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Find the necessary inductance, if 110 V, 10 W ratting bulb is to be used with 220 V A.C source having frequency 50 Hz. [ Ans. L = 6.67 H] |
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Answer» udent,◆ Answer -L = 6.674 H◆ Explaination -# Given -Pb = 10 WVb = 110 VVs = 220 Vf = 50 HZ# SOLUTION -Current flowing through bulb is -I = Pb/VbI = 10/110 I = 1/11 AVoltage across inductor would be -V = √(Vs^2 - Vb^2)V = √(220^2 - 110^2)V = 110√3Reactance of the inductor would be -XL = V/I = 2πfLL = V / (2πfI)L = 110√3 / (2 × 3.14 × 50 × 1/11)L = 6.674 HTherefore, necessary inductance is 6.674 H.Thanks DEAR... |
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