1.

(3^2)0 +3-4×3^6+(1÷3)-2

Answer»

You need to CONSIDER the ORDER of operations.

First, we evaluate what is inside the parenthesis:

15−(−3)2+(4−4)3⋅[5+(−3)⋅(−6)]=15−(−3)2+03⋅[5+(−3)⋅(−6)]
15

(

3
)
2
+
(
4

4
)
3

[
5
+
(

3
)

(

6
)
]
=
15

(

3
)
2
+
0
3

[
5
+
(

3
)

(

6
)
]

Next, we evaluate the exponents:

15−(−3)2+03⋅[5+(−3)⋅(−6)]=15−9+03⋅[5+(−3)⋅(−6)]
15

(

3
)
2
+
0
3

[
5
+
(

3
)

(

6
)
]
=
15

9
+
0
3

[
5
+
(

3
)

(

6
)
]

Next, we evaluate any multiplication and division:

15−9+03⋅[5+(−3)⋅(−6)]=15−9+0⋅[5+(−3)⋅(−6)]
15

9
+
0
3

[
5
+
(

3
)

(

6
)
]
=
15

9
+
0

[
5
+
(

3
)

(

6
)
]

15−9+0⋅[5+(−3)⋅(−6)]=15−9+0
15

9
+
0

[
5
+
(

3
)

(

6
)
]
=
15

9
+
0

Finally, we evaluate any ADDITION and subtraction:

15−9+0=6



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