Explore topic-wise InterviewSolutions in Current Affairs.

Hey !!
your answer is --

(a) Potential energy of WOUND up spring converts into kinetic energy.

(b) Chemical energy of petrol or diesel converts into mechanical energy (kinetic energy)

(c) Kinetic energy to potential energy

(d) Light energy changes into chemical energy

(e) Electrical energy changes into chemical energy

(f) Chemical energy changes into heat energy

(G) Chemical energy changes into heat and light energy

(h) Chemical energy changes into heat, light and SOUND energy


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A) CONTINUOUS SPECTRUM with ABSORPTION LINES

HERE IS THE SOLUTION;

◆According to the QUESTION;

u= -40 CM 【 Near Point 】

v = -∞

F=?

◆ Formula Used



◆ Using Lens Formula;

P= ?

f= -40 Cm



So, the power is -2.5 D.

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The SAFFRON and GREEN PORTIONS will APPEAR green

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Horse is ABLE to do that because he APPLIES his energy over pulling the CART ..... its QUITE simple.....

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Hey dear!

The ans is It DISCONNECTS the live and neutral wire..

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It is a PROPERTY of liquid by VIRTUE of which the liquid tends to have minimum SURFACE AREA...

Hey friend!!!

In usual notation,

v2 - u2 = 2as = 900 - 400 = 500

Thus, as = 250 --- (1)

At s/2 if speed is w:

W2 - u2 = 2A(s/2)

Which MEANS,

w2 = u2 + as = 400 + 250, using (1).

Or,

w = sqrt(650) = approx 25.5 m/s.

then your answer is option "b"

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A is the CORRECT ONE

A is the CORRECT ONE

Dimension of P = [ML⁻¹T⁻²] [ ∵ pressure = force/area , Force = [MLT⁻²] ]
dimension of I = [ML²T⁻²]/[L²][T] = [MT⁻³] [ ∵ ENERGY = [ML²T⁻²] ]
dimension of C = [LT⁻¹]

Now, P^x × I^y × c^Z = dimensionless
[ML⁻¹T⁻²]^x × [MT⁻³]^y × [LT⁻¹]^z = [M⁰L⁰T⁰]
[M]^(x + y) [L]^(-x + z) [T]^(-2x +3Y -z) = [M⁰L⁰T⁰]
Compare both sides,
(x + y) = 0
(-x + z) = 0
(-2x + 3y - z) = 0
After solving EQUATIONS , we get x = 0, y = 0 and z = 0
Hence, x = 0, y = 0, z = 0

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Let US take the tension between A and B be T and tension between B and C be T1.
The masses are connected to a massless string moving over a frictionless pulley.
Now, if they are allowed to move freely, then they move with common magnitude of acceleration 'a'.
Mass of A, B and C = 2kg (m)

Now,

For C,
=> ma = mg - T1

=> T1 = mg - ma. ....(1)

For B,
=> ma = mg + T1 - T. ....(2)

For A,
=> ma = T - mg

=> T = ma + mg. ....(3)

Now, from (1) and (3) we will put value of The and T1 in (2), we get

=> ma = mg + (mg - ma) - (ma + mg)

=> ma = mg + mg - ma - ma - mg

=> 3ma = mg

=> a = g/3

Now, putting the value in (1) and (3), we will get the tensions..

Tension between B and C = m(g - a)

= m(g - g/3)

= 2(2g/3)

= 4g/3. (g = 10)

= 40/3

= 13.3N

Tension between A and B = m(a + g)

= m(g/3 + g)

= 2(4g/3)

= 8g/3

= 80/3

= 26.6N

From above we get that the tension in the string connecting WEIGHTS B and C = 13.3N (Option B)

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The answer is given below :

The train travels the first 30 KM at UNIFORM speed 30 km/h

and

let, the next 90 km is travelled at x km/h.

Then, the AVERAGE speed is

= (30 + x)/2 km/h

Given that,

(30 + x)/2 = 60

=> 30 + x = 120

=> x = 120 - 30

=> x = 90

Therefore, the required speed for the last 90 km is to be 90 km/h.

