Find the missing number in the box [ ] in the proportion:16/36 = [ ]/6

1.	Find the missing number in the box [ ] in the proportion:16/36 = [ ]/63 = 36/[ ] = [ ]/117
Answer» Consider the first two ratios 16/36 = [ ]/63 Let us assume the missing number be P Then, 16/36 = P/63 By cross multiplication we get, P = (16 × 63)/36 P = 1008/36 Divide both numerator and denominator by 36. P = 28 Therefore, 16/36 = [28]/63 Now, consider the middle two ratios, 28/63 = 36/[ ] Let us assume the missing number be Q, Then, 28/63 = 36/Q By cross multiplication we get, Q = (36 × 63)/28 Q = 2268/28 Divide both numerator and denominator by 28. Q = 81 Therefore, 28/63 = 36/[81] Consider the last two ratios 36/81 = [ ]/117 Let us assume the missing number be R Then, 28/63 = R/117 By cross multiplication we get, P = (28 × 117)/63 P = 3276/63 Divide both numerator and denominator by 63. P = 52 Therefore, 36/81 = [52]/117 So, 16/36 = [28]/63 = 36/[81] = [52]/117

Find the missing number in the box [ ] in the proportion:16/36 = [ ]/63 = 36/[ ] = [ ]/117

Answer»

Consider the first two ratios 16/36 = [ ]/63

Let us assume the missing number be P

Then, 16/36 = P/63

By cross multiplication we get,

P = (16 × 63)/36

P = 1008/36

Divide both numerator and denominator by 36.

P = 28

Therefore, 16/36 = [28]/63

Now, consider the middle two ratios, 28/63 = 36/[ ]

Let us assume the missing number be Q,

Then, 28/63 = 36/Q

By cross multiplication we get,

Q = (36 × 63)/28

Q = 2268/28

Divide both numerator and denominator by 28.

Q = 81

Therefore, 28/63 = 36/[81]

Consider the last two ratios 36/81 = [ ]/117

Let us assume the missing number be R

Then, 28/63 = R/117

By cross multiplication we get,

P = (28 × 117)/63

P = 3276/63

Divide both numerator and denominator by 63.

P = 52

Therefore, 36/81 = [52]/117

So, 16/36 = [28]/63 = 36/[81] = [52]/117