Heya DEAR,here IZ your answer Let the the 3 NUMBERS to bex , x+11 , x+22 now ATQsum of these CONSECUTIVE numbers is 363so,x+x+11×x+22 = 3633x + 33 = 3633x = 363 - 333x = 330now x = 330/3x = 110So now the numbers arex = 110x+11 = 110+11 = 121x+22 = 110+22 = 132sho 110,121,132 sum is 363 and also these are consecutive MULTIPLES of 11thanks !!!!
Your experience on this site will be improved by allowing cookies. Read Cookie Policy