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Now let US assume the small AMOUNT of a NEGATIVE charge is equal to  Q*dA/(4*pi*a^2) on a dA

SO it will make it neutral to cut the area of the MEANING charge with positive and will disappear on it.

Therefore the negative charge will be pleased to be confused and the mass in the contribution on an electric field.

F=qE

1/(4*pi*e)*q^2/r^2 = qE

E=1/(4*pi*e)*q^2/r^2

putting in values

E=1/(4*pi*e)*[Q*dA/(4*pi*a^2)]^2/a^2

U=0
v=72km/h=20m/sec
v=u+at
20=0+a×20
20a=20
a=1m/sec^2

Now
u=20m/sec
v=0
s=80m
2as=v^2 -u^2
2×a×80=-20×20
8a=-20
a=-2.5 m/sec^2

What to ANSWER
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The COMMERCIAL UNIT of energy is KILOWATT hour (KWH).

1 Kwh=1 kw×1 hour

=1000 W×3600 Seconds

=3600000 J=3.6×10^6 J

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Hello FRIEND...

The answer of u r question is...

Option.D

Thank you..☺️☺️☺️

An EARTHQUAKE is considered as non-periodic change because it can HAPPEN at any point of time. Whereas,CHANGES which occur periodically, like:Solar Eclipse,Lunar Eclipse,Sunrise,and SUNSET , etc.are considered as Periodic changes

+16Q _________________-4q______P____
                         L                                  x

Since, the positive charge is GREATER than the negative charge so The NEUTRAL point will be on the RIGHT of the negative charge as shown above

=>               16/(L+x)² = 4/(x)²
=>                 4 = {(L+x)/x}²
=>                 (2)² = ( L/x + 1) ²
=>                 L/x +1 = 2
=>                 x = L

So, The Neutral point is L UNITS right to the Negative charge

It's not MANDATORY as LONG as gravity exists you have to BURN from below in SPACE you can burn it from any where

See attachment, 
length L ,long wire is bent in the shape of semicircle of RADIUS r .
then, length of wire = circumference of semicircle 
L = πr => r = L/2π 

now, MAGNETIC dipole = magnetic dipole moment × minimum separation between TWO dipoles 

here ( in PIC ) it is clear that , minimum separation between dipoles is 2r = 2L/π 

∴ magnetic dipole = M × 2L/π = 2ML/π
hence, magnetic moment =2M/π

It is 4°C.

DENSITY is inversely proportionate to Volume.

With decreasing temperature, up to 4 DEGREE CELCIUS, the volume of a particular amount of water SHRINKS and the speed of molecular movements decreases. So, the density increases gradually.

At 4 degree celcius the density BECOMES maximum while it is in liquid state.

Depression in the beam is given by
δ = WL³/4Ybd³
Where W is weight , L is length , b is BREADTH, Y is Young's MODULUS and d is depth also δ is depression in the beam.
Here it is clear that ,
Depression in the beam is INVERSELY proportional to Young's modulus.
e.g., δ 1/Y

Hence option (C) is correct.

Please question complete kro.....

A linear APERTURE whose WIDTH is 0.02 cm is placed immediately in front of a lens of focal length 60 cm. The aperture is ILLUMINATED normally by a parallel beam of wavelength 5 x 10-5cm. The distance of the FIRST dark band of the diffraction pattern from the CENTRE of the screen is:



f= D = 60cm

for first minima

y = wavelength * D / a

y = 5 x 10-5 * 60 / 0.02 = 0.15 cm

The characteristics of both PNP and NPN transistors are similar except that the BIASING of the voltage and current directions are reversed for any one of the possible three configurations such as a common base(CB), common emitter(CE) and common COLLECTOR(CC).The voltage between the base and emitter TERMINAL VBE....

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Нєу !

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▶25F or more degrees

▶Evaporation can EXTRACT the most HEAT when the AIR is dry.

⏩⏩⏩⏩Hope it helps✌✌✌

When the temperature INCREASE, the will be more ENERGY GOING into substance, makes the molecules VIBRATE more and more. As it vibrate more, the substance's volume increase, LEADING substance to expand

The FOLLOWING are SI units
distance = metre
speed = metre/sec
velocity = metre/sec
acceleration = metre/sec²