1.

the product of first two terms of an arithmetic sequence with the common difference 6 is 135 find the first term

Answer»

Given d=6
t1 t2 are FIRST 2 terms
product =135
a(a+d)=135
a(a+6)=135
a^2+6a-135=0
a^2+15a-9a-135=0
a(a+15)-9(a+15)=0
(a-9)(a+15)=0
a=9, -15
a=9 is considered
first term is a and answer is 9



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