1.

A ball is thrown vertically upwards from the top of a tower with a speed of 100 m/s. It strikes the pond near the base of the tower after 25 second. The height of the tower is(1) 500 m(2) 125 m(3) 625 m(4) 425 m​

Answer»

- Initial velocity = 100 ms-¹As we know that when a BODY is thrown upward then it is moving with negative acceleration due to gravity.g = -10 ms-²Here we will APPLY the third equation of motion:- v²-u²= 2gh 0²-(100)²= 2 x -(10) x h -10000 = -20H h = -10000/-20h = 500 m Hence, the height of tower = h = 500 m.



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