This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Which approximate wavelength ranges are generally not visible to human eye?Answer the given question in brief. |
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Answer» tion:We USUALLY refer to visible light as having WAVELENGTHS of between 400 nm and 750 nm. (The RETINA of the eye actually RESPONDS to the lowest ultraviolet frequencies, but these do not normally reach the retina because they are absorbed by the cornea and lens of the eye.) |
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| 2. |
Which term was missing in one of the equations relating electric and magnetic fields?Answer the given question in brief. |
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Answer» tion:Ampère-Maxwell law Maxwell's equations and the Lorentz force law TOGETHER encompass all the LAWS of electricity and magnetism. The symmetry that Maxwell introduced into his mathematical framework may not be immediately apparent. Faraday's law describes how changing magnetic fields PRODUCE ELECTRIC fields. |
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| 3. |
The intensity of a plane electromagnetic wave with B₀ = 1.0 X 10⁻⁴ T is Wm⁻² [C = 3*10⁸ m S⁻¹ , μ₀ = 4π*10⁻⁷ NA⁻²] choose the correct option from the given options. (A) 2.38*10⁶ (B) 1.19*10⁶ (C) 6*10⁵ (D) 4.76*10⁶ |
| Answer» HT ANSWER in the GIVEN OPTION is C | |
| 4. |
Define the energy density of electromagnetic wave.Answer the given question in brief. |
| Answer» TION:I HOPE you UNDERSTAND this ANSWER | |
| 5. |
In an A.C. circuit R and L are connected in series with source of maximum 220 V and frequency 50 Hz. If L = 1 H and R = 100 Ω. Find the maximum current in inductor and phase difference between voltage and current. [Ans. 0.668 A, 72°, 20'] |
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| 6. |
Two opposite charged particles oscillate about their mean equilibrium position in free space, with a frequency of 10⁹ Hz. The wavelength of the corresponding electromagnetic wave produced is ...........,choose the correct option from the given options. (A) 0.3 m (B) 3*10¹⁷ m (C) 10⁹ m (D) 3.3 m |
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| 7. |
The value of the A.C. voltage of a generator is V=O volts at time t= O. At time t=1/100π seconds, the voltage V=2 volts. The voltage keeps on increasing upto 100 volts. After that it starts decreasing. Determine the frequency of the voltage source. [Ans: 1 Hz] |
| Answer» ANNUAL Islamic FM psalm bullhorn am HANGING ISTHMUS | |
| 8. |
The tank circuit of L-C oscillator contains a capacitor of 30 μF and an inductor of 27 mH. Find the natural angular frequency of oscillations. [ Ans. 1.111*10³ rads⁻¹] |
| Answer» FIELDWORK SLEEPS all FM of FM of DHL is TTYL if DHL is | |
| 9. |
State the possible effects of equal and opposite balanced force |
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Answer» Heya mate......FORCES that are equal in SIZE but opposite in direction are called balanced forces. Balanced forces do not cause a change in motion. When balanced forces ACT on an object at rest, the object will not move. If you push against a WALL, the wall pushes back with an equal but opposite force.Hope it HELPS..... |
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| 10. |
An inductor of 0.5 H and 200 Ω resistor are connected in series with A.C. source of 230 V and frequency 50 Hz, then calculate : (1) Maximum current in the inductor (2) Phase difference between current and voltage and time difference (time lag) [Ans. Imax=1.28 A, 38°, 8' and 2.1ms] |
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| 11. |
In an ideal transformer input A.C. voltage is 220 V. Current in secondary coil is 2.5 A If the ratio of number of turns in primary coil and secondary coil is 1 : 10, find (1) Output voltage (2) Current in primary coil (3) Input and output power. [Ans: 2200 V, 25 A, 5500 W] |
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Answer» Bdyd UDHR hrhr hdrh dhrhr |
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| 12. |
Find the necessary inductance, if 110 V, 10 W ratting bulb is to be used with 220 V A.C source having frequency 50 Hz. [ Ans. L = 6.67 H] |
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Answer» udent,◆ Answer -L = 6.674 H◆ Explaination -# Given -Pb = 10 WVb = 110 VVs = 220 Vf = 50 HZ# SOLUTION -Current flowing through bulb is -I = Pb/VbI = 10/110 I = 1/11 AVoltage across inductor would be -V = √(Vs^2 - Vb^2)V = √(220^2 - 110^2)V = 110√3Reactance of the inductor would be -XL = V/I = 2πfLL = V / (2πfI)L = 110√3 / (2 × 3.14 × 50 × 1/11)L = 6.674 HTherefore, necessary inductance is 6.674 H.Thanks DEAR... |
