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What will be the time taken by electron to move with drift velocity from one end to the other end of copper conductor 3 metre long and carrying a current of 3 A ? [The cross-sectional area of the conductor = 2 x 10⁻⁶ m² and electron density for copper n = 8.5 X 10²⁸ m⁻³] (A) 2.72 x 10³s (B) 2.72 x 10⁴s (C) 2.72s (D) 2.72 x 10⁻⁴s |
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Answer» udent,◆ Answer - (B)t = 2.72×10^4 s● Explaination -CURRENT flowing through conductor is given by -I = n.A.e.vv = I / n.A.ev = 3 / (8.5×10^28 × 2×10^-6 × 1.6×10^-19)v = 1.103×10^-4 m/sTime taken for e- to move with this drift velocity is -t = l / vt = 3 / 1.103×10^-4t = 2.72×10^4 sTherefore, 2.72×10^4 s will be taken for ELECTRON to move from one end to another.Hope this HELPS you... |
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