This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 3. |
the two legs of a triangle are equal and the square of its hypotenuse is 50 find the length of each leg |
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Answer» LET the length of two legs be ' X ' and that of Hypotenuse be y. Applying Pythagoras Theorem we get, x² + x² = y² We know y² = 50 Substituting it in the above equation we get, x² + x² = 50 2x² = 50 x² = 50 / 2 = 25 => x = √ 25 = 5 units. Hence the length of each side other than hypotenuse is 5 units and that of hypotenuse is √ 50. |
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| 4. |
the hcf and lcm of two numbers are 12 and 72 respectively.if the sum of the two numbers is 60,then find the two numbers? |
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Answer» Then ANSWER is 6 and 12 RESPECTIVELY |
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| 5. |
Thoiba bought 150 toy guns for Rs 11250. He sold 30 of them at a gain of 8%. At what gain percent he sell the remaining so as to gain 12% on the whole? |
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Answer» 150 toys=11250 1 TOY= 11250/150=RS=7.5 he sold 30 toy=30×7.5=RS=51 remaining toys=150-30=120 he gain 12%on 120toys gain%=gain/CP×100 price if 120 toys=120×7.5=900 so, 8%=x/900×100 8%=x\9 9 GONE LHS so, 9×8=x then, x=72 |
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| 6. |
Answer for this:if a=2,b=3,find the value of (aᵇ+bᵃ)⁻¹ |
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Answer» 1/17 or 17^-1..is the ANSWER |
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| 7. |
(u^2)÷u where u is any negative integer |
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Answer» It is a BLUNDER question.the ANSWER will be U itself |
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| 8. |
Plzzzzzzzzz find it... |
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Answer» (x^2+x+1)(x^2-3x-1) +(6x+6) = x^4-3x^2+4x+5 |
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| 9. |
Find next 3 terms of AP: |
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Answer» HEY friend, _____________________________________________________________
Common DIFFERENCE (d) = 73 - 49 = 49 - 25 = 24 First term (a) = 1 5th term = a + (n-1)d = 1 + (5-1)*24 = 1 + 4*24 = 1 + 96 = 97 6th term = 1 + (6-1)*24 = 1 + 5*24 = 1 + 120 = 121 7th term = 1 + (7-1)*24 = 1 + 6*24 = 1 + 144 = 145 Next three terms of AP will be 1 , 25 , 49 , 73 , 97 , 121 , 145 ........ _____________________________________________________________ HOPE this helped you !! |
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| 10. |
the hcf and the lcm of two numbers are 50 and 300 respectively. if one of the numbers is 150. find the other one. |
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| 11. |
the cost of 5 kg of sugar and 7 kg of rice is rupees 153 and the cost of 7 kg of sugar and 5kg of rice is rupees 147 find the cost of 6 kg of sugar and 10 kg of rice |
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Answer» let 1 kg sugar be x , and 1 kg rice be y 5x+7y = 153 12 x + 12Y = 153 + 147 12x + 12y = 300 x + 12y = 300/12 x + 12 y = 25 x + y = 25/12 x+y = 2.5 price of 6 kg sugar and 10 kg rice = 2.5 * 6 * 10 = 150 |
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| 12. |
How to maintain family relationships though there are economic presures |
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Answer» By leaving in peace |
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| 14. |
Find the smallest number that must be added to 123 so that it become divisible by 5 |
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Answer» The smallest number is 2 because when we add 123 with 2 so we get 125 which is easily DIVISIBLE by 5 |
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| 15. |
Factorise8x³-y³-12x²y+6xy² |
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Answer» We will use the following IDENTITY, ➠ x³ - y³ - 3x²y + 3xy² = (X - y)³ Given, ➠ 8x³ - y³ - 12x²y + 6xy² ⇒ 2x³ - y³ - 3(2X)²(y) + 3(2x)(y)² ⇒(2x - y)³ ⇒(2x - y)(2x - y)(2x - y) -»-»-»-»-» -»-»-»-»-» ✪ Be BRAINLY ✪ |
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| 16. |
in the class of 40 students 30 speak hindi and 20 speak english. what is the lowest possible number of students who speak both the languages? |
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Answer» This QUESTION tests the concept of LCM. We will need to get the LCM of the THREE NUMBERS. That is: LCM of 40, 30,20 The LCM of these three is 120. 120 can divide 40,30 and 20. The least number of STUDENTS who speak all the languages is 120 |
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| 17. |
In how many ways can at least two team members be selected for grade a out of 7 members in a group |
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Answer» Any odd DEGREE polynomial with REAL coefficients has at least one real root. In what follows, I ..... OOPS - NICE answer to the wrong question. 1 .... So NECESSARY conditions are. |
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| 18. |
In an orchard there are 3293 mango trees 1367 apple trees and 2658 apricot trees. find the total number of trees in the orchard. |
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Answer» No of MANGO tree=3293 |
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| 19. |
1,2,3,5,4,5,9,14,13,14,27? explain plz |
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Answer» 2+3=8 -> 2*3+2 -> 2*3+2*1 -> 6+2 |
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| 20. |
21/4÷14/5×16/9= detail answer |
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Answer» 21/4÷14/5×16/9 |
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| 23. |
A number is 7 more than one third of itself |
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| 24. |
HOW TO DIVIDE 50.75÷2.5 BY PROCRSS plz ans |
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Answer» |
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| 25. |
The area of the equilateral triangle is 20√3 cm². Find the length of the side. |
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Answer» AREA of equilateral triangle = root3 a^2 / 4 => 20 root3 = root3 a^2 / 4 => 80 root3 / root3 = a^2 => a^2 = 80 => a = 5 × 16 => a = 4 ROOT5 Side of triangle = 4 root5 cm |
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| 26. |
Simplify (x2-11x-80) ➗ (16-x) |
