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If Alfa and beta are the zeroes of the quadratic polynomial f(x) = kx² + 4x + 4 such that Alfa² + beta² = 24 find the value of k |
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Answer» LET ALPHA =a and beta=b a+b= -4/k and AB= 4/k a^2+b^2=[(a+b)^2-2ab] 24=16/k^2 - 8/k 3=2/k^2 - 1/k 3k^2+k-2=0 (3k-2)(k+1)=0 k = 2/3 or -1 |
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