1.

two point charges +16q and -4q located at x=0 and x=L respectively. the location of a point on the x axis from x=0, at which the net electric field due to these 2 charges is zero is...

Answer»

+16Q _________________-4q______P____
                         L                                  x

Since, the positive charge is GREATER than the negative charge so The NEUTRAL point will be on the RIGHT of the negative charge as shown above

=>               16/(L+x)² = 4/(x)²
=>                 4 = {(L+x)/x}²
=>                 (2)² = ( L/x + 1) ²
=>                 L/x +1 = 2
=>                 x = L

So, The Neutral point is L UNITS right to the Negative charge


Discussion

No Comment Found

Related InterviewSolutions