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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Energy of a charged capacitor is U. Now it is removed from a battery and then is connected to another identical uncharged capacitor in parallel. What will be the energy of each capacitor now ?(A) 3U/2 (B) U (C) U/4 (D) U/2 |
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Answer» (C) U/4Explanation:Energy of a CHARGED capacitor = ULet the charge on capacitor be = Q. THUS, the energy Stored : Q²/2CThe flow of charge will be such that the potential DIFFERENCE and total charge (Q) across the capacitor remains same.Hence,Potential difference across the capacitor- V = Q/2CEnergy in each capacitor - 1/2C V²= 1/2C × (Q/2C)²= 1/4 × (1/2 Q²/C)= 1/4UTherefore, the energy of each capacitor will be U/4 . |
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| 2. |
A moving electron approaches another electron. What will happen to the potential energy of this system ?(A) will remain constant (B) will increase(C) will decrease (D) may increase or decrease |
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Answer» (B) will increaseExplanation:If an electron is brought CLOSER to another electron, as the distance between them decreases, the electrical potential energy will increase. Electric potential is inversely proportional to the range and the research carried out is inversely proportional to the distance square.Since, the electron is CHARGED negatively, thus when it is brought close to another electron, a repulsive force is generated between them because of the same adverse charge. Hence, an action is performed against this repulsive force to bring them NEARER and is PLACED in the form of potential electrostatic energy which also IMPROVES the system's electrostatic potential energy. |
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| 3. |
6. An athelete of mass 60 kg skips at the rate of 20 steps per minute through an average height of. 25 cm. The power developed is: |
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Answer» An athlete massskips at the RETE ofsteps PER minute through an aberage height of. The POWER devolepment isAnswer : |
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| 4. |
Find outmomentum of point 0.2 kg moving with a velocity 0.3m/s ? |
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Answer» m is product of VELOCITY and mass.It is the actual MEASURE of motion CONTAINED in an object . Denoted by pp = mv = 0.06 KG m/s |
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| 5. |
Work done by isothermale is |
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Answer» Isothermale:Thus, in an ISOTHERMAL PROCESS the internal energy of an IDEAL gas is CONSTANT. ... In the isothermal compression of a gas there is work done on the system to decrease the volume and increase the pressure. Doing work on the gas increases the internal energy and will tend to increase the temperature. |
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| 7. |
About cochlear in one or two lines |
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| 8. |
What is meant by the attractive property of a magnet ? Describe an experiment to show that the magnetic poles have maximum attractionexplain the conclusion |
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| 9. |
Three resistors of 5 home, 10 Home, 13 home are connected in parallel to a 6 volt battery find a the value of current through each resistor. B.the total current current be in the circuit . c. and the total effective resistance of the circuit . |
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Answer» ..HEY MATE..ANSWER IS IN THE ATTACHMENT..HOPE IT HELPS U..______.. |
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| 10. |
Choose the correct answer : If length of side of a square is 1.2 m, then areaof square with correct number of significant figuresis(1)1.44 m2(3) 1.5 m2(2) 1.4 m2(4) 1.2 m2 |
| Answer» 1. (1.2)^2---1.44m^2 | |
| 11. |
The x and y-coordinates of a particle in motion,as functions of time t,are given by: x=7t^2-4t+6, y=3t^3-3t^2-12t-5(x and y are in m and t is in s.) Then what are the x and y-components of the average velocity,in the interval from t= 0 s to t= 5 s?? |
