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Hiiii VIEWER here's the answer to the given question

first 10 NATURAL numbers are 1,2,3,4,5,6,7,8,9,10
it's squares are 1,4,9,16,25,36,49,64,81,100

it's SUM are 1+4+9+16+25+36+49+64+81+100=385

hope ull get the answer to the given question and mark as brainliest one.........

Min value of ax^2 + BX + c (where a>0) is -D/4a.
D = DISCRIMINANT


Using this, min value of the expression is

= -49/8

Mean=sum of OBSERVATION /TOTAL no. of observation
MEDIAN= n+1/2

First TAKE LCM of 10 and 10
then FIND the WORDS to which we multiply and get 10 as denominator
the TWO fractions will come
between that u can find

The ANSWER is 15

Heya !!

Here's your answer.. ⬇⬇

GREATEST six digit no. is = 999999

Find L.C.M of 24, 15 and 36.

24 = 2 × 2 × 2 × 3

15 = 3 × 5

36 = 2 × 2 × 3 × 3

L.C.M = 2 × 2 × 2 × 3 × 3 × 5

= 360

Now, divide 999999 by 360

= 999999/360
= 2777.777..
= 2777 ( approx. )

Multiplying L.C.M 360 by 2777 we GET..

= 2777 × 360
= 972220

Now,

972220/24 = 41655

972220/15 = 66648

972220/36 = 27770

972220 is divisible by 15, 24, and 36.

972220 is the greatest no. divisible by 15, 24 and 36.


Hope it helps..

Thanks (:

7x/6 =7350
X =1050×6 =$6300 CP

Here the ANSWER.................

S = (15 + 13 + 14)/2 = 21

Now APPLY herons formula











Area = 1/2 × b × H

84 = 1/2 × 14 × h

(84 × 2)/14 = h

h = 12 cm


Thanks

2x+5=0
2x=-5
x=-5/2

hope ULL GET the answer to the given question and MARK as BRAINLIEST one

Answer :-

→ k = 0 .

Step-by-step explanation :-

It is GIVEN that,

→ One zeros of the given polynomial is NEGATIVE of the other .

Let one zero of the given polynomial be x .

Then, the other zero is -x .

•°• Sum of zeros = x + ( - x ) = 0 .

But, Sum of zeros = -( COEFFICIENT of x )/( coefficient of x² ) = - ( -8k )/4 .

==> 2k = 0 .

==> k = 0/2 .

k = 0 .

Hence, it is SOLVED.

Heyaa....

Subtract:

(-728)-(-415)
=(-728)+(415)
(-313)

HOPE it helped you DEAR

Any INTEGER can be written as
1.4q,
2.4q+1,
3.4q+2,
4.4q+3,
5.4(q+1) {=4n, n€z},
check which no is/are ODD

only 2 and 4 are not divisible by 2.therefore odd.

Hope it helps U..let me KNOW if its not CLEAR

1.414 is the ANSWER

LET the shorter side of the rectangular field be 'x' meters.

Therefore the LONGER side will be (x + 30) meters.

And the LENGTH of the diagonal will be (x + 60) meters.

Now, according to the question,

The diagonal divides the rectangular into two right angledtriangles and the diagonal is the common side of the two triangles and it isalso the LONGEST side of the triangles i.e. the hypotenuse.

So, by Pythagoras Theorem,

(Diagonal)² = (Smaller Side)² + (Longer Side)²

(x + 60)² = (x)² + (x + 30)²

x² + 120x + 3600 = x² + x² + 60x + 900

x² + 60x - 120x + 900 - 3600 = 0

x² - 60x - 2700 = 0

x² - 90x + 30x - 2700 = 0

x(x - 90) + 30(x - 90) = 0

(x - 90) (x + 30) = 0

x = 90 because x = - 30 as length cannot be possible.

So the length of the shorter side is 90 meters and thelength of the longer side is 90 + 30 = 120 meters.

There’s an alternate method too:

Let the shorter side of the rectangle be x m.
Then, larger side of the rectangle = (x + 30) m

⇒ x2 + (x + 30)2 = (x + 60)2
⇒ x2 + x2 + 900 + 60x = x2 + 3600 + 120x
⇒ x2 - 60x - 2700 = 0
⇒ x2 - 90x + 30x - 2700 = 0
⇒ x(x - 90) + 30(x -90)
⇒ (x - 90)(x + 30) = 0
⇒ x = 90, -30
However, side cannot be negative. Therefore, the length ofthe shorter side will be 90 m.
Hence, length of the larger side will be (90 + 30) m = 120 m.

