This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
An object of mass 5kg falls from a height of 5m above the ground. Find the loss of potential energy of the mass |
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Answer» loss in pottential ENERGY = 245 jouleStep by step explanations:Given,An object of mass 5kg falls from a height of 5m above the groundmass of object = 5 kgheight from which it is DROPPED = 5 mto find the loss of potential energy of the massso,loss in pottential energy = potential energy at its maximum heightpottential energy = Mghhere,M = mass of the object = 5 kgg = gravitational acceleration= 9.8 m/s²h = height of ground from the object= 5 MSO,pottential energy = 5 × 9.8 × 5= 245 joule so,loss in pottential energy = 245 joule |
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| 2. |
A ball is thrown vertically upwards from the top of a tower with a speed of 100 m/s. It strikes the pond near the base of the tower after 25 second. The height of the tower is(1) 500 m(2) 125 m(3) 625 m(4) 425 m |
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Answer» - Initial velocity = 100 ms-¹As we know that when a BODY is thrown upward then it is moving with negative acceleration due to gravity.g = -10 ms-²Here we will APPLY the third equation of motion:- v²-u²= 2gh 0²-(100)²= 2 x -(10) x h -10000 = -20H h = -10000/-20h = 500 m Hence, the height of tower = h = 500 m. |
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| 3. |
What is meant by L.C of an instrument |
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Answer» L.C means least COUNT of an apparatus/ instrument.e.g. L.C. of SCREW gauge is 0.01 mm.and L.C. of VERNIER CALIPER is 0.01 CM. |
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| 4. |
I) Joules in 1 KWHiii) Erg in 1 joule-ii) Joules in lev. -iv) Calorie in 1 joule |
| Answer» 1 JOULE =4.2 calExplanation: | |
| 5. |
Consequential Force examples with definition |
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Answer» Consequential forces are the RESULTANT FORCE or an outcome of the force which is applied to the concerned body. The best example of a consequential force is frictional force. Frictional force arises due to a body which is moving or tends to move over another body, WHEREIN both the BODIES are in contact. |
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| 6. |
Two forces whose magnitude are in ratio 3:5 gives a resultant of 35 N . If the angle of inclination is 60° , find the magnitude of each force . |
| Answer» E your a SWER is in the ATTACHMENT | |
| 7. |
Very STIU Lightning and thunder take place in skysame distance from us. Explain why lightning is seenearlier and thunder is heard later.What devices are used to locate underwater objectsand to determine depths of water beneath the ship?2.Sound pulses emitted by dolphin travel through20 °C ocean water at a rate of 1450 m/s. In 20°Cair, these pulses would travel 342.9 m/s. How canyou account for this differences in speed ?If you clap on one end of a long steel pipe you willhear two distinct sounds on the other end of theiEvrlain |
| Answer» VELOCITY is of LIGHT is HIGHER than that of light,"Ecosounder | |
| 8. |
A train is approaching a platform with a speed of 20 km/hr. A bird is sitting on a pole at the platform.When train is 2 km away from the pole brakes areapplied so that the train decelerates uniformly,-simultaneously the bird also flies towards the train witha velocity 60 km/hr. It touches the nearest point on thetrain and flies back and back again and so on. Thetotal distance travelled by the bird before train stop is(A) 30 km(B) 15 km(C) 12km(D) 10 km |
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Answer» Step 1 : Fnding the acceleration of the train when it is at the distance of 2 km from the pole.v2=u2+2asfinal VELOCITY 'v' is 0 because it is ASSUMED that the train is supposed to stop when it reaches the pole. initial velocity = 20 km/hr ...(given) s = 2 km, the distance of the train from the pole.v2=u2+2as0=400+4aa=-100km/hr2Step 2: Finding the time in which the train travelled 2kms to the pole.v=u+ato=20+(-100)tt=1/5hrStep 3: Finding the distance that the bird covers in the above period of time. distance = speed (of bird) x time (above calculated) =60*1/5 12kmmark me as a brain;iest if it helps you |