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| 13. |
Using P = Vrms Irms cosδ discuss the special cases for power consumed in an A.C circuit. |
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Answer» hsusvdjdhfbgvvuihji#ijH8C7G6 |
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| 14. |
Explain necessity of transformer for power transmission and distribution |
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Answer» Transformer is the foremost reason that most of the electric POWER transmission in the world today is in the form of AC instead of DC. This is because transformer can easily step down or step up voltages which is ESSENTIAL for the EFFICIENT electric power transmission. Stepping up voltages to higher voltages before transmission at the generation end greatly reduces I2R losses over long distances. And it can be easily stepped down using transformer to REQUIRED lower voltages at the consumer end. |
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| 15. |
L = 8.1 mH, C = 12.5 μF and R = 100 Ω are connected in series with A.C. source of 230V and frequency 500 Hz. Calculate voltage across the two ends of resistance. [Ans.230 V] |
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Answer» NOTHING BUT USE REASONCE OF FREQUENCY FORMULA AND U WILL GET THE GIVEN FREQUENCY IS EQUAL TO THE OBTAINED FREQUENCY SO THE CHANGE IN OSCILLATION IS ZERO HENCE THE VOLTAGE IS EQUAL TO THE GIVEN |
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| 16. |
Obtain the expression for resonance frequency and rms current at resonance in an A.C L-C—R series circuit using expression for rms current Irms. |
| Answer» DONT KNOW brothaaaaaaaaa | |
| 17. |
Derive expression P = Vrms Irms cosδ for an A.C. circuit |
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Answer» ith Explanation:Assume that the alternating voltage given by The resulting alternating CURRENT in the CIRCUIT be with a phase change of Ф, LET Ф=p and amplitude be I ;THEREFORE power P at any INSTANT is we can write as where z is impedance.z is given by ∠δ in phasor, where δ is same as phase difference between current and voltage in the circuit.The power in phasor form given by ∠δ.where |p|= is therefore,rewriting the phasor, we can write power as δ |
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| 18. |
Explain altemating current using circuit containing only resistance R and drawing graph of current and time (I —> t). |
| Answer» TION:eyaFjafggdhfhgtuifieuu | |
| 19. |
What does Q-factor give measure of? Answer the given question in brief. |
| Answer» TION:Q-factor is a comprehensive measure for the signal quality of an OPTICAL CHANNEL that TAKES into .... This has been shown to give an acceptable qualitative ANALYSIS for macro-slip. | |
| 20. |
For L-C-R A.C. circuit resonance frequency is 600 Hz and frequencies at half power points are 550 Hz and 650 Hz. What will be the Q-factor? choose the correct option from the given options. (A) 1/6 (B) 1/3 (C) 6 (D) 3 |
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Answer» c) 6Explanation:Circuit resonance frequency = w = 600Hz (Given)Frequency = w1 = 500 (Given)Frequency = w2 = 600 Hz (Given)In a L-C-R AC circuit, the HALF power band WIDTH is the DIFFERENCE between two frequencies, namely w2 and w1, that corresponds to the current I( rms, max)/ √2 or equivalently half power in the series resonance curve. The Q factor is the measure of sharpness of resonance curve DEFINED as -Q = WO/(w2-w1), where wo is the resonance frequency.Thus, Q = 600/(650–550)Q = 600/100Q = 6. |
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| 21. |
Give relation between output power and input power for an ideal transformer.Answer the given question in brief. |
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Answer» tion:If IDEAL and no LOSSES then the output POWER is equal the INPUT power. But depending on the PRIMARY to secondary turns ratio the output voltage will be directly this ratio, step up or down, and the current will be inverse to the ratio. |
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| 22. |
Which quantity enables us to know sharpness of resonance?Answer the given question in brief. |
