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a body travels 200 CM in first 2 seconds and 220 CM in next 5 second calculate the velocity at the end of the 7th second from the start |
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Answer» let initial VELOCITY = u & accleration is a then distance travelled in 4 sec = S6 using , s=ut + at2/2 S6 = 4u + a36/2 = 6u+18a distance covered in 2 sec = S2 = 2u + 4a/2 =2u+2a = 200 (given) u+a = 100 ........................1 now distance covered in 2 to 6 sec is given 220cm S6-200 = 220 6u + 18a = 420 u+3a = 70 .................2 from 1& 2 a = -15 & u=115 velocity after 7 sec = V7 V7 = u + at =115 - 15*7=10cm/sec |
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