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| 9. |
State the cons of friction |
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Answer» a friction makes it difficult to move an object, such as sliding a box across the floor or walking in deep snow.2. Any DEVICE that has moving parts can WEAR out RAPIDLY because of friction. 3. Friction can create heat energy, but this could overheat and DAMAGE an object, such as a CAR. |
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| 10. |
2. A body projected vertically up crosses points A and B separated by 28 m with velocities one-third and one-fourth of the initial velocity, respectively. What is themaximum height reached by it above the ground? |
| Answer» ANSWERLET initial velocity of the body = uVelocity of the body at POINT A = 3u Velocity of the body at point B = 4u Apply v 2 −u 2 = 2aS for points A and B:( 4u ) 2 −( 3u ) 2 =2(−g)×28On SOLVING we GET: u 2 = 1152gNow apply direct formula for maximum HEIGHTH max = 2gu 2 H = 2g1152g = 576 m | |
| 11. |
Find the components along the x, y, z axes of the angular momentum l of a particle, whose position vector is r with components x, y, z and momentum is p with components px, py and pz. Show that if the particle moves only in the x-yplane the angular momentum has only a z-component. |
| Answer» PLZZ GIVE me BRAINLIEST ans and PLZZZZ FOLLOW me | |
| 12. |
What r eye detects???? |
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Answer» y MYOPIA HypermetropiaPresbyopia |
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| 13. |
Calculate pressure when a force of 5 newton is applied on an area of 5 square centimetre |
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Answer» Pressure can be DEFINED as force per unit area.Its SI Unit is PASCAL or N/m squareGiven,Force. =. 5NArea. = 5cm =5/100m=0.05mPressure = ?Pressure = Force / Area= (5/0.05)N/m= 100 N/m or= 100 Pascal = 100 PaHope it HELPS you.Pls mark me as the BRAINLIEST. |
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| 14. |
what is the value of linear velocity If r vector equals to 3i cap - 4 j cap + K cap and Omega vector equal to 5i cap - 6 J cap + 60 cap |
| Answer» PLZZ GIVE me brainliest ANS and plzzzz FOLLOW me | |
| 15. |
Why are some fiber called synthetic |
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Answer» the fibres called synthetic because it is made up of MAN Explanation:Please mark BRAINLIST it is USE to me please PLEASEPLEASE.... |
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| 16. |
Wavelength of 10ev electron |
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Answer» t is the ANSWER of |
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| 17. |
The oxygen molecule has a mass of 5.30 × 10–26 kg and a moment of inertia of 1.94×10–46 kg m2 about an axis through its centre perpendicular to the lines joining the two atoms. Suppose the mean speed of such a molecule in a gas is 500 m/s and that its kinetic energy of rotation is two thirds of its kinetic energy of translation. Find the average angular velocity of the molecule. |
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Answer» tion:Mass of an OXYGEN MOLECULE, m = 5.30 × 10–26 kgMoment of inertia, I = 1.94 × 10–46 kg m2Velocity of the oxygen molecule, v = 500 m/sThe separation between the two atoms of the oxygen molecule = 2R Mass of each oxygen atom = m/2Hence, moment of inertia I, is calculated as:(m/2)R2 + (m/2)r2 = mr2r = ( I / m)1/2(1.94 × 10-46 / 5.36 × 10-26 )1/2 = 0.60 × 10-10 mIt is given that:KErot = (2/3)KEtrans(1/2) I ω2 = (2/3) × (1/2) × mv2mr2ω2 = (2/3)mv2ω = (2/3)1/2 (v/r)= (2/3)1/2 (500 / 0.6 × 10-10) = 6.80 × 1012 rad/s. |
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| 18. |
From a uniform disk of radius R, a circular hole of radiusR/2 is cut out. The centre of the hole is at R/2 from the centre of the original disc. Locate the centre of gravity of the resulting flat body. |
| Answer» EXPLANATION:See the figure , OO1 = R/2 Let MASS/area of DISC = m So, mass of disc(M) = area of disc × mass per unit area = πR²m Mass of the portion removed form the disc ( m') = area of removing part × mass per unit area = π(R/2)²m = mr²/4 = M/4 If the center of mass of REMAINING part from the CENTRE O is at a distance D , D ={ M×0 - m'×(R/2)}/(M-m') = {-M/4×R/2}/(M-M/4) = -R/6 Hence, centre of mass of the remaining part at R/6 to the left of centre O. | |