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Answer» tion:Basically sharpness of resonance is the define as a Q FACTOR, which related to how fast energy decay in an OSCILLATING SYSTEM. sharpness of resonance are depend UPON two FACTORS, or we can say two generally factor that effect the sharpness ho resonance. |
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| 23. |
In an oscillating L-C circuit the maximum charge on the capacitor is Q. What will be the charge on the plate of the capacitor, when energy stored in magnetic field and electric field are equal? choose the correct option from the given options. (A) Q/3 (B) Q/√2 (C) Q (D) Q/2 |
| Answer» B) Q/√2Explanation:In parallel resonance L-C CIRCUIT, energy keeps moving from L and C every HALF cycle, and no current is drawn from the supply. Total energy stored in the condenser is transferred to the inducer and then returned to the condenser again, and the cycle continues. The condenser storage is in the electrical field, while the inductor stores the magnetic field energy.Therefore, for a given energy. which is stored in the capacitor if the energy on the CHARGE on the capacitor is halved it will be Q/√2. | |
| 24. |
Which value of the A.C. voltage can be measured by an A.C. voltmeter?Answer the given question in brief. |
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Answer» tion:The instrument, which is USED to measure the AC voltage ACROSS any two points of electric CIRCUIT is called AC voltmeter. If the AC voltmeter consists of rectifier, then it is said to be rectifier based AC voltmeter. The DC voltmeter MEASURES only DC VOLTAGES. |
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| 25. |
A particle is projected at an angle of elevation sin-1 (4/5) and its range on the horizontal plane is 3km.The initial velocity of projection is _______.the answer is 175 m/s.explain how? |
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Answer» tal range , R = u²sin2θ/gwhere θ is ANGLE of elevation of projectile, u is velocity of projection and g is acceleration due to gravity.here, R = 3km = 3000m , g = 9.8 m/s² θ = sin^-1(4/5) we know, sin2θ = 2sinθcosθ = 2 × sin{sin^-1(4/5)} × COS{sin^-1(4/5)}= 2 × 4/5 × cos{cos^-1(3/5)}= 2 × 4/5 × 3/5 = 24/25 so, sin2θ = 24/25then, 3000 = u²(24/25)/9.8or, 3000 × 9.8 × 25/24 = u²or, 1000 × 25/8 = u² or, 125 × 9.8 × 25 = u² or, u² = (25 × 25 × 49) or, u = 175 m/s hence, velocity of projection is 175m/s |
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| 26. |
a boy throws a ball upward with speed of 10 M per second the mass of ball equals to 400 gram calculate weight of the ball and initial momentum of the ball at highest point |
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| 27. |
21. which among the following elements whose atomic number are given below belong to the Same period? Give the reason(17,10,20,12,19,15 ) |
| Answer» EXPLANATION:the ANSWER is GIVEN below : | |
| 28. |
Velocity time graph of a body thrown vertically up is |
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Answer» Helloराधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे राधे |
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| 29. |
Give the characteristics of an induced emf in AC generator.Answer the Given question. |
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Answer» enerator is an electric GENERATOR that converts mechanical energy into electrical energy in form of alternative emf or alternating current. AC generator works on the principle of ”Electromagnetic Induction”. Parts of an AC GeneratorAn Ac generator consists of two poles i.e is the north pole and south pole of a magnet so that we can have a uniform magnetic field. There is also a COIL which is rectangular in shape that is the ARMATURE. These coils are connected to the slip rings and attached to them are carbon brushes.The slip rings are made of METAL and are insulated from each other. The brushes are carbon brushes and one end of each brush connects to the ring and other connects to the circuit. The rectangular coils rotate about an AXIS which is perpendicular to the magnetic field. There is also a shaft which rotates rapidly.Learn more about Biot-Savart Law.Working of an AC GeneratorWhen the armature rotates between the poles of the magnet upon an axis perpendicular to the magnetic field, the flux which links with the armature changes continuously. Due to this, an emf is induced in the armature. This produces an electric current through the galvanometer and the slip rings and brushes.The galvanometer swings between the positive and negative values. This indicates that there is an alternating current flowing through the galvanometer |
