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A charge enclosed by the spherical Gaussian surface is 8.85 x 10⁻⁸C. What is the electric flux linked with this surface ? If the radius of sphere is doubled, what is the electric flux ? |
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Answer» udent,◆ ANSWER -Φ = 10^4 Nm^2/C◆ Explaination -# Given -Q = 8.85×10^-8 C# SOLUTION -Electric flux PASSING through Guassian SURFACE is given by -Φ = Q/εΦ = 8.85×10^-8 / 8.85×10^-12Φ = 10^4 Nm^2/CTherefore, electric flux passing through SPHERICAL surface is 10^4 Nm^2/C.Hope this helps you... |
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