the product of first 2 tearms of an arithernetic sequence with common

1.	the product of first 2 tearms of an arithernetic sequence with common difference is 60 is 135 find the first term
Answer» your question NEEDS a correction, 6 is written wrong as 60 first term = a COMMON difference = d = 6 SECOND term = a + d = a + 6 Product of first and second term = 135 / $\rightarrow a( a + 6 ) = 135 \\\rightarrow a^2 + 6a - 135 = 0 \\\rightarrow a^2 + 15a - 9a - 135 = 0\\\rightarrow a( a + 15 ) - 9( a + 15 ) = 0\\\rightarrow (a + 15 ) (a - 9 ) = 0 \\$ a = - 15 or 9

the product of first 2 tearms of an arithernetic sequence with common difference is 60 is 135 find the first term

Answer»

your question NEEDS a correction,

6 is written wrong as 60

first term = a

COMMON difference = d = 6

SECOND term = a + d

= a + 6

Product of first and second term = 135

/ $\rightarrow a( a + 6 ) = 135 \\\rightarrow a^2 + 6a - 135 = 0 \\\rightarrow a^2 + 15a - 9a - 135 = 0\\\rightarrow a( a + 15 ) - 9( a + 15 ) = 0\\\rightarrow (a + 15 ) (a - 9 ) = 0 \\$

a = - 15 or 9

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the product of first 2 tearms of an arithernetic sequence with common difference is 60 is 135 find the first term

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