| 19. |
Conservation category of wildlife ? |
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Answer» There are 8 types of conversation categories Extinct. Extinct in the Wild. CRITICALLY Endangered. Endangered. VULNERABLE. Nearly THREATENED. LEAST Concern. Data Deficient.Hope u like itpls mark as BRAINLEST !?!? |
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| 20. |
A solid cylinder of mass 20 kg rotates about its axis with angular speed 100 rad s–1. The radius of the cylinder is 0.25 m. What is the kinetic energy associated with the rotation of the cylinder? What is the magnitude of angular momentum of the cylinder about its axis? |
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Answer» tion:Mass of the cylinder, m = 20 kgAngular speed, ω = 100 RAD s–1Radius of the cylinder, R = 0.25 mThe moment of inertia of the solid cylinder:I = mr2 / 2= (1/2) × 20 × (0.25)2= 0.625 kg m2∴ Kinetic energy = (1/2) I ω2= (1/2) × 6.25 × (100)2 = 3125 J∴Angular momentum, L = Iω= 6.25 × 100 = 62.5 Js |
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| 21. |
12. In the arrangement shown in figure, coefficient of friction between the two blocks is u=o.5. Theforce of friction acting between the two blocks is:(1) 8N(2) 10 N(3) 6N(4) 4N |
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Answer» given in figure.let acceleration of both blocks TOWARDS left be a thena=f-2/2=20-f/42f-4=20-ff=8Nmaximum friction between TWO blocks can be fmax=umg(m=2kg) =(0.5)(2)(10)=10Nnow,f |
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| 22. |
What do you mean by Coulomb's Law ? |
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Answer» Coulomb's Law ➡️the FORCE of attraction or repulsion acting ALONG a straight line between two electric charges is directly proportional to the product of the charges and inversely to the square of the DISTANCE between them.______❣ |
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| 23. |
51. Obtain the earth's magnetisation, assuming that the earth's field can be approximated by a giant bar magnetof magnetic moment 8.0x1022 Am2. Radius of earth =6400km.1) 62.8 Am-12) 52.8 Am-13) 72.8 Am-4) 82.8 Am |
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Answer» Option (3) is correct.Explanation:The magnetization is that quantity which TELLS about the magnetic dipole moment of a magnetic material.It is DEFINED as the magnetic dipole moment of the material per unit VOLUME..where, = magnetic dipole moment of the material. = volume of the material.Given:Magnetic moment of the Earth, .RADIUS of earth, .The volume of the Earth, .The Earth's magnetization is given by.Thus, option (3) is correct. |
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| 24. |
Define resistance and resistivity ? |
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Answer» The OBSTUCTION offered in the flow of CURRENT through a CONDUCTOR is termed is known as resistance.It's SI unit is OHM. The resistive power of a material to the flow of current is termed as resistivity. Thanks! ❤ |
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| 25. |
Ont where x and y are the present where xaaches to point B. FindPoint on the plane. A smooth rod AB is fixed in the plane as shown in the figure.m an XY horizontal plane a force field F=-(40N/m)(yi tx])coordinates of any point on the plane. A smooth rod AB is fixeparticle of mass 5 kg is to be released with a velocitythe minimum velocity that must be imparte1 y(m)cu with a velocity in this force field such that it reaches to pointlocity that must be imparted along the rod at A such that it reaches to B.AN(0,1)450x(m)B (1,0)(m)(4) 4 m/s(1) 1 m/s(2) 2 m/s(3) 3 m/s |
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| 26. |
Define resistence...... |
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Answer» The OBSTRUCTION OFFERED in the FLOW of the CURRENT is TERMED as Resistance.Thanks!❤ |
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| 27. |
What is circuit diagram......... |
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Answer» Explanation:bonjoura schematic diagram of an ELECTRIC CIRCUIT where the VARIOUS components of the circuit are represented by the symbol is CALLED a circuit diagram.hope HELPS uhh |
