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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 2. |
Class 10 maths solve it |
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Answer» Answer: AMOUNT RECEIVED by daughter = 48lacs Amount received by daughter = 48lacsAmount received by SON = 16lacs Step-by-step EXPLANATION: Total amount = Daughter's SHARE + Son's share
64 = 3/4*64 + 1/4*64 Daughter share = 48lacs Son share = 16lacs |
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| 3. |
Tick the set which has onemore than the otherobject1.Age2. |
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| 6. |
Which one of the following is not a quadratic equation?Options:1. (x+2)²=2(x+3)2.x²+3x = (-1) (1-3x)²3.(x+2) (x-1) = x²-2x-34. x³- x² + 2x+1=(x +1)³ |
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Answer» HEY MATE here is your ANSWER ⬇️ Answer:1.☑️
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| 7. |
Add 6 upon 7 and 4 upon 7 |
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Answer» 6/7+4/7. (DENOMINATORS are same so ADD NUMERATORS) =6+4/7 =10/7 |
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| 8. |
4. Given that HCF (306,657)=9, find LCM (306, 657).5. Check whether 6" can end with the digit 0 for any natural number n. |
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Answer» Step-by-step explanation: GIVEN that HCF = 9 and the numbers are 306 and 657 LCM = ? We know that LCM × HCF = PRODUCT of two numbers ⇒LCM × 9 = 306 × 657 ⇒LCM = 201042/9 = 22338 . |
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| 9. |
If theta tan and tan theta is the geometric mean between sin theta and cos theta , then prove that, 2-4 sin^2 theta +3 sin^4 theta -sin^6 theta equals to 1 |
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| 10. |
एक catcher है वह 3 minute मे 36 catch पकड़ता है. वह हर 4 minute के बाद 3 minute का break लेता है तो वह 15 minute कितने catch पकड़े गा!!! |
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Answer» Answer: 180 catches. Step-by-step explanation: 1 min = 12 catch. 15 min = 12 ×15 = 180 catches. plzzz FOLLOW me... thnxx |
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| 13. |
If mx^2 < nx such that m and n have opposite signs then x can be (m being positive)(a) x > n/m(b) x < n/m(c)n/ m < x < 0(d) None of these |
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| 14. |
Consider the equation of the form ax + pax+ q = r where all a, p,q,r are natural numbers greater than 1 . This equation can be solved for x by using the following procedure Step 1Take ax common from LHS then we get ax(1 + paq) =r Step 2 ax = r/ (1+ paq)Step 3 guess x from the value of axQ.1 solve 2x + 3(2x+4 ) = 196 for the value of x using the procedure given above . find x and show your calculation .Q.2 solve 2(3x+2) + 3x = 513 for the value of x using the procedure given above . find x and show your calculation . |
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Answer» Answer: Eliminating z form the 1ST and 2nd equation and from the 2nd and the 3rd equation we get 5x+4y=11p−3qand5x+4y= 5 7q+11r
At LEAST one SOLUTION MEANS we can have infinite solution Applying the conditions of infinite solutions we get 11p−3q= 5 7q+11r
⇒5p−2q−r=0 mark it as branlist..FOLLOW me pls.. |
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| 16. |
Help me in this question isme value nikalni hai a cube plus➕ b cube ki Thanks❤❤❤❤❤ |
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Answer» Hey mate! the answer to your QUESTION is 540. hope it helps mark as BRAINLIEST. THANK you. |
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| 17. |
Suppose that m and n are two independent works .If ways to do a work m is x and number of ways to do a work n is y then number of ways in which both work (m and n ) can be done is xy .x={2,3,4,5,6,7,8,9}y={0,1}z={0,1,2,3,4,5,6,7,8,9}Before 1990, telephone area codes in the United States were three-digit numbers of the form xyz. Shown above are sets X, Y, and Z from which the digits x, y, and z, respectively, were chosen.Q.1 how many possible area codes were there ?Q.2 how many such area codes are possible which have two same digits ( repetitive digit ) |
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Answer» Answer: Suppose that m and n are two independent WORKS . If WAYS to do a work m is x and number of ways to do a work n is y then number of ways in which both work (m and n ) can be done is xy . x={2,3,4,5,6,7,8,9} y={0,1} z={0,1,2,3,4,5,6,7,8,9} Before 1990, telephone AREA codes in the United States were three-digit NUMBERS of the form xyz. SHOWN above are sets X, Y, and Z from which the digits x, y, and z, respectively, were chosen. Q.1 how many possible area codes were there ? Q.2 how many such area codes are possible which have two same digits ( repetitive digit ) |
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| 18. |
for every 2 girls in a class there are 3 boys what is the ratio of boys to girls in the class give your answer in the simplest form |