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Answer» x component of AVERAGE VELOCITY = 31 m/s.y component of average velocity = 48 m/s.Explanation:Given:The x and y coordinates of the particle,The average velocity of the particle in the TIME interval from INITIAL time to final time is defined as where, are the initial and final positions of the particle at time and respectively.For the x component of average velocity,where,For the y component of average velocity,where, |
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| 12. |
Distingwish between the work done by adiabatic and work done by isothermale |
| Answer» TION:Adiabatic : There is no heat transfer. WHATEVER WORK is done on system will drive change in state properties. Temperature being a state property may change and ALSO pressure, specific volume , INTERNAL energy and other state properties as well. Isothermal : There is no change in Temperature. | |
| 13. |
A particle of mass 5 x 10⁻⁹ kg is held at some distance from very large uniformly charged plane. The surface charge density on the plane is 4 x 10⁻⁶C/m². What should be the charge on the particle so that the particle remains stationary even after releasing it ? ε₀ = 8.85 x 10⁻¹² C⁻² m², g = 9.8 ms⁻² |
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Answer» udent,◆ Answer -Q = 2.168×10^-13 C◆ Explanation -For the particle to remain STATIONARY, its gravitational force should be BALANCED by electrostatic force.Fg = Fem.g = q.Em.g = q.σ/2ε₀q = 2m.g.ε₀/σSubstitute values,q = 2 × 5×10^-9 × 9.8 × 8.85×10^-12 / 4×10^-6q = 2.168×10^-13 CTherefore, CHARGE on the particle must be 2.168×10^-13 C.Hope this helps you... |
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| 14. |
A particle having mass m and charge q is at rest. On applying a uniform electric field E on it, it starts moving. What is its kinetic energy when it travels a distance y in the direction of force ?(A) qE²y (B) qEy² (C) qEy (D) q²Ey |
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Answer» correct OPTION is the BEXPLANATION:HOPE it helps you PLEASE make it brainlist ANSWER |
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| 15. |
The surface charge density of a very large surface is —3.0 X 10⁻⁶Cm⁻². From what distance should an electron of 150 eV energy be projected towards the plane so that its velocity becomes zero on reaching the plane ? Charge of an electron = 1.6 X 10⁻¹⁹C,1 eV = 1.6 x 10⁻¹⁹J, ε₀ = 9 X 10⁻¹² SI. |
| Answer» EXPLANATION:JOSH has not coming back in my TENTH anniversary celebration for me 3 | |
| 16. |
In the hydrogen atom, an electron revolves around a proton in a circular orbit of radius 0.53 A° . Calculate the radial acceleration and the angular velocity of the electron. me = 9.1 x 10⁻³¹ kg, e = 1.6 x 10⁻¹⁹C. |
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Answer» 0.82×10`−9 NExplanation:ACCORDING to the COULOMB's law opposite charges attract and the like charges repel with the force that is proportional to the product of the chargesProton in a circular orbit of RADIUS = 0.53 A = 5.3× 10`11 (GIVEN)e = 1.6 x 10⁻¹⁹C (Given)The force used is the coulomb attraction force. Therefore, the force, will be - F =1/4πε0 ×e²/r²where e is the CHARGE of an electronThus, F = 9 × 10`9 × (1.6 x 10⁻¹⁹)²C/ (5.3× 10`11)²= 0.82×10`−9 N |
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| 17. |
Two small, identical spheres, one positively charged and another negatively charged are placed 0.5m apart attract each other with a force of 0.108N. If they are brought in contact for some time and again separated by 0.5m, they repelled each other with force of 0.036N. What were the initial charges on the spheres ? |
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Answer» tion:pankaj Kumar chai walachalli bechene WALE KA number bhutte dar goshtNancy khuddarh BHOJPURI Lanna tkuttarakude waala |
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| 18. |
Two charged particles of mass m and 2m have charges +2q and +q respectively. They are kept in a uniform electric field far away from each other and then allowed to move for some time t. Find the ratio of their kinetic energy. |
