1.

a body starts from rest and accelerates to attain a speed 72 km/h in 20 seconds then It retards to come to rest after covering a distance of 80 m. calculate the acceleration as well as the retardation of the body

Answer»

U=0
v=72km/h=20m/sec
v=u+at
20=0+a×20
20a=20
a=1m/sec^2

Now
u=20m/sec
v=0
s=80m
2as=v^2 -u^2
2×a×80=-20×20
8a=-20
a=-2.5 m/sec^2


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