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| 30. |
Explain conversion of mechanical energy into the elecnical energy in case of conducting rod sliding over a U-shaped Wire Which is placed inside a magnetic field.Answer the Given question. |
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Answer» area enclosed by the ROD and u shaped WIRE changes every time due the rod's velocity.Due to that Magnetic flux changes PRODUCING induced current which INTURN is responsible for the retarding Lorentz force. The Lorentz force tries to BALANCE the force exerted for motion of rod. |
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| 31. |
Discuss the reason behind the production of induced emf in case of a conducting rod moving in the magnetic field with its velocity perpendicular to the magnetic field. |
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Answer» in MAGNETIC flux DUE to change in AREA swept by the rod because it has velocity. |
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| 32. |
A coil having 200 turns has a surface area 0.12 m². A magnetic field of strength 0.10 Wbm⁻² linked perpendicular to this area changes to 0.5 Wbrn⁻² in 0.2 s. Find the average emf induced in the coil. [Ans:48 V] |
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Answer» Average value of induced emf = 48 V.Explanation:Given:Number of turns of the coil, .Surface area of the coil, .Strength of the magnetic field initially, .Strength of the magnetic field after 0.2 s, .The magnetic flux through a surface is defined as where, = area vector of the coil which is DIRECTED along the normal to the plane of the coil and has magnitude equal to the surface area of the coil. = ANGLE between and .In the given question, the magnetic field is perpendicular to the area of the coil which means it is along the same direction as that of .THEREFORE, .The magnetic flux linked with the coil is given asAccording to the Faraday's law of electromagnetic induction, the emf induced in the coil is given by is the change in the magnetic field = Therefore, The average induced emf is given bySince, there is no TIME dependent term in the value of the induced emf, therefore,Thus, the magnitude of average emf induced in the coil is same as the magnitude of induced emf i.e., 48 V. |
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| 33. |
Give two definitions of mutual inductance and Write its unit.Answer the Given question. |
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Answer» inductance is a measure of the induction of two CIRCUITS, the RATIO of two ELECTROMOTIVE forces in a circuit to the corresponding change of current in a neighbouring circuit .the UNIT of mutual inductance is Henry. |
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| 34. |
On what factors does the mutual inductance of a system of two coils depend?Answer the Given question in brief. |
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Answer» Explanation:The term MUTUAL SUGGESTS that the magnetic flux which is shared or common between TWO current carrying coils and which in term is dependent on the medium / material between the two coils. If the mutual flux is in a medium such as air then the magnetic flux DENSITY and will be ~ \mu_0. |
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| 35. |
With the help of neat diagram derive the expression for induced emf in an AC generator.Answer the Given question. |
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Answer» nerators or alternators (as they are usually CALLED) operate on the same fundamental principles of electromagnetic induction as D.C. generators. Alternating voltage MAY be generated by ROTATING a coil in the magnetic field or by rotating a magnetic field within a stationary coil. The value of the voltage generated depends on- the number of turns in the coil. strength of the field. the SPEED at which the coil or magnetic field rotates. |
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| 36. |
A coil having N turns and resistance R Ω is connected to a galvanometer of resistance 4R Ω. This combination is moved in time I seconds from a magnetic flux Φ₁ Wb to Φ₁ Wb. What is the induced current in the circuit?Answer the Given question in brief. |