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Answer» udent,◆ Answer -E1 : E2 = 8 : 1● EXPLAINATION -Velocity of mass m after time t is -v1 = 2qε/m × tv1 = 2qεt/mVelocity of mass 2M after time t is -v1 = qε/2m × tv1 = qεt/2mKinetic energy of mass m is -E1 = 1/2 m1.v1^2E1 = 1/2 × m × (2qεt/m)^2E1 = 2(qεt)²/mKinetic energy of mass 4M is -E2 = 1/2 m2.v1^2E2 = 1/2 × 2m × (qεt/2m)^2E2 = (qεt)²/4mRatio of kinetic energies is -E1/E2 = [2(qεt)²/m] / [(qεt)²/4m]E1/E2 = 8Therefore, RATIO of kinetic energies is 8:1.Thanks dear... |
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| 19. |
Guys what is m in this formula Pls tell fast nm=p |
| Answer» TION:its WRITTEN:Rho = OHM * metre.hope this helps.Please mark this as the BRAINLIEST!!!!! | |
| 20. |
Define motion ...... |
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Answer» The CHANGE in the position of a body from ONE PLACE to ANOTHER place is for motion. |
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| 21. |
2. After touching an object how do we say the followinga. it is hot. |
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Answer» by TOUCHING the OBJECT we can feel it is HOT by GETTING burn in handhope it's helps you✌ |
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| 22. |
What is the formula of gravitation? |
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Answer» The formula is F = G*((m sub 1*m sub 2)/r^2), where F is the force of attraction between the TWO BODIES, G is the universal gravitational CONSTANT, m sub 1 is the mass of the first object, m sub 2 is the mass of the second object and r is the distance between the centers of each object. |
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| 23. |
Ing »20.) A displacement vector of magnitude 4 makes an angle 30° with the x-axis. Its rectangular components in X-y plane are12 ABA |
| Answer» TION:DANISH ZEHEN riyazfaisuhasnainadnanadilucky dancerSiddharth nigamjannat zubairavneet KAUR | |
| 24. |
A particle starts from rest and moves along a straight line with constant acceleration. The variation of velocity v with displacement S is : ( Please give full explanation) |
| Answer» TION:shhwyehecsvhahwgwhkalwidvsgshsbejsjejbjiqoqowkehdeffegshwhwjwjgryrttwuqiooakakmsnvf | |
| 25. |
Image formed by concave mirror how? |
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Answer» ON OF DIFFERENT TYPES OF IMAGES BY A CONCAVE MIRRORFORMATION OF DIFFERENT TYPES OF IMAGES BY A CONCAVE MIRRORWhen the object is placed at infinity, the two rays AB and DE running parallel to the principal AXIS get REFLECTED at point B and E respectively and intersect each other at the principal focus F on the principal axis. |
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| 26. |
What is distance... |
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Answer» The actual path TRAVELLED by a BODY in any DIRECTION is called distance.distance is a SCALAR quantity.distance never be zero. |
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| 27. |
What is displacement. |
| Answer» TION:the shortest DISTANCE between initial POSITION and FINAL position is called DISPLACEMENT | |
| 28. |
A particle moves along a circular path with'0'as centre.if radius of circular path be 10cm. Calculate the total distance and displacement. |
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Answer» Explanation:CONSIDERING distance & displacement for ONE revolution,distance=2πr=2×22/7×10=2×3.14×10=62.8Since he returns to starting point,His Displacement BECOMES 0.Hope it HELPS :D |
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| 29. |
What is uniform motion |
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Answer» If if a body travels EQUAL DISTANCE in equal INTERVAL of TIME no matter how is small this interval. |
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| 30. |
Define velocity.... |
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Answer» Velocity a body is the distance TRAVELLED by it PER UNIT TIME in GIVEN direction.velocity is a vector quantity. |
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| 31. |
A charge enclosed by the spherical Gaussian surface is 8.85 x 10⁻⁸C. What is the electric flux linked with this surface ? If the radius of sphere is doubled, what is the electric flux ? |
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Answer» udent,◆ ANSWER -Φ = 10^4 Nm^2/C◆ Explaination -# Given -Q = 8.85×10^-8 C# SOLUTION -Electric flux PASSING through Guassian SURFACE is given by -Φ = Q/εΦ = 8.85×10^-8 / 8.85×10^-12Φ = 10^4 Nm^2/CTherefore, electric flux passing through SPHERICAL surface is 10^4 Nm^2/C.Hope this helps you... |
