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Please solve this ASAP..Q.no 3..And get 100 points |
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Answer» => 2x^2 - 6x + x - 3 = 0 => 2x( x - 3 ) + ( x - 3 ) = 0 => ( x - 3 ) ( 2x + 1 ) = 0
=> x = 3 Or x = -1/2 According to the question, zeroes of x^2 + PX + q are 2(3) = 6 and 2(-1/2) = -1 taking 6 as zero, x^2 + px + q = 0 6^2 + 6p + q = 0 36 + 6p + q = 0 q = - 36 - 6p taking -1 as zero, x^2 + px + q = 0 (-1)^2 -p + q = 0 1 - p + q = 0 q = p - 1 ======================== q = q => -36 - 6p = p - 1 => -36 + 1 = p + 6p => -35 = 7p => -5 = p q = p - 1 = -5 - 1 = - 6 HENCE, p = - 5 and q = -6 |
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