Saved Bookmarks
| 1. |
When two spheres having 2Q and —Q charge are placed at a certain distance, the force acting between them is F. Now they are connected by a conducting wire and again separated from each other. How much force will act between them if the separation now is the same as before ? (A) F (B) F/2 (C) F/4 (D) F/8 |
|
Answer» udent,◆ Answer -(D) F/8◆ Explaination -INITIALLY, force between TWO spheres is -F = k.Q1.Q2 / r^2F = k × 2Q × -Q / r^2F = 2k.Q^2 / r^2Charge on each sphere after connecting two spheres is given by -Q' = (Q1+Q2) / 2Q' = (2Q-Q) / 2Q' = Q/2Later, force between two spheres is given by -F' = k.Q'^2 / r^2F' = k.(Q/2)^2 / r^2F' = k.Q^2 / 4r^2F' = (2k.Q^2/r^2) / 8F' = F/8Therefore, force between two charges is F/8.Thanks dear... |
|