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| 32. |
If q₁q₂ > 0, which type of the force acting between two charges ? |
| Answer» REPULSIVE force.. EXPLANATION:as we KNOW +ve charge REPEL each other so,f=q1×q2/r^2.. | |
| 33. |
The liquid drop of mass m has a charge q. What should be the magnitude of electric field E to balance this drop ?(A) mg/q (B) E/m (C) mgq (D) mq/g |
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Answer» udent,◆ ANSWER -(A) E = mg/q● Explaination -Consider a LIQUID drop of MASS m and charge q.For ELECTRIC field to balance liquid drop, gravitational force and electrostatic force should be equal.Fg = Femg = qEE = mg/qTherefore, magnitude of electric field is mg/q.Thanks for asking. HOPE this is helpful... |
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| 34. |
When two spheres having 2Q and —Q charge are placed at a certain distance, the force acting between them is F. Now they are connected by a conducting wire and again separated from each other. How much force will act between them if the separation now is the same as before ? (A) F (B) F/2 (C) F/4 (D) F/8 |
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Answer» udent,◆ Answer -(D) F/8◆ Explaination -INITIALLY, force between TWO spheres is -F = k.Q1.Q2 / r^2F = k × 2Q × -Q / r^2F = 2k.Q^2 / r^2Charge on each sphere after connecting two spheres is given by -Q' = (Q1+Q2) / 2Q' = (2Q-Q) / 2Q' = Q/2Later, force between two spheres is given by -F' = k.Q'^2 / r^2F' = k.(Q/2)^2 / r^2F' = k.Q^2 / 4r^2F' = (2k.Q^2/r^2) / 8F' = F/8Therefore, force between two charges is F/8.Thanks dear... |
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| 35. |
When a 10 μC charge is enclosed by a closed surface, the flux passing through the surface is 0. Now another -10 μC charge is placed inside the closed surface, then the flux passing through the surface is ______ (A) 2Φ (B) Φ (C) 4Φ (D) zero |
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Answer» udent,◆ Answer -(D) zero◆ EXPLANATION -Gauss's law STATES that the electric field FLUX through a CLOSED surface equals the enclosed charge divided by the PERMITIVITY of free space.Thus, electric flux is -Electric flux = charge / permittivityΦ' = (10×10^-6 - 10×10^-6) / ε0Φ' = 0 / ε0Φ' = 0 Therefore, the flux passing through the surface is zero.Hope this helps you... |
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| 36. |
There exists an electric field of 100 N/C along Z—direction. The flux passing through a square of 10 cm sides placed on XY plane inside the electric field is ______ (A) 1.0 Nm²/C (B) 2.0 Vm (C) 10 Vm (D) 4.0 Nm²/C |
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Answer» (A) 1.0 Nm²/CExplanation:ELECTRIC field = 100 N/C (Given)Side of square = 10CM (Given)Electric flux = E.SE = 100i (N/C)Side of the square, s = 10 cm = 0.1 mArea of the square, A = s² = 0.01 m²Area vector (S) will be NORMAL to the PLANE ThereforeElectric flux = 0.01 × 100k = 1Hence, the flux through the plane in x-y plane would be 1.0 Nm²/C. |
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| 37. |
Two point charges of q and 4q are kept 30 cm apart. At a distance ______ , on the straight line joining them, the intensity of electric field is zero.(A) 20 cm from 4q (B) 7.5 cm from q(C) 15 cm from 4q (D) 5 cm from q |
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Answer» udent,◆ Answer -(A) 20 cm from 4q◆ Explaination -LET intensity of ELECTRIC field be zero at distance x from charge Q. Thus the point will be 30-x away from charge 4q.For electric field intensity to be EQUAL, electric field due to two POINTS should be equal.E1 = E2k.q/x^2 = k.4q/(30-x)^2(30-x)^2 = 4x^230-x = 2x3x = 30x = 30/3x = 10 cmThus this point will be 30-10 = 20 cm from charge 4q.Hope this was helpful... |
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| 38. |
Find a vector of magnitude 18 which is perpendicular to both the vectors 4i^-j^+k^ |
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| 39. |
An object of mass 5 kg is initially at rest it is acted on by a force so that its velocity changes to 10m/s in 5s .find the force acting on it? |
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Answer» Force = mass × CHANGE in velocity / timeForce = 5 × 10/5Force = 10 newton hope it HELPS you....!mark me as BRAINLIEST....!#FOLLOW ME#JAI HINDH ❣️ADVANCE HAPPY INDEPENDENCE DAY |
