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In the hydrogen atom, an electron revolves around a proton in a circular orbit of radius 0.53 A° . Calculate the radial acceleration and the angular velocity of the electron. me = 9.1 x 10⁻³¹ kg, e = 1.6 x 10⁻¹⁹C. |
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Answer» 0.82×10`−9 NExplanation:ACCORDING to the COULOMB's law opposite charges attract and the like charges repel with the force that is proportional to the product of the chargesProton in a circular orbit of RADIUS = 0.53 A = 5.3× 10`11 (GIVEN)e = 1.6 x 10⁻¹⁹C (Given)The force used is the coulomb attraction force. Therefore, the force, will be - F =1/4πε0 ×e²/r²where e is the CHARGE of an electronThus, F = 9 × 10`9 × (1.6 x 10⁻¹⁹)²C/ (5.3× 10`11)²= 0.82×10`−9 N |
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