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Answer» udent,◆ ANSWER -I = -N(Φ₂-Φ₁)/5Rt◆ Explanation -Total resistance in the circuit is -R' = R + 4RR' = 4RAlso EMF induced in the coil is given by -V = -N.∆Φ/tV = -N(Φ₂-Φ₁)/tNow, induced CURRENT in the circuit will be -I = V/R'I = [-N(Φ₂-Φ₁)/t]/5RI = -N(Φ₂-Φ₁)/5RtHope this HELPS you... |
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| 37. |
Give the statement of Lenz‘s law to determine the direction of induced emf.Answer the Given question in brief. |
| Answer» EXPLANATION:Lenz's law STATES that the direction of INDUCED emf is such that it OPPOSES change in flux . | |
| 38. |
A wheel with 10 metallic spokes each 0.5 m long rotated with a speed of 120 rpm in a plane normal to the horizontal component of earth’s magnetic field Bh at a place. If Bh = 0.4 G at the place, what is the induced emf between the axle and the rim of the wheel ? (1G=10⁻⁴ T)choose the correct option from the given options. (A) 0 V (B) 0.628 mV (C) 0.628 μV (D) 62.8 μV |
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Answer» udent,◆ ANSWER -(D) 62.8 μV◆ Explanation -Potential DIFFERENCE GENERATED between rim and axis of cycle is calculated by -EMF = 1/2 B.ω.l²EMF = 1/2 × B × 2πf × l²EMF = B × πf × l²EMF = 0.4×10^-4 × 3.14 × 2 × 0.5^2EMF = 62.8×10^-6 VEMF = 62.8 μVTherefore, EMF generated between rim and axis of cycle is 62.8 μV.Thanks DEAR... |
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| 39. |
The self-inductance of two solenoids A and B having equal length are same. If the number of turns in two solenoids A and B are 100 and 200 respectively,the ratio of the radii of their cross-section will be ........,choose the correct option from the given options. (A) 2:1 (B) 1:2 (C) 1:4 (D) 4:1 |
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Answer» udent,◆ Answer - (A)R1 : R2 = 2 : 1◆ Explanation -Given that self inductance of both solenoids is same.L1 = L2μₒ.N1².A1/l = μₒ.N2².A1/lN1².πr1² = N2².πr2²r1²/r2² = N2²/N1²r1/r2 = N2/N1r1/r2 = 200/100r1/r2 = 2Therefore, ratio of radii of cross-section of solenoids is 2:1.Thanks buddy... |
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| 40. |
How to conserve energy resources? Explain with examples |
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Answer» icycle or walk for short distances.Use public transport.Use only natural LIGHT in the morning.Disposal of waste after SEGREGATION into renewable and non renewable.Reusable bottles , Pens ( avoid buying pens that DEMAND replacement of its plastic CARTRIDGE) |
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| 41. |
A semi conductor loop of diameter d is made by usin a conducting wire of resistance per unit length r which is connected with ideal battery of emf E as shown in figure thn heat dissipated per unit second by semi circular wire --- --- --- --- --- _________ ! ! !____! | ___-! E [ imagine it as a figure] |
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Answer» Most circuits have more than one COMPONENT, called a resistor that limits the flow of charge in the circuit. A measure of this limit on charge flow is called resistance. The simplest combinations of resistors are the series and parallel connections illustrated in Figure 1. The total resistance of a combination of resistors depends on both their individual values and how they are CONNECTED.In part a of the figure, resistors labeled R sub 1, R sub 2, R sub 3, and R sub 4 are connected in series along one path of a circuit. In part b of the figure, the same resistors are connected along parallel paths of a circuit.Figure 1. (a) A series connection of resistors. (b) A parallel connection of resistors.Resistors in SeriesWhen are resistors in series? Resistors are in series whenever the flow of charge, called the current, must flow through devices sequentially. For example, if current flows through a person holding a screwdriver and into the Earth, then R1 in Figure 1(a) could be the resistance of the screwdriver’s shaft, R2 the resistance of its handle, R3 the person’s body resistance, and R4 the resistance of her shoes. Figure 2 shows resistors in series connected to a voltage source. It seems reasonable that the total resistance is the sum of the individual RESISTANCES, considering that the current has to pass through each resistor in sequence. (This fact would be an ADVANTAGE to a person wishing to avoid an electrical shock, who could reduce the current by wearing high-resistance rubber-soled shoes. It could be a disadvantage if one of the resistances were a faulty high-resistance cord to an appliance that would reduce the operating current.) |
