Saved Bookmarks
This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What is fundamental units |
|
Answer» y CELL is the fundamental unit of human BODY. Fundamental units means the BASIC structure of something. Hope it HELP you Please mark me please #SIBI |
|
| 2. |
Difference between electric motor and electric generator |
| Answer» TION:Electric motor: It is USED to convert electrical ENERGY into MECHANICAL energy.Electric generator: It is used to convert mechanical energy into electric energy.We provide petrol or DIESEL to generator for mechanic work. | |
| 3. |
N identical cells each of emf ε and internal resistance r are connected in parallel with resistor R. The current flowing through resistor R is, ______ . (A) nε/R+nr (B) nε/nR+r (C) ε/R+r (D) ε/nR+r |
| Answer» | |
| 4. |
What will be the time taken by electron to move with drift velocity from one end to the other end of copper conductor 3 metre long and carrying a current of 3 A ? [The cross-sectional area of the conductor = 2 x 10⁻⁶ m² and electron density for copper n = 8.5 X 10²⁸ m⁻³] (A) 2.72 x 10³s (B) 2.72 x 10⁴s (C) 2.72s (D) 2.72 x 10⁻⁴s |
|
Answer» udent,◆ Answer - (B)t = 2.72×10^4 s● Explaination -CURRENT flowing through conductor is given by -I = n.A.e.vv = I / n.A.ev = 3 / (8.5×10^28 × 2×10^-6 × 1.6×10^-19)v = 1.103×10^-4 m/sTime taken for e- to move with this drift velocity is -t = l / vt = 3 / 1.103×10^-4t = 2.72×10^4 sTherefore, 2.72×10^4 s will be taken for ELECTRON to move from one end to another.Hope this HELPS you... |
|
| 5. |
A uniform conductor of resistance R is cut into 20 equal pieces. Half of them are joined in series and the remaining half of them are connected in parallel. If the two combinations are joined in series, the effective resistance of all the pieces is : (A) R (B) R/2 (C) 101R/200 (D) 201R/200 |
| Answer» | |
| 6. |
You are given n identical resistors each of resistance rΩ. First they are connected in such a way that the possible minimum value of resistance is obtained. Then they are connected in a way to get maximum possible resistance. The ratio of minimum and maximum resistance obtained in these ways is _____ (A) 1/n (B) n (C) n² (D) 1/n² |
|
Answer» e connected in series to GET MAXIMUM in this case resistance would be nrand to get minimun resistance they are connected in parallel :. resistance in this case is n/r:.RATIO between MINIMUM and maximum resistance is n/r/nr = 1/r^2please MARK it as a brainlist please plz plz plz |
|
| 7. |
A cell supplies a current of 0.9 A through a 2 Ω resistor and current of 0.3 A through a 7 Ω resistor. What is the internal resistance of the cell ?(A) 0.5 Ω (B) 1.0 Ω (C) 1.2 Ω (D) 2.0 Ω |
| Answer» OPTION C CORRECT ANSWER | |
| 8. |
In a hydrogen atom, the electron is moving in a circular orbit of radius 5.3 x 10⁻¹¹ m with a constant speed of 2.2 x 10⁻⁶ ms⁻¹. The electric current formed due to the motion of electron is _______ (A) 1.12 A (B) 1.06 mA (C) 1.06 A (D) 1.12 mA |
|
Answer» udent,I would suggest a small CORRECTION. Speed of electron can't be 2.2x10⁻⁶ m/s, it should have been 2.2x10⁶ m/s.◆ Answer - (B)I = 1.06 mA● EXPLANATION -Electric current formed due to MOTION of e- is -I = Q / tI = e / (2πr/v)I = e.v / 2πrSubstitute values,I = 1.6×10^-19 × 2.2×10^6 / (2 × 3.14 × 5.3×10^-11)I = 1.058×10^-3 AI = 1.06 mATherefore, electric current formed due to the motion of electron is 1.06 mA.Thanks dear... |
|
| 9. |
(1) A capacitor of 900 pF is charged with the help of 100 V battery. Calculate the electric potential energy of this capacitor. (2) The above capacitor is disconnected from the battery and is connected to another identical uncharged capacitor. What will be the total energy of the system ? |
| Answer» | |
| 10. |
Q.1 Two projectiles projected upward from level ground, at same initial speeds have same range but different times of flight. The ratio of the productof times of flights to their range is (g = acceleration due to gravity)(a)g(b) g/2(c) 1/g(d) 2/g |
| Answer» EXPLANATION:RANGE and U same=complementary ANGLE of PROJECTION. | |
| 11. |
Gather the information about theapparatus used to measure time inolden days |
|
