 These are not equal. (b) True, Because 25 Persons : 130 persons = 5:26 and 15 kg : 78 kg These are equal.

Discussion

29396.	9% of ₹ 700 is …………………. A) ₹ 20 B) ₹ 36 C) ₹ 60 D) ₹ 63
Answer» Correct option is (D) ₹ 63 9% of Rs 700 \(=Rs(\frac{9\times700}{100})\) = Rs (9 \(\times\) 7) = Rs 63 Correct option is D) ₹ 63

29396.

9% of ₹ 700 is …………………. A) ₹ 20 B) ₹ 36 C) ₹ 60 D) ₹ 63

Answer»

Correct option is (D) ₹ 63

9% of Rs 700 \(=Rs(\frac{9\times700}{100})\)

= Rs (9 \(\times\) 7)

= Rs 63

Correct option is D) ₹ 63

Discussion

29397.	The ratio of Rs 8 to 80 paise is (A) 1 : 10 (B) 10 : 1 (C) 1: 1 (D) 100 : 1
Answer» Correct answer is (B) 10 : 1 1 Rupee = 100 paise

29397.

The ratio of Rs 8 to 80 paise is (A) 1 : 10 (B) 10 : 1 (C) 1: 1 (D) 100 : 1

Answer»

Correct answer is (B) 10 : 1

1 Rupee = 100 paise

Discussion

29398.	State whether the given statements are true or false:(a) 12 : 18 = 28 : 56 (b) 25 persons : 130 persons = 15 kg : 78 kg
Answer» (a) False, Because 12:18 = 12/18 = 2/3 = 2:4 and 28:56 = 28/56 = 1/2 = 1:2 These are not equal. (b) True, Because 25 persons : 130 persons = 5: 26 and 15 kg : 78 kg = 5: 26 These are equal.

29398.

State whether the given statements are true or false:(a) 12 : 18 = 28 : 56 (b) 25 persons : 130 persons = 15 kg : 78 kg

Answer»

(a) False, Because

12:18 = 12/18 = 2/3 = 2:4

and 28:56 = 28/56 = 1/2 = 1:2

These are not equal.

(b) True, Because

25 persons : 130 persons = 5: 26

and 15 kg : 78 kg = 5: 26

These are equal.

Discussion

29399.	From the following pairs of numbers, find the reduced form of ratio of first number to second number.i. 72,60 ii. 38,57iii. 52,78
Answer» i. 72, 60 Ratio =\(\frac{72}{60}\) =\(\frac{12\times6}{12\times5}\) = \(\frac{6}{5}\) = 6 : 5 ii. 38, 57 Ratio =\(\frac{38}{57}\) =\(\frac{19\times2}{19\times3}\) = \(\frac{2}{3}\) = 2 : 3 iii. 52, 78 Ratio =\(\frac{52}{78}\) =\(\frac{26\times2}{26\times3}\) = \(\frac{2}{3}\) = 2 : 3

29399.

From the following pairs of numbers, find the reduced form of ratio of first number to second number.i. 72,60 ii. 38,57iii. 52,78

Answer»

i. 72, 60

Ratio =\(\frac{72}{60}\) =\(\frac{12\times6}{12\times5}\) = \(\frac{6}{5}\) = 6 : 5

ii. 38, 57

Ratio =\(\frac{38}{57}\) =\(\frac{19\times2}{19\times3}\) = \(\frac{2}{3}\) = 2 : 3

iii. 52, 78

Ratio =\(\frac{52}{78}\) =\(\frac{26\times2}{26\times3}\) = \(\frac{2}{3}\) = 2 : 3

Discussion

29400.	A Sum Of Rs.312 Is To Be Distributed Among 100 Boys And Girls Such That If Each Boy Gets Rs.3.60 And Each Girl Gets Rs.2.40 Then Find How Many Number Of Boys In The Class?
Answer» Let there be X boys in the class and Y girls in the girls X+Y=100 3.6X+2.4Y=312 By solving 1 & 2 we get X=60 and Y=40 The number of boys present in the class=60

29400.

A Sum Of Rs.312 Is To Be Distributed Among 100 Boys And Girls Such That If Each Boy Gets Rs.3.60 And Each Girl Gets Rs.2.40 Then Find How Many Number Of Boys In The Class?

Answer»

Let there be X boys in the class and Y girls in the girls

X+Y=100

3.6X+2.4Y=312

By solving 1 & 2 we get X=60 and Y=40

The number of boys present in the class=60

Discussion

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Find the missing number in the box [ ] in the proportion:16/36 = [ ]/63 = 36/[ ] = [ ]/117

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Divide 96 chocolates between Raju and Ravi in the ratio 5 : 7

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20 tons of iron costs Rs 600000. Find the cost of 560kg of iron.

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Income of Rahim is Rs 12000 per month and that of Ami is Rs 191520 per annum. If the monthly expenditure of each of them is Rs 9960 per month find the ratio of their savings.

Rahim made 48 runs in 8 overs and Kabir made. 54 runs in 6 overs. Who made more runs per over?

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Sudha has ₹ 5. Money with Radha is 3 times the money with Sudha. How much money does Radha have? (i) What is the ratio of Radha’s money and Sudha’s money? (ii) What is the ratio of Sudha’s money and Radha’s money?

The cost of a scooter is ₹ 42,000 and the depreciation value for every year is 8% then the value of scooter after 1 year is ……………….A) ₹ 18,600 B) ₹ 38,640 C) ₹ 39,469 D) ₹ 18,460

The length and breadth of a steel tape are 10m and 2.4cm, respectively. The ratio of the length to the breadth is (A) 5 : 1.2 (B) 25: 6 (C) 625: 6 (D) 1250: 3

Income of Rahim is Rs 12000 per month and that of Ami is Rs 191520 per annum. If the monthly expenditure of each of them is Rs 9960 per month find the ratio of their savings

What is the ratio of ₹ 100 and ₹ 10? Express your answer in the simplest form.

Navya bought a scooter for ₹ 36,450 and paid a tax of 9% then how much amount she paid in total ? A) ₹ 19,370 B) ₹ 39,170.5 C) ₹ 39,0470D) ₹ 39,730.5

The length and breadth of a steel tape are 10m and 2.4cm, respectively. The ratio of the length to the breadth is (A) 5 : 1.2 (B) 25: 6 (C) 625: 6 (D) 1250: 3

Fill in the blanks: If two ratios are ______, then they are in proportion.

State whether the given statements are true or false: (a) 12 : 18 = 28 : 56 (b) 25 persons : 130 persons = 15kg : 78kg

9% of ₹ 700 is …………………. A) ₹ 20 B) ₹ 36 C) ₹ 60 D) ₹ 63

The ratio of Rs 8 to 80 paise is (A) 1 : 10 (B) 10 : 1 (C) 1: 1 (D) 100 : 1

State whether the given statements are true or false:(a) 12 : 18 = 28 : 56 (b) 25 persons : 130 persons = 15 kg : 78 kg

From the following pairs of numbers, find the reduced form of ratio of first number to second number.i. 72,60 ii. 38,57iii. 52,78

A Sum Of Rs.312 Is To Be Distributed Among 100 Boys And Girls Such That If Each Boy Gets Rs.3.60 And Each Girl Gets Rs.2.40 Then Find How Many Number Of Boys In The Class?

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