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A coil having N turns and resistance R Ω is connected to a galvanometer of resistance 4R Ω. This combination is moved in time I seconds from a magnetic flux Φ₁ Wb to Φ₁ Wb. What is the induced current in the circuit?Answer the Given question in brief. |
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Answer» udent,◆ ANSWER -I = -N(Φ₂-Φ₁)/5Rt◆ Explanation -Total resistance in the circuit is -R' = R + 4RR' = 4RAlso EMF induced in the coil is given by -V = -N.∆Φ/tV = -N(Φ₂-Φ₁)/tNow, induced CURRENT in the circuit will be -I = V/R'I = [-N(Φ₂-Φ₁)/t]/5RI = -N(Φ₂-Φ₁)/5RtHope this HELPS you... |
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