| 1. |
A coil having 200 turns has a surface area 0.12 m². A magnetic field of strength 0.10 Wbm⁻² linked perpendicular to this area changes to 0.5 Wbrn⁻² in 0.2 s. Find the average emf induced in the coil. [Ans:48 V] |
|
Answer» Average value of induced emf = 48 V.Explanation:Given:Number of turns of the coil, .Surface area of the coil, .Strength of the magnetic field initially, .Strength of the magnetic field after 0.2 s, .The magnetic flux through a surface is defined as where, = area vector of the coil which is DIRECTED along the normal to the plane of the coil and has magnitude equal to the surface area of the coil. = ANGLE between and .In the given question, the magnetic field is perpendicular to the area of the coil which means it is along the same direction as that of .THEREFORE, .The magnetic flux linked with the coil is given asAccording to the Faraday's law of electromagnetic induction, the emf induced in the coil is given by is the change in the magnetic field = Therefore, The average induced emf is given bySince, there is no TIME dependent term in the value of the induced emf, therefore,Thus, the magnitude of average emf induced in the coil is same as the magnitude of induced emf i.e., 48 V. |
|