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| 43. |
the particle has velocity given by v = 20+ 0.1 t square then it has option 1 uniform acceleration option 2 uniform retardation option 3 non uniform acceleration option 4 zero acceleration |
| Answer» 1.) uniform accelerationStep by step explanations:Given the particle has velocity given by V = 20+ 0.1 TWE know that by differenciating velocity with RESPECT to TIME wew get accelerationso,dv/dt= 0.1 and here,Acceleration is not depending upon time so,it is the case of constant accelerationso,Correct option : 1.) uniform acceleration | |
| 44. |
If pulley and all strings as shown are massless then tension T, = 100 N. Calculate weight of theblock (g = 10 m/s2)60"30°(1) 50 N(3) 50/3 N(2) 100 N(4) 100,3 N |
| Answer» 50 N is the correct ANSWER HOPE it will help U | |
| 45. |
What happens to the speed of sound when medium B(carbon dioxide) is heated?Explain the reason |
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Answer» wer 1 => sound waves travel faster in solids than in liquids, and faster in liquids than in gasses. While the DENSITY of a medium also affects thespeed of sound, the elastic PROPERTIES have a greater influence on the wavespeed. The density of a medium is the second factor that affects the speed of sound.____________(^^-^^)______________Answer 2=> The temperature of the Earth depends on a BALANCE between incoming energy from the Sun and the energy that bounces back into space.Carbon DIOXIDE absorbs heat that would otherwise be lost to space. ❤❤ |
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| 46. |
Two Particle A and B starts moving with velocity 70m/s and 30m/s and acceleration - 4m/s² and 8m/s².[direction :A to B] at which two-time they meet? |
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Answer» 10 secExplanation:this question is very easy by using CONCEPT of relatives velocity. UAB =Va-Vb =70-30 =40m/sAcc.ab = Aa-Ba =4-8 =-4m/s²now v = u+atVab=uab-aab. tsince body meet FINAL RELATIVE velocity (Vab ) =00 = 40-4t 4t = 40t=10 sec |
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| 47. |
The displacement time relationship of particle is given by X =a0+a1t+a2t^2. the acceleration of particle is |
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Answer» acceleration is 4aExplanation:First we have to diffrentiate displacementX= a+at+at^2 then VELOCITY is a+4at.Another TIME diffrentiation will GIVE U acceleration that is 4a |
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| 48. |
Why ampere is fundamental unit ? |
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Answer» imately, all SI units must be TRACEABLE to Mass, Length and Time. The currentdefinition of the Ampere is:The constant current which will produce an attractive force of 2 × 10–7 newtons per metre of length between two straight, parallel CONDUCTORS of infinite length and NEGLIGIBLE CIRCULAR cross section placed one metre apart in a vacuum.As the Newton is a measure of force, and therefore given by Mass * Acceleration (second order SPEED, distance / time), the definition ultimately reduces to a form that is derived from only Mass, Length and Time. |
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| 49. |
how to find the tension of a string with considerable mass ?? give the derivation,and dont copy from google |
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Answer» To FIND TENSION force we need the weight developed in the string and here weight is the body pulling the string. TENSION T(=W) DEVELOPED IN THE STRING. DERIVATIONWhen a body is suspended by a string attached to a rigid support,the body,DUE to its weight W, pulls the string vertically downwards and the string in its stretched condition pulls the body upwards by a force which BALANCES the weight of the body. This force developed in the string is called tension(or the force of tension).MAY this will help UPls mark this as a BRAINLIST ANSWER |
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| 50. |
Oxidizing and reducing atmosphere |
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Answer» Oxidising is the CHEMICAL reaction which MEANS the IRON, oxygen and moisture content in the ATMOSPHERE will reacts ang gives a NEW product.iron+oxygen+moisture(water)=Rust |
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