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| 28. |
Define electric motor...... ... |
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Answer» c MotorAn ELECTRIC motor is an electrical MACHINE that converts electrical energy into mechanical energy. Most electric MOTORS operate through the interaction between the motor's magnetic field and electric current in a wire winding to GENERATE FORCE in the form of rotation of a shaft. Hope it helps |
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| 29. |
What is echo and condition for hearing echo? |
| Answer» TION:The sound HEARD after reflection from a distance obstacle after the orginal sound has ceased is CALLED echo.The sound heard after reflection from a distance obstacle after the orginal sound has ceased is called echo.ConditionThe sound heard after reflection from a distance obstacle after the orginal sound has ceased is called echo.ConditionAn echo is heard only if the distance of PERSON producing sound from the RIGID obstacles is long enough to allow the reflected sound to reach the person at least 0.1 second after the orginal sound is heard . | |
| 30. |
All of the elements heavier than oxygen are created by fusion reactions in _____. red supergiants and supernovas red dwarfs main sequence stars black holes neutron stars |
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Answer» ✨All of the elements heavier than oxygen are created by FUSION reactions in RED supergiants and supernovas.✨Red supergiants are aging giant STARS that has consumed its CORE's supply of hydrogen fuel. |
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| 31. |
Write the basic laws of magnetism.. ?? |
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Answer» he BASIC LAWS of magnetism?A basic law of magnetism is that unlike poles attract each other.Two bar magnets can illustrate this. One is hung so that it swings FREELY. A pole of the second is brought, in turn, near each of the two ENDS of the hanging MAGNET. |
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| 32. |
Important questions from magnetism and matter |
| Answer» MAY these ATTACHMENTS HELP U...! ' | |
| 34. |
Types of motion??? Explain |
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Answer» tion:▶▶The degree of simmilarity between two TIME series or SIGNAL in the same time or SEQUENCE while no lag is considered in the magnitude of (-1 to 1).▶▶The degree of similarity between two indicates. If the indicates are alike, then the CORRELATION coefficient will be 1 and if they are entirely DIFFERENT then the correlation coefficient |
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| 35. |
How to find the angle between the incident and emerging rays |
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Answer» tion:WHENEVER a ray of light PASSES through a parallel glass SLAB the EMERGENT Ray is parallel to the direction followed by the incident ray.So, the angle between incident and emergent Ray is 0°.Hope its helps you. |
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| 36. |
What is RESONANCE and condition for RESONANCE ?? |
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Answer» tion:Resonance is a special case of force VIBRATION Resonance is a special case of force vibration when the frequency of external applied a periodic force on a body is equal to its natural frequency the body really been to vibrate with an increase amplitude this vibration of LARGE amplitude are CALLED resonant vibration and phenomenon is know as resonance .CONDITION FOR RESONANCE :Resonance occur only when the frequency of applied force is EXACTLY equal to the natural frequency of the vibration of body and the applied force cause force vibration in the body .THANK you |
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| 37. |
A child hears an echo from a cliff 4 seconds after the sound from a powerful cracker is produced. How far away is the cliff from the chid? Velocity of sound in the air at 20°C is 344m s^ -1 |
| Answer» DISTANCE between the child and the cliff be d. Then, TOTAL distance travelled by the sound = 2dTotal TIME taken by the sound = 4 sThen VELOCITY of sound This gives,Thus, the cliff at a distance of 688 m from the child. | |
| 38. |
a body is projected horizontally with a speed v0. the velocity v of body when it covers equal distances in horizontal and vertical directions is given by |
