1.

bulleted of 5 kg is fired with the mass of 2kg if after firing the bullet goes at the speed of 5m/s .find recoiling velocity of a gun​

Answer»

m before firing = MOMENTUM after firing [ DUE to CONSERVATION of Momentum ]m1u1(Gun) + m1u2(Bullet) = m2v1(Gun) + m2v2(Bullet)2×0 + 5×0 = 2×v + 5×50 = 2v + 252v = -25V = -25/2 Recoil VELOCITY = -12.5 m/s



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