Answer» y days SUNDIAL was used to konw the time the machenism used was that it showed time ACCORDING to the POSITION of the sun,when the sunlight hitted the bended pole then it formed a shadow on the flat DISK which consisted of info. of time written on it.For short intervals a sand clock was used hope it helps thanks |
|
| 12. |
Please answer it I have doubt in it |
|
Answer» ................... |
|
| 13. |
What are fundamental quantities ?? |
|
Answer» Some physical QUANTITIES are more fundamental than OTHERS. In physics, there are seven fundamental physical quantities that are measured in base or physical fundamental units: LENGTH, mass, time, electric current temperature, amount of SUBSTANCE, and luminous intensity. ... These are CALLED derived units. |
|
| 14. |
76. If the velocity of a particle is given by v = (180 - 16x)1/2m/s, then its acceleration will beIJ & K CET 20041(a) Zero(b) 8 m/s2et - 8 m/s²(d) 4 m/s2 |
|
Answer» - 8m/sec^2 EXPLANATION:RETARDATION |
|
| 15. |
Mirror in the arrangement shown in figure is moving up with speed 4 cm/sec. Find the speed of final image of object o (in cm/s) formed after two refraction and one reflection.(water u = 4/3) |
| Answer» 4 CM and the other SIDE 4 | |
| 16. |
Solve this!! prblm |
|
Answer» e here's UR answerur ANSWER is 8 s..HOPE this helps youfollow me :) |
|
| 17. |
An object is moving in a straight line with velocity v(t) = t^2 -2t m/s. If it is starts from the origin then find (a) displacement of the object in t=0 to t=3 second (b) distance travelled by the object in t=0 to t=3 seconds |
|
Answer» as the velocity is 0 at 2sc you have to FIND individual distance at the time.pls NOTICE the calculation of the distance . distance can't negative.if you r getting PROBLEM to understand this you can make a number line you will DEFINITELY understand. |
|
| 18. |
How much would a70kg man weight on the moon? What will be his mass on the earth and on the moon? [ g on moon = 1.7 m s ^ -2 ] |
|
Answer» the man, m = 70kg WEIGHT of the man on the moon, W = ?From RELATION, W = mgPutting values, we GET, The weight of the man on the moon will be 199N The mass will REMAIN same (70kg ) on earth and the moon. |
|
| 19. |
Heya guysGood morning What are physical quantities ??? |
|
Answer» Hello❤A PHYSICAL QUANTITY is a PROPERTY of a MATERIAL that can be QUANTIFIED by measurement. |
|
| 20. |
What kind of wind causes reduced pressure |
| Answer» INCREASE WIND speed is, INDEED accompanied by a REDUCED air PRESSURE | |
| 21. |
bulleted of 5 kg is fired with the mass of 2kg if after firing the bullet goes at the speed of 5m/s .find recoiling velocity of a gun |
|
Answer» m before firing = MOMENTUM after firing [ DUE to CONSERVATION of Momentum ]m1u1(Gun) + m1u2(Bullet) = m2v1(Gun) + m2v2(Bullet)2×0 + 5×0 = 2×v + 5×50 = 2v + 252v = -25V = -25/2 Recoil VELOCITY = -12.5 m/s |
|
| 22. |
What happens toan image when we move the object away of the pin hole of pin hole camera |
|
Answer» Pinhole cameras USE the principle of rectilinear propagation of light. When you place an object in front of the pinhole camera, a clear image is formed on the screen. The image formed on the pinhole camera is inverted. Since the aperture of the pinhole camera is small (a DIAMETER close to 5mm) only ONE ray from each point on the object passes through the pinhole and moves on to the screen. Thus there is one-to-one correspondence between the points on the object and the points on the screen. If the distance between the pinhole and screen is reduced, the size of the image will decrease and the image will become bright since the light spreads over a small area. If the distance between the pinhole and screen is INCREASED, the image size will increase and the image however will get less bright since the light spreads over a large area.Hope it helps youMark it as BRAINLIEST |
|
| 23. |
V=at+b/t+c+v0 is valid dimensional formula or not |
|
Answer» noExplanation:v=ut+1/2at^2 is the FORMULA of SECOND EQUATION of MOTION |
|
| 24. |
In two dimensional motion, the position vector of a moving particle changes as :x(t) = 10 + 51 + 71and y(t) = 12 - 4t + 3t.Where, x and y are in metre and t is in second.Calculate the following:(1) Distance from origin at the initial state.(ü) Distance from origin 5 seconds lattor.(iii) Velocity and acceleration after 10 seconds. |
