This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Express the following in the form of p/q where p and q are integers and q≠0 (a) 0.6 |
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Answer» Here we don't know what 0.6...... is, let US CALL it 'x' |
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| 2. |
express 5.2 in the form of p/q where p and q are in integers and q is not equal to 0 please workout for me plzzzz |
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Answer» HEY dear here is your answer 5.2= 52/10 hope it will HELP you |
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| 3. |
The sum of a number and it's reciprocal is 50/7 then the number is |
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Answer» HOPE this HELPS you please MARK as BRAINLIST |
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| 4. |
If Alfa and beta are the zeroes of the quadratic polynomial f(x) = kx² + 4x + 4 such that Alfa² + beta² = 24 find the value of k |
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Answer» LET ALPHA =a and beta=b a+b= -4/k and AB= 4/k a^2+b^2=[(a+b)^2-2ab] 24=16/k^2 - 8/k 3=2/k^2 - 1/k 3k^2+k-2=0 (3k-2)(k+1)=0 k = 2/3 or -1 |
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| 5. |
The denominator of a rational number greater than its numerator by 8 if numerator is increased by 17and denominatior is decreased by 1 the number obtained is 3/2 the rational number is? |
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Answer» Let the rational no be x / y |
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| 6. |
Prove that 8n never ends with digit 0 |
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| 7. |
What will be the sign of the product if we multiply together 7 negative integers and one positive integer? (Solution with answer please) |
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| 8. |
What must be subtracted or added to p of x is equals to 8 power 4 + 14 x cube minus 2 x square + 8 x minus 12 so x 4 x square + 3 x minus 2 is a factor of p of x? |
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Answer» Now, p (x) ÷ g (x) REMAINDER you will GET after dividing is your answer. Thanks |
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| 9. |
The marked price of a book is 225 . The publisher allow a discount of 10 on it.find the selling price of it? |
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Answer» 10% of 225 10/100*225 22.5rs Do SP= 225-22.5 =202.5 RS |
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| 10. |
The compound interest on 4000 at 10% annum for 2years 3months , compounded annually will be |
| Answer» HOPE. this HELPS you LITTLE SOUL | |
| 11. |
a mobile phone was marked at 35% above the cost price and a discount of 20% was given on the marked price find the profit it % or loss % made by the shopkeeper |
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Answer» Let the cost price be ₹100 |
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| 12. |
Rationalise the denominator √2+1/√5 where √10 = 3.162 and √5 = 2.236 |
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| 13. |
Ve=? ve=√2gr r=6400km g=9.8m/s2 |
| Answer» UR ANSWER is ........88699.47 after MULTIPLYING | |
| 14. |
The sides of a triangular field are 41m,40m and 9m.Find the number of rose beds that can be prepared in the field if each rose bed in an average requires 900cm square of space |
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Answer» By HERON's FORMULA. Area of a triangular= √s×(s-a)(s-b)(s-C) ,where a,b,c are sides of the triangle and s is the semi perimeter. so, area of the field=√[45×(45-41)(45-40)(45-9)] = √(45 × 4 × 5 × 36) = √32400 = 180m^2 =1800000cm^2. now, space needed for a flower BED = 900cm^2. so, number of flower beds = 1800000/900 = 2000. |
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| 15. |
How.to.make a different type of tbing with the help of circle? |
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Answer» Hlo firstly CUT 40 circles from a tissue PAPER then PASTE them step-by-step when its finished crump all the circle step-by-step . its a tissue flower |
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| 16. |
If alpha and beta are zero of quadratic polynomial f(t)=t^2-p(t+1)-c,show that (alpha+1)(beta+1)=1-c |
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Answer» HEYA!! REFER to GIVEN ATTACHMENT PLEASE |
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| 17. |
If cos ∅ - sin ∅ =√2 sin∅, prove that cos ∅ + sin∅ =√2 cos∅ |
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Answer» Here I am WRITING Ф as A because it is difficult for me to WRITE Ф Always. |
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| 18. |
A person bought some articles at the rate of 6 for rs 20 and bought same number of articles at the rate of 8 for rs 25. and sold all the stock at the rate of 8 for rs 31. find the profit or loss % |
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Answer» He had and profit he sold articles of which he brought for recipes Rs 25 for 8 and he had sold it for Rs 31 of 8 , he also had sold articles which he was brought for Rs 21 of 6 and sold it for the Rs 31 of 8, so, he had EARNED profit. |
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| 19. |
Simplify square root of 80/405 |
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Answer» Hey friend, |
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| 20. |
(2+3)*3250 + 3 power minus 1 into 3 power 2 |
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Answer» Hey friend, |
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| 21. |
Factorize 4x^2+9y^2+16^2+12xy-24yz-16xz |
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Answer» HELLO DEAR FRIEND . here is Ur answer . ……………………………………………………… Hope it's HELPS you. <<<☺>>> |
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| 23. |
Construct the given angles using ruler and compass only ¡) 60° |
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Answer» Steps: |
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| 24. |
On rationalizing the denominator of 1/√7-√6 |
