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Two charged particles of mass m and 2m have charges +2q and +q respectively. They are kept in a uniform electric field far away from each other and then allowed to move for some time t. Find the ratio of their kinetic energy.

Answer»

udent,◆ Answer -E1 : E2 = 8 : 1● EXPLAINATION -Velocity of mass m after time t is -v1 = 2qε/m × tv1 = 2qεt/mVelocity of mass 2M after time t is -v1 = qε/2m × tv1 = qεt/2mKinetic energy of mass m is -E1 = 1/2 m1.v1^2E1 = 1/2 × m × (2qεt/m)^2E1 = 2(qεt)²/mKinetic energy of mass 4M is -E2 = 1/2 m2.v1^2E2 = 1/2 × 2m × (qεt/2m)^2E2 = (qεt)²/4mRatio of kinetic energies is -E1/E2 = [2(qεt)²/m] / [(qεt)²/4m]E1/E2 = 8Therefore, RATIO of kinetic energies is 8:1.Thanks dear...



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