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Answer» X^2-11x-80÷x-16 |
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| 27. |
Subtract 5xy+3yz-9x from 6xy-+8yz-20x |
| Answer» PLEASE MARK my ANSWER as BRAINLIEST. | |
| 28. |
Suggest some websites to read books online |
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Answer» 10 sites where you can read BOOKS online |
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| 30. |
I need to know the working as how we arrived at answer 17 for question that what should be added to 100056 to get number completely divisible by 23 |
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Answer» When we will divide 100056 by 23 then we will get quotient = 4350 and REMAINDER = 6 Now 4350 * 23 = 100050 So the NEXT number be completely divisible by 23 WOULD be 100073 but we have 100056 as our number, So 100073 - 100056 = 17 So we have 17 as the least number to be added to 100056 to make it completely divisible by 23 |
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| 31. |
U + 6 into U + 12 equal to |
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Answer» U(u+12)+6(u+12) u square+12u+6u+36 u square+18u+36=0 ...this will be UR AWNSER |
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| 34. |
How measure a reflex angle ? |
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Answer» Find its measure by first determining themeasure of the corresponding acute or obtuse ANGLE. Then SUBTRACT from 360 to find the difference. The difference is the measure of the REFLEX angle. |
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| 35. |
Question number 13 please fast |
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Answer» Hey friend ...here's your answer |
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| 36. |
Can I get answer of Q.3,6give Fast for Brainlest |
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Answer» (6)VALUE with negative POWER will reverse |
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| 37. |
Prove that..... my question |
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Answer» We KNOW that, |
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| 38. |
The average age of 50 pupils in a clss is 10.5.if the class teacher is included,the average increases by 5.then the age of the class teacher is |
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Answer» Solution: _______ Average age = 10.5 Sum of total age of the 50 students = 50 x 10.5 = 525 After including the teacher total strength = 51 new average = 10.5 + 0.5 = 11 sum of total age of all 51 = 51 x 11 = 561 the age of teacher = 561 - 525 = 36 So, the age of the teacher is 36 years Note: I have MADE a correction in the given question by taking numeral 5 as 0.5. _______________________________________ Any problem in understanding the solution, please feel fee to ASK in the COMMENT box. |
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| 39. |
Multiplicative inverse of 2raist ki power-4 |
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Answer» 1/2^4 |
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| 40. |
Pranav took a loan of $1800 with a rate of simple interest that was 3 times the time period in years. At the end of the time period, Pranav paid a total interest of $216. What was the time period and rate of interest per annum? |
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Answer» P = 1800$ T = 3R SI = (P*T*R)/100 216 = (1800*3R*R)/100 216 = 18 * 3R * R 216/18 = 3*R^2 12 = 3* R^2 4 = R^2 R = SQRT(4) R = 2% T = 3R T = 3*2 T = 6 YEARS Rate of interest per annum = 2% Time period = 6 years. |
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| 41. |
In a 20kg mixture of sprit and water there is 10 % water.how much water will be added so that quantity of water wil become 25% |
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| 42. |
In an angle is a parallelogram of 4/5 of its adjacent angle. then, find tge measure of all angle of a parallelogram |
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Answer» LET ONE ANGLE be x another angle 4/5x HENCE x+4/5x=180 x=100 another is 80 |
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| 43. |
Is there temperature which is numerically the same in both Fahrenheit and Celsius ?if yes, find it. |
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Answer» No,the TEMPERATURE DEGREE of F and C is not same |
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| 44. |
if a triangle ABC and triangle qrp and triangle ABC and q r p equal to 9 vitamin foods and BC equal to 5 cm then find the PR |
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Answer» GIVEN : Area of ∆ ABCArea of ∆QRP = 94 AB = 18 cm , BC = 15 cm So PR = ? We know when TWO triangles are similar then " The areas of two similar triangles are proportional to the squares of their corresponding sides. Area of ∆ ABCArea of ∆ QRP = AB2QR2 = BC2PR2 = AC2QP2 So , we take Area of ∆ ABCArea of ∆ QRP = BC2PR2 Now SUBSTITUTE all given values and get 94 = 152PR2 Taking square root on both hand side , we get 32 = 15PR PR = 10 cm |
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| 45. |
The product of two number is 432 and their lcm is 72. find their hcf |
| Answer» THEREFORE HCF is EQUAL to 6 | |
| 46. |
the difference between two whole no's is 66.the ratio of two no's is 2 is to 5 .what r the two numbers .explain clearly every step |
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Answer» Let the no. x and y |
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| 48. |
HOW TO GET GOOD MARKS IN SSLC EXAM |
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Answer» Pay attention in your classes and concentrate The BEST thing you can do to RAISE your test scores is to pay attention when you're supposed to be learning the material: in class! ... |
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| 49. |
Write two numbers which differ by 3 and whose product is 54 |
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Answer» Hii There!!! |
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| 50. |
Find the rate of discount being goven find the rate of discount begin given on a ceiling fan whose selling price rupees 1175 after alloying a discount of rupees 75 on its marked price |
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Answer» MP = 1250 SP = 1175 Discount = 75 |
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