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A wheel with 10 metallic spokes each 0.5 m long rotated with a speed of 120 rpm in a plane normal to the horizontal component of earth’s magnetic field Bh at a place. If Bh = 0.4 G at the place, what is the induced emf between the axle and the rim of the wheel ? (1G=10⁻⁴ T)choose the correct option from the given options. (A) 0 V (B) 0.628 mV (C) 0.628 μV (D) 62.8 μV

Answer»

udent,◆ ANSWER -(D) 62.8 μV◆ Explanation -Potential DIFFERENCE GENERATED between rim and axis of cycle is calculated by -EMF = 1/2 B.ω.l²EMF = 1/2 × B × 2πf × l²EMF = B × πf × l²EMF = 0.4×10^-4 × 3.14 × 2 × 0.5^2EMF = 62.8×10^-6 VEMF = 62.8 μVTherefore, EMF generated between rim and axis of cycle is 62.8 μV.Thanks DEAR...



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