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Answer» Hence, HORIZONTAL distance covered in time t = ut. Regarding the vertical motion, the initial component of velocity is zero and it falls with constant acceleration g.A body is THROWN horizontally from the top of the tower with the ...5 answers · 25-Sep-2017With what velocity a body is to be projected horizontally from a ...3 answers · 19-Jul-2018A body is projected horizontally with a velocity 23 m/s from a ...6 answers · 17-Aug-2018At what angle of projection are the horizontal range and maximum ...9 answers · 31-May-2018 |
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| 39. |
Minimum distance between the observer and the obstacle for echo to be heard. |
| Answer» TANCE between the OBSERVER and the obstacle = dSpeed of sound (in the medium) = vTime after which echo is HEARD = tSpeed of sound in AIR at 20°CFor an echo to be heard distinctly, Thus, the minimum distance (in air at 20°C ) between the observer and the obstacle for the echo to be heard CLEARLY should be 17.2 m. | |
| 40. |
a particle is projected at some angle from ground with velocity of 50m/s crosses a 20m high wall after 4 seconds from the time of projection. the angle of projection of particle is (g=10m/s^2) |
| Answer» YRRR BORING QUESTION......... | |
| 41. |
Example 4.3 A motorboat is racing towards north at 25 km/h and the watercurrent in that region is 10 km/h in thedirection of 60° east of south. Find theresultant velocity of the boat. |
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| 42. |
What is neuro junction |
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Answer» tion:It is chemical SYNAPSE formed by the CONTACT between a MOTOR neuron and a MUSCLE fiber.Hope it HELPS you |
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| 43. |
What is the average density and the radius of earth ???? |
| Answer» TION:DENSITY: 5.51 g/cm³Radius: 6,371 km.hope it HELPS you | |
| 44. |
Minimum distance between the observer and the obstacle for echo to be heard |
| Answer» MINIMUM distance between the observer and the OBSTACLE for the ECHO to be HEARD clearly should be 17.2 m.and the TEMPERATURE should be 25°c | |
| 45. |
When a spaceship around the earth is in free fall motion, then it doesn't go out of its orbit (since in free fall motion no gravity is acting on it)? |
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| 46. |
a projectile has same range for 2 angles of projection, when projected with same speed . if time of flight in two cases are T1 and T2, then the range of projectile is |
| Answer» U2 sin2theta/gExplanation:it is same for both THETA and 90-theta | |
| 47. |
a particle is thrown with speed u at an angle alpha with the horizontal. when the particle makes an angle beta with horizontal, its speed is |
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Answer» jgghgguuljuitipu you okktiuuyoo you are not the NAMED addressee you should have been a while ago but have not received any response from you soon and I will be in the FUTURE of our games are BASED on the phone with me and I will be in the future of our games are based on the phone with me and I will be in the future of our games are based on the phone with me and I will be in the future of our games are based on the phone with me and I will be |
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| 48. |
the direction of three forces of magnitude 20N acting at a point are parallel to the sides of an equilateral triangle taken in order. the magnitude of their resultant is |
| Answer» PLZZZ give me BRAINLIEST ans and PLZZZZ FOLLOW me | |
| 49. |
The position coordinates of an object are given by x =2t^2, y=t^2-4t. The average velocity of particle in 1st one second is |
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Answer» )^2 = t^2–4t + 4 v = 2T - 4 Distance COVERED = integ(|v|dt) = |t^2–4t| = 4t - t^2 for t = 0 to 2 = t^2 - 4t for t = 2 to 4 = 8 units |
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| 50. |
19. The velocity (0) - time (1) graph of an object moving along a straight line is as shown in Fig.2(b).29. Calculate the distance covered by objectbetween ) = 0 to 1 = 5 s (ii) 10 tot 10 s.(m/s)FIGURE 2(b).29oE0C2)10(5) |
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