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| 40. |
Calulatethe F required to change the velocity of an object of mass 6 kg from 5 meter per second to 8 meter per second in 1 second |
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Answer» The force required is 18 N Explanation: GIVEN, u = 5 m/s V = 8 m/s t = 1 SEC Mass = 6 kg Force =? We all KNOW that force = m×aAcceleration = 3 m/s2 So,, f = 6 × 3 Hence, force = 18N |
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| 41. |
- A body is dropped from a height h. If it acquiresa momentum p then the mass of the body is: |
| Answer» PLEASE CHECK your ANSWER on GOOGLE BABA | |
| 42. |
Two stones A and B are projected horizontally from the top of a building at 20m/s and 25 m/s respectively (a) a will reach ground first (b) b will reach ground first(c) both will reach ground simultaneously.(d) can not be concluded without knowing height |
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| 43. |
Hira kyo Chamakta hai? |
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Answer» tion:Why diamond shine?--Total internal reflection partially provides the brilliance and shine to the diamond. When LIGHT strikes the diamond, it gets refracted and get separated into INDIVIDUALS colors.Hope it HELPS you. |
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| 44. |
What do you mean by electric dipole?? |
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Answer» An electric DIPOLE is a separation of positive and negative charges. The SIMPLEST example of this is a pair of electric charges of equal magnitude but opposite sign, separated by some (usually small) DISTANCE. A permanent electric dipole is CALLED an electret.Explanation: |
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| 45. |
Who is inverter of cement |
| Answer» H Aspdin❕❗#HOPE IT HELPS YOU ❤♥♠♣#GO_π_FOLLOW_ME⏬⏫⏪⏩⤵⤴#ItzShwetlana... ⭐✨✌ | |
| 46. |
The distance between two point charges 4q and -q is r. A third charge Q is placed at their midpoint. The resultant force acting on -q is zero then Q = _____ (A) -q (B) q (C) -4q (D) 4q |
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Answer» c: -4qExplanation:because -4 Q and +4q charges both CANCEL each other |
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| 47. |
The linear charge density on the circumference of a circle of radius 'a' varies as λ = λ₀cosθ. The total charge on it is _____(A) zero (B) infinite (C) πaλ₀ (D) 2πa |
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Answer» Total charge will be zero. Explanation:DQ = ʎ dx Now do the DIFFERENTIATION for above equation, ƪ dq = ƪ ʎ dx Q = ʎᵒ ƪ cos Ɵ . dx [ Ɵ = Arc/radius d Ɵ = dx/R so dx = RdƟ] q = ʎᵒ 0ƪ2π cos Ɵ . dƟ = ʎᵒ R . [Sin Ɵ]2π = ʎᵒ R [ Sin 2π – Sin Ɵ] q = ʎᵒ R [ 0 – 0] So total charge, q = 0 |
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| 48. |
When an electron and a proton are both placed in an electric field _____ (A) the electric forces acting on them are equal in magnitude as well as direction.(B) only the magnitudes of forces are same(C) accelerations produced in them are same(D) magnitudes of accelerations produced in them are same. |
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Answer» b.) only the magnitudes are the same.Explanation:because their CHARGES are EQUAL but opposite in sign i.e + and -.Similarly they have equal force, but they travel in opposite directions i.e TOWARDS each other.. |
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| 49. |
In which section of the communication system, the noise signal get admixed with the information signal?choose the correct option from the given options. (A) Source of information (B) Transmitter (C) Communication channel (D) Receiver |
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Answer» (A) SOURCE of INFORMATION |
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| 50. |
A carrier Wave of 2 MHz is amplitude modulated by a modulating Wave of 2 kHz. Which of the following frequencies will be present in AM Wave?choose the correct option from the given options. (A) 2 MHz, 2 kHz (B) 2 kHz, 2.002 MHz,1.998 MHz (C) 2 MHz, 2.002 MHz,1.998 MHz (D) 2.002 MHz,1.998 MHz |
| Answer» TION:ueudhdhdbfbdhdbdnd dbdjdjdhwgdifbdisbdkd | |