Hope This Helps :)

Let the THREE consecutive ODD NUMBERS be x, x+2, x+4
Given that the SUM of these numbers = 63
Therefore
x + x + 2 + x + 4 = 63
3x + 6 = 63
3x = 57
x = 57/3 = 19

Therefore the three consecutive odd numbers are 19, 21, 23

Hey Mate!
~~~~~~~~

Here is your answer :

=================================

Given,

Sum of the numbers = 36

let the numbers be X , x +1 , x + 2

ATP,

x + x + 1 + x + 2 = 36

3x + 3 = 36

3x = 36 - 3

3x = 33

x = 33/3

x = 11

Therefore,

the numbers are 11, 12, 13


HOPE THIS HELPS U...

Heyy Gagan....
.
.
4x^2+8x+3
4x^2+6x+2x+3
2x(2x+3)+(2x+3)
(2x+3)(2x+1)
.
.
here is UR ANSWER....
mark it as BRAINLIEST

According to question

T9 = 0

let a is the first term of A.p. and d is difference

=> a + 8d = 9 ......(1)

now

T19 = a + 18d

= (a + 8d) +10d

put value (a+8d) from equation (1)

= 0+ 10d

T19 = 10d ....(2)

same as

T29 = a + 28d

= (a+ 8d) + 20d

= 0 + 20d

T29 = 20d .....(3)

now from equation (2)& (3) we can say that

T29 = 2(10d)

T29 = 2(T19) →that's proved ......

—————————————

hope it will HELP you .....,,,,✌✌✌

HEYA FRND. ........ ☺

PLZ SEE THE ATTACHED PICTURE ABOVE. . . . . . . . . ☝

HOPE IT WILL HELP YOU. . . . . . . ☺

GIVEN,

Investment = RS. 8800

FV = Rs. 100

Premium = 10 %

So,

MV = 100 + 10%100

MV = 100 + 10

MV = Rs. 110

1)--

Number of SHARES = Investment \ MV on one share

Number of shares =8800 / 110

Number of shares = 80.

2)--

Dividend = Rs. 1200

Annual dividend = (Number of shares × Dividend % × FV) \100

Annual dividend = 80 × DIVIDENT % × 100 /100

1200= 80 × Divident %

1200 /80 = Dividend %

Dividend % = 15 %

Hey mate !!

Here's the ANSWER !!

REFER to the ATTACHMENT !!

Hope it HELPS !!

Cheers !!

Hey, here is your answer.....

I THINK answer is.....

OPTION : D... i.e., 90°....

HOPE this helps you....

THANK you.... for giving me a CHANCE to answer...

Heya DEAR,

here IZ your answer

Let the the 3 NUMBERS to be

x , x+11 , x+22

now ATQ

sum of these CONSECUTIVE numbers is 363

so,

x+x+11×x+22 = 363

3x + 33 = 363

3x = 363 - 33

3x = 330

now x = 330/3

x = 110

So now the numbers are

x = 110

x+11 = 110+11 = 121

x+22 = 110+22 = 132

sho 110,121,132 sum is 363 and also these are consecutive MULTIPLES of 11


thanks !!!!

The REQUIRED PAIR of INTEGERS here is,
(-2) + (-3) = (-5)

31/6+x=19/42
X= 19/42-(31×7)÷(6×7)
= -33/7

Here is your answer
make factors of 72
72=2x2x2x3x3
make PAIRS 2x2 and 3x3 since 2 is not MAKING pair it is the required number and if we DECIDE it we will GET 36WHICH is sq of 6
hope helped

Your ANSWER is GIVEN in attachment.

Hope it HELPS U :)

Hi friend, Harish  here.

Here is your answer:

GIVEN that:

NON PARALLEL sides are 18m & 22m .

Height = 16m

To FIND, 

The area of the trapezium.

Solution:



⇒ 

⇒  

Therefore are is 320 m².
____________________________________________________

Hope my answer is helpful to you.

299=15+(n-1)4
299=15+4n-4
299=11+4n
299-11=4n
288=4n
n=72

Hello user !!!

FINDING SQUARE of 81 using REPEATED subtractions of odd numbers.

81-1=80
80-3=77
77-5=72
72-7=65
65-9=56
56-11=45
45-13=32
32-15=17
17-17=0

Therefore, √81 =9

Hope it HELPS :)

There is no QUESTION PAPER for CLASS 7TH

By VBODMAS RULE


(-6)+[(-8)+12]=[-6+(-8)]+12
-6+4=-14+12
-2=-2

LHS=RHS

7/9 will be 1.28 

HOPE it HELPS!!