Explore topic-wise InterviewSolutions in Current Affairs.

Hey Mate

Here is your answer




Hope it helps

Cheers!!

PLEASE MARK as brainliest if it helps

A+37d=3A+17d×3
a+37d= 3a+ 51d
2a+14d=0
2(a+7d)=0
2×0=0
ans is 0.
I HOPE it DEFINITELY helps u.

20+1=21we can EXPRESS..

HEY DEAR !!
HERE IS YOUR ANSWER.

88 PAISA PER kg

see the refer ATTACHMENT for the BRIEF solution

YES it is CORRECT QUESTION GO AHEAD

We have x/2+2y/3=-1............

I can't UNDERSTAND ANYTHING PLZZ RESEND it

The FIRST 12 odd numbers are :
9, 15, 21, 25, 27, 33, 35, 39, 45, 49, 55, 57

Hope it'll help..

Eliminate 17 and 16 from both SIDES
and you will get ur ANS
i. E.
x = -13

We can find that the MIRROR is CONCAVE or convex by seeing the mirror:
• the mirror will be concave if the mirror SURFACE is inward
•the mirror will be convex if the mirror surface is outward
Hope this answer HELP u
Mark as brainliest

(75-25)-2÷50×10
=50-2÷50×10
=50-25×10
=50-250
=200(ANS)

Dead FRIEND,
Here's your ANSWER...
Least number DIVISIBLE by 15, 20, 24, 32, 36 = LCM(15, 20, 24, 32, 36) = 2880
So, the answer is 2880.
Hope it helps you!!
Please mark my answer as BRAINLIEST!

An = 253
d= -5
N th term from end= ( an + (n -1)d )
20th term from end = ( 253+ 19*-5)
=( 253-95)
= 158

The positive integers MEANS all NUMBERS like 1,2,3,4 etc and SOMETIMES 0 as well are CALLED natural numbers.

2500/2=1250. it is very EASY QUESTION

I think

should be the ANSWER

(x-y) ^2 = (x+y)^2 -4xy
= (9)^2 -4(-22)
= 81+88
169
(x-y) ^2 =169
x-y = root(169)
x-y=13 is answer

By phythagores THEORAM,
AC^2=AB^2+BC^2
10^2=6^2+BC^2
100=36+BC^2
100-36=BC^2
64=BC^2
SQUARE ROOT of 64=BC
BC=8 CM
a=10cm
b=6cm
c=8cm
s=a+b+c/2
=10+6+8/2
=24/2
s=12cm
Area of triangle
=square root of (s-a)(s-b)(s-c) =square root of (12-10)(12-6)(12-8)
=square root of 2×6×4
=square root of 2×3×2×2×2
=2×2 square root of 3
=4 square root of 3

zeroes of 2x^2 - 5X - 3

=> 2x^2 - 6x + x - 3 = 0

=> 2x( x - 3 ) + ( x - 3 ) = 0

=> ( x - 3 ) ( 2x + 1 ) = 0

=> x = 3 Or x = -1/2

According to the question,

zeroes of x^2 + PX + q are 2(3) = 6 and 2(-1/2) = -1

taking 6 as zero,

x^2 + px + q = 0

6^2 + 6p + q = 0

36 + 6p + q = 0

q = - 36 - 6p

taking -1 as zero,

x^2 + px + q = 0

(-1)^2 -p + q = 0

1 - p + q = 0

q = p - 1

========================

q = q

=> -36 - 6p = p - 1

=> -36 + 1 = p + 6p

=> -35 = 7p

=> -5 = p

q = p - 1

= -5 - 1

= - 6

HENCE, p = - 5 and q = -6

Yes SURE i will DEFINE rational and IRRATIONAL numbers

966666666669999999998589686

The PRODUCT of TWO NUMBER is 450

Answer:

(AverageCGPA - 0.75) * 10%.

Step-by-step explanation:

In order to calculate the aggregate PERCENTAGE in semester exams it is not the CGPA*10 but some more CALCULATION to it.

First of all you have to find the aggregate CGPA of the five sems that can be obtained by adding the CGPAs and dividing it by 5.

Now subtract 0.75 from the obtained result.

Now MULTIPLY 10 to the difference obtained.

The obtained product will be your percentage.

For example the aggregate CGPA of 5 semester is 8.75.

So, 8.75-0.75 = 8.00

Now, % will be 8.00×10%  = 80%.

5/4 -4/5
take LCM
LCM of 4,5 is 20
5×5 -4×4/20
25-16/20
9/20 is ANSWER

You need to CONSIDER the ORDER of operations.

First, we evaluate what is inside the parenthesis:

15−(−3)2+(4−4)3⋅[5+(−3)⋅(−6)]=15−(−3)2+03⋅[5+(−3)⋅(−6)]
15
−
(
−
3
)
2
+
(
4
−
4
)
3
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]
=
15
−
(
−
3
)
2
+
0
3
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]

Next, we evaluate the exponents:

15−(−3)2+03⋅[5+(−3)⋅(−6)]=15−9+03⋅[5+(−3)⋅(−6)]
15
−
(
−
3
)
2
+
0
3
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]
=
15
−
9
+
0
3
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]

Next, we evaluate any multiplication and division:

15−9+03⋅[5+(−3)⋅(−6)]=15−9+0⋅[5+(−3)⋅(−6)]
15
−
9
+
0
3
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]
=
15
−
9
+
0
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]

15−9+0⋅[5+(−3)⋅(−6)]=15−9+0
15
−
9
+
0
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]
=
15
−
9
+
0

Finally, we evaluate any ADDITION and subtraction:

15−9+0=6

(a+b)^2 =a^2 + b^2 + 2×a×b
= a^2 + b^2 + 2AB

a - 1/a= 5. a^2 + 1 ÷ a^2
a - 1. =5a. Substituting a=-1/4
4a = -1. We get
a. = -1/4. Ans 17

X = 280°
Explanation -
const.- DRAW a line segment PQ from point O ,i.e. PQ || AB || CD
Proof- ANGLE BOQ = 55° ( alternate angle)
angle DOQ = 25° ( " )
ANGLEBOD +angle DOQ +angle BOQ= 360
BOD +25+55=360
BOD =360-80
=280°

(|||) is the RIGHT ANSWER

hey friend ,

Here is your answer

======================================================================

remainder theorem ,

if (x)=-1/2 i.e. x+1/2=0 is the ZERO of POLYNOMIAL

then p(x)=2x+1=0

lets verify

L.H.S

2*( -1 )+1 => -1+1=0=R.H.S { since TWO and two get cancelled }

      2

HENCE PROVED

======================================================================

HOPE THIS HELPED YOU

3xof 2x=90 (COMPLEMENTARY ANGLES)
6X =90
x=90/6
x =15

Given d=6
t1 t2 are FIRST 2 terms
product =135
a(a+d)=135
a(a+6)=135
a^2+6a-135=0
a^2+15a-9a-135=0
a(a+15)-9(a+15)=0
(a-9)(a+15)=0
a=9, -15
a=9 is considered
first term is a and answer is 9

your question NEEDS a correction,

6 is written wrong as 60

first term = a

COMMON difference = d = 6

SECOND term = a + d

= a + 6

Product of first and second term = 135

/

a = - 15 or 9