| Answer» KINDLY CHECK out question again. I THINK you WROTE X(t) wrong | |
| 25. |
Pls answer fast. My as is (3) what is the answer with proper steps |
|
Answer» the ANSWER is three BECAUSETHE x is having 3 as it's largest nopl. mark as BRAINLIEST and FOLLOW me |
|
| 26. |
READING THE EXAMINER’S MIND 0.1 How is the speed of em wave in vacuum is determined by the electric and magnetic fields?(DELHI 2017) |
| Answer» TION: The SPEED of the em-waves in a vacuum is determined by the RATIO of the peak VALUE of electric and magnetic fields. | |
| 27. |
A spherical drop of water has 3 x 10⁻¹⁰ C amount of charge residing on it. 500 V electric potential exists on its surface. Calculate the radius of this drop. If eight such drops (Having identical charge and radii) combine to form a single drop, calculate the electric potential on the surface of the new drop. k = 9 x 10⁹ SI. |
|
Answer» udent,◆ Answer -r = 5.4 mmV' = 2000 V● Explanation -Let r be the radius of the drop. Electric potential of the drop is GIVEN by -V = (1/4πε) q/rr = (1/4πε) q/Vr = 9×10^9 × 3×10^-10 / 500r = 5.4×10^-3 MWHEN 8 such drops are merged together, radius of bigger drop will be -R = r.∛nR = 5.4×10^-3 × ∛8R = 5.4×10^-3 × 2R = 1.08×10^-2 mTotal CHARGE on bigger drop will be -Q = nqQ = 8 × 3×10^-10Q = 2.4×10^-9 CNow, electric potential of bigger drop will be -V' = (1/4πε) Q/RV' = 9×10^9 × 2.4×10^-9 / 1.08×10^-2V' = 2000 VHope this helps you... |
|
| 28. |
The resultant electric field inside a dielectric placed between two plates of a capacitor is E = σf - σb /ε₀ . Hence obtain E = E₀/K, where E₀ = external electric field on the dielectric. |
| Answer» | |
| 29. |
Obtain the formula for the energy, stored in the capacitor and also for the energy density. |
| Answer» TION:ANSWER REFER in AttachmentThank you | |
| 30. |
Derive the formula for the electric potential energy of an electric dipole in a uniform electric field. |
|
Answer» tion:The potential energy is -P*E*COS(theta) where P is the dipole moment, E is the ELECTRIC field and theta is the ANGLE dipole .HOPE it helps you. |
|
| 31. |
Show that the work done by the electric field in moving a unit positive charge from one point to the other point in an electric field depends only on the positions of those two points and not on the path joining them. |
|
Answer» tion:In DETAIL explain in Attachment.NOTE : Electrostatic force is an conservative force means in ROUND trip work done is zero.It is work done is INDEPENDENT of path CHOSEN .THANK you |
|
| 32. |
Define electric potential and give the formula corresponding to it. Write its units and dimensions. |
|
Answer» Electric potential has the DIMENSION LENGTH squared mass per electric current time cubed. The SI unit of electric potential is the VOLT, which is DEFINED as a joule per coulomb. A statvolt is defined as volts where c is the magnitude of the speed of LIGHT, and is energy-equivalent to the unit square root dyneExplanation: |
|
| 33. |
State the use of Van-de-Graf generator. |
|
Answer» A van - de - Graff generator can be used to generator high amounts of potential difference to the order of about 5 mega VOLTS. Generally used for SCIENTIFIC experiments , the GENERATED charges are used to speed particles such as ions .Explanation:# Follow me # Market me as Brainliest ✌️ |
|
| 34. |
Two bodies of masses 3kg and 2kg are connected by a along string and the string is made to pass over a smooth fixed pulley Initially the bodies are held at the saem level and released from rest. The velocity of the 3kg body after one second is |
| Answer» FIND your ANSWER here | |
| 35. |
State the evidences for the existence of Earth's magnetic field |