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Answer» |
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| 25. |
Find the hcf of 81 and 237 and express it as a linear combination of 81 and 237 |
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Answer» 237=81*3+3 81=27*3+0 There FORE 3 is the hcf 3=81-27*3 =81-27*237-81*3 =81*-2-27*237 |
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| 26. |
How to rationalize the denominator? |
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Answer» To be in "simplest form" the denominator should not be IRRATIONAL! FIXING it (by MAKING the denominator RATIONAL) is called " Rationalizing the Denominator". |
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| 27. |
If 7x=1 then find the decimal expantion of x. |
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Answer» Heya |
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| 28. |
Math question out odd numbers and write them in the give spaces13 16 24 19 17 20 ..........................answer |
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Answer» In 1 BLANK 2 |
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| 29. |
Prove that root 3+root 5 is irrational |
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Answer» Hey friend your answer is ☺ |
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| 30. |
If a certain amount with simple interest becomes double in 10years ,then what is the rate of interest p.c.p.a? |
| Answer» 2% PA. is a RATE ...... | |
| 32. |
Divide the sum of 3/8 and -5/12 by the reciprocal of-15/8×16/27 |
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Answer» Here is your ANSWER.... |
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| 33. |
Name the quadrilateral with only one pair of opposite parallel sides |
| Answer» TRAPEZIUM has only ONE OPPOSITE PARALLEL SIDES | |
| 34. |
after covering 3 by 4 of my journey, I find that 15 km is still left. how much distance is the total journey ? |
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Answer» 1- 3/4 =1/4 1/4 =15 1=60km |
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| 36. |
Find CSA of each of the of the following cylinders |
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Answer» HEY DEAR.... YOUR ANSWER⬆ sry about my messy handwriting. I HOPE YOU FIND IT HELPFUL. YOUR FRIEND. #LAKSHMI... :-) |
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| 38. |
A car travels 30 km at an uniform speed of 40 km per hour and the next 30 km at a uniform speed of 20 kilometre per hour find its average speed |
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Answer» ANS 1st Fomula:AVERAGE Speed = Total Distance / Total TimeSpeed = Distance / TimeTime = Distance / SpeedTime1 = 30 / 40 = 0.75 hoursTime2 = 30 / 20 = 1.5 hoursAverage Speed = (30 + 30) / ( 1.5+0.75)Average Speed = 60 / 2.25Average Speed = 60 / 2.25Average Speed = 26.667 km/hr Ans 2 and 3 in image |
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| 39. |
In how much time will a certain sum be 1.5 times the principal at 10% per annum ? |
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Answer» Hi |
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| 40. |
I6f 45kg 450 gm of sugar equally distribute among 15 persons how much shall each get |
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Answer» Given : 45 kg 450 gm of sugar be equally DISTRIBUTED among 15 people To Find : Each one's share. Solution :Let's change Kilograms to GRAMS : So,
45 kg = 45 x 1000 45 kg = 45000 grams. As given, Total QUANTITY of Sugar : 45000 g + 450 g → 45450 grams. Finding Each One's Share : 15 people = 45450 grams sugar 1 person = 45450÷15 1 person = 3030 grams. 3030 grams = 3030÷1000 3030 grams = 3.03 kg. Hence, Hence, Each person will get 3.03 kg of sugar. |
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| 41. |
Factorise: x^2+y^2+x+y+2xy |
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Answer» X² + y² + X + y + 2XY = x² + y² + 2xy + x + y = (x+y)² + (x+y) = (x+y) (x+y+1) |
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| 42. |
If f (x) x²+3_2x-3 then f(-1) |
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Answer» -1 is the ANSWER SUBSTITUTE -1 in the PLACE of X |
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| 43. |
A two digit no. is 4 times the sum of its digits and twice the productof its digits .Find the numberPls don't spam answer..Pls give me ryt answer I have doubt on my equation..Pls help me ☺️ |
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Answer» Let the digit in the ones PLACE be x and tens place be y |
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| 44. |
A rectangular sheet of paper is 15 3/4 cm long and 12 1/2 cm wide .find perimeter |
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Answer» HEY mate !! Here's your ANSWER !! REFER to the attachment !! Hope it helps !! CHEERS !! |
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| 45. |
The Marketed Price of an gift item is Rs.176 and sold it for Rs.165. Find the discount percent. |
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Answer» Discount % = 6.25% Step-by-step explanation: Marked PRICE of the GIFT item = 176 rs Selling price of the gift item = 165 rs Discount = marked price - selling price Discount = 176 - 165 Discount = 11 rupees The shopkeeper PROVIDED a discount of 11 rupees on the gift item Discount % = discount/marked price × 100 Discount % = 11/176 × 100 Discount % = 25/4 Discount % = 6.25% Discount % = 6.25% |
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| 47. |
Find values of : i) sin120° ii)cos315° |
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Answer» .......................... |
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| 49. |
Factorise (2x5) (3x-2) (x2) (2x-3) |
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Answer» HEY!! [(2X+5)(3x-2)] + [(X+2)(2x-3)] = [2x (3x-2) + 5 (3x-2)] + [x (2x-3) + 2(2x-3)] = [6x^2 - 4x + 8X - 10] + [2x^2 - 3x +4x - 6] = [6x^2 + 4x - 10] + [2x^2 + x - 6] = 6x^2 + 4x - 10 + 2x^2 +x - 6 = 6x^2 + 2x^2 + 4x + x -10 - 6 = 8x^2 + 5x -16 |
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