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Factorise (2x5) (3x-2) (x2) (2x-3) |
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Answer» HEY!! [(2X+5)(3x-2)] + [(X+2)(2x-3)] = [2x (3x-2) + 5 (3x-2)] + [x (2x-3) + 2(2x-3)] = [6x^2 - 4x + 8X - 10] + [2x^2 - 3x +4x - 6] = [6x^2 + 4x - 10] + [2x^2 + x - 6] = 6x^2 + 4x - 10 + 2x^2 +x - 6 = 6x^2 + 2x^2 + 4x + x -10 - 6 = 8x^2 + 5x -16 |
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