| Answer» EARTH's magnetic field, also known as the geomagnetic field, is the magnetic field that EXTENDS from the Earth's interior out into space, where it interacts with the solar wind, a stream of charged particles EMANATING from the SUN. The magnetic field is generated by electric currents due to the motion of convection currents of molten iron in the Earth's OUTER core: these convection currents are caused by heat escaping from the core, a natural process called a geodynamo. The magnitude of the Earth's magnetic field at its surface ranges from 25 to 65 microteslas (0.25 to 0.65 gauss).[3] As an approximation, it is represented by a field of a magnetic dipole currently tilted at an angle of about 11 degrees with respect to Earth's rotational axis, as if there were a bar magnet placed at that angle at the center of the Earth. The North geomagnetic pole, currently located near Greenland in the northern hemisphere, is actually the south pole of the Earth's magnetic field, and conversely.Explanation: | |
| 36. |
A particle projected from the top of the tower at an initial velocity 40 m/s an angle of projection 30° falls at a distance of 200√3m from the foot of the tower the height of tower is : (a) 160m (b) 200m (c) 300m(d) 400m |
| Answer» OPTION B is CORRECT...... | |
| 37. |
Bulleted of 5 kg is fired with the mass of 2 kg if after firing the bullet goes at 5ge speed of 50m/s find recoiling velocity of a gun? |
| Answer» TION:not UNDERSTAND the QUESTION SORRY | |
| 38. |
If an object moves with uniform motion its acceleration is what |
| Answer» TION:it's ACCELERATION is UNIFORM acceleration | |
| 39. |
How will you recognize a magnetic field experimentally |
|
Answer» By seeing the structure of the iron fillings AROUND the magnet we can RECOGNISE the MAGNETIC field.hope it helpspls MARK as brainliest. |
|
| 40. |
V=at+b/t+c+v0 dimensions formula |
|
Answer» We have, v = at + b/(t + C)Here, c is added by t , THEREFORE, c = [T]Again at = LT–1Therefore, a = [LT–1]/T = LT–2And [b]/[T] = [LT–1]Therefore, [b] = [L] |
|
| 42. |
What is the directive property of a magnet?explain with activity |
| Answer» TION:dbhdjdksjjdbfdfrfrjjr | |
| 43. |
Help me pls pls pls |
|
Answer» .............................. |
|
| 44. |
What do u mean by loading |
|
Answer» the process in which any animal or MAN and KEEP the OBJECT on her back is LOAD the things is called loading objects |
|
| 45. |
What is meant by alternative source of energy give example |
|
Answer» tion:ALTERNATIVE SOURCE of energy MEANS the energy which are obtained through alternate WAY from the nature which will never be extinct. For example, SOLAR energy. |
|
| 46. |
Electric field is always ______ to the equipotential surface and in a direction in which the rate of decrease of potential is ______. |
| Answer» NORTH and WEST is the ANSWER | |
| 47. |
How does the energy density associated with an electric field depend on the value of electric field ? |
|
Answer» tion:For a CHARGE concentrated NEARLY at a POINT, the electric field is directly proportional to the amount of charge; it is inversely proportional to the square of the distance radially away from the centre of the SOURCE charge and depends also UPON the nature of the medium. |
|
| 48. |
For a capacitor the distance between two plates is 5x and the electric field between them is E₀, Now a dielectric slab having dielectric constant 3 and thickness x is placed between them in contact with one plate. In this condition what is the p.d. between its two plates ? (A) 13E₀x/3 (B) 15 E₀ x (C) 7 E₀ x (D) 9E₀x/2 |
| Answer» C ONE is the ANSWER of the QUESTION | |
| 49. |
The distance between electric charges Q C and 9Q C is 4 m. What is the electric potential at a point on the line joining them where the electric field is zero ?(A) 4 kQ V (B) 10 kQ V (C) 2 kQ V (D) 2.5 kQ V |
|
Answer» A)4kQ VExplanation:HOPE it HELP you MARK as BRAINLIEST ANSWER |
|
| 50. |
The capacitance of a variable capacitor joined with a battery of 100 V is changed from 2 μF to 10 μF. What is the change in the energy stored in it ?(A) 2 X 10⁻² J (B) 2.5 X 10⁻² J (C) 6.5 X 10⁻² J (D) 4 X 10⁻² J |
| Answer» DENTS,◆ Answer - (D)∆E = 4×10^-2 J◆ Explaination -# Given -V = 100 VC1 = 2 μF = 2×10^-6 FC2 = 10 μF = 10×10^-6 F# SOLUTION -CHANGE in energy stored in CAPACITOR is given by -∆E = 1/2 (C2-C1)V^2∆E = 1/2 × (10×10^-6 - 2×10^-6) × 100^2∆E = 4×10^-2 JTherefore, the change in the energy stored in capacitor is 4×10^-2 J.Thanks dear... | |