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On rationalizing the denominator of 1/√7-√6

Answer»
\frac{1}{ \sqrt{7} - \sqrt{6} } \\ \\ = \frac{1}{ \sqrt{7} - \sqrt{6} } \times \frac{ \sqrt{7} + \sqrt{6} }{ \sqrt{7} + \sqrt{6} } \\ \\ = \frac{ \sqrt{7} + \sqrt{6} }{ {( \sqrt{7}) }^{2} - {( \sqrt{6}) }^{2} } \\ \\ = \frac{ \sqrt{7} + \sqrt{6} }{7 - 6} \\ \\ \frac{ \sqrt{7} + \sqrt{6} }{1} \\ \\ = \sqrt{7} + \sqrt{6}


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