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Answer» Answer:3:2 Step-by-step EXPLANATION: |
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| 19. |
If r is the ratio of the roots of the equation ax²+bx+c=0,show that (r+1)²ac=b²r. |
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Answer» Step-by-step EXPLANATION:
let one root = p => another root = rp sum of roots => p+rp = -b/a => p(r+1) = -b/a => p² = b² /(r+1)²a²..............(1) product of roots => p×rp = c/a => p² = c / RA.........................(2) from (1) and (2) c/ra = b²/(r+1)²a² => c/r = b²/(r+1)²a => ac(r+1)²= b²r => (r+1)²ac = b²r Proved hope this helps you |
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| 20. |
A discount of 10% was given. If a further discount of 10% was given on the reduced percalculate the total single discount given on the marked price.The marked price of an article is Rs 1600. If it is sold for Rs 1472 what is the |
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Answer» Answer: 100. Now, a 10% discount is given on the market price and this will be our SELLING price. So, selling price = 1200 – 10% of 1200 => 1200 – 120 => RS. 1080. Step-by-step explanation: |
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| 21. |
The horizontal cross section of cylinder is |
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Answer» Answer: The cross-sectional area of a CYLINDER is equal to the area of a CIRCLE if cut parallel to the circular base. The cross-sectional area is the area of a two-dimensional shape that is obtained when a three-dimensional object - such as a cylinder - is sliced perpendicular to some specified axis at a point. Step-by-step EXPLANATION: The Cross SECTION of an object is the shape you get when you cut straight through an object. It can be a rectangle, a circle even an oval, depending on how it has been cut. Thus the cross section of the above cylinder is a circle. Hence the cross sectional area is the area of a circle. Area of a circle = π x R2 R= radius Thus the cross section of the above cylinder is a rectangle, hence calculate the area of a rectangle. Area of a rectangle= length*width Thus the cross section of the above cylinder is an oval, hence calculate the area of the oval. Area of an oval= π*short radius*long radius Using the figure below as an example, the short radius is a the long radius is b thus the area is = π*a*b So what will GUIDE you is how it has been cut. Good Day. MARK AS BRAINLIEST... :) |
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| 22. |
A flock of 12 birds sat over the branch of the tree.No more birds joined them. How many birds are sitting on the branch of the tree? |
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Answer» Answer: |
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| 23. |
If the area and the breadth of a rectangle are 31.25 cm2 and 0.025 m. Find the lengthof rectangle in cms |
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Answer» __________________________________ |
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| 24. |
If one zero of the quadratic polynomial (k-1)x²+kx+1 is -4, then the value of k is(lockdown offer) |
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Answer» Answer: Step-by-step explanation: p(X)=(k-1)x²+ KX +1 and -4 is a zero than if we put x=-4 we can GET the VALUE of k. p(-4)=(k-1)(-4)² + k × (-4) + 1 = 0 16×(k-1) - 4k +1 =0 16k - 16 - 4k + 1 =0 12k -15 =0 12k = 15 k=15/12 k=5/4 hence, this is your answer. |
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| 25. |
In a mathematics examination sum of marks secured by two students radhika and anuradha is 76, and radhika 8 marks more than that of anuradha secured. Write suitable pair of linear equations for this information |
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Answer» let the marks secured by Anuradha be X let the marks secured by RADHIKA be X+8 according to the QUESTION, The sum of their marks: X+(X+8)=76 X+X+8=76 2X=68 X=34 therefore,marks of Anuradha is 34 and marks of radhika is (34+8) 48 |
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| 26. |
2. If y,z are the roots of the equation ax^2+bx+c = 0, then form an equation whose rootsare :y/z,z/y |
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Answer» hvieh,ouojfojfo jdorjdojojedobkhdih kjrixjojx its JX jepjxorux usoxnorkxjofhxojxorjpcjtpckpy yjocjltjclt knxodhojcorkvuv ojkho |
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| 27. |
A chord of a circle of radius 6cm is making an angle 60 at the centre, find the length of the chord |
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Answer» Answer: 6 cm Step-by-step explanation: We KNOW that the angle subtended by the Chief at the centre is 60 degrees. So, from there we get to know that the triangle FORMED by the centre and the chord is an equilateral triangle. We know that, all the sides of a triangle are equal in equilateral triangle, therefore the LENGTH of the chord will be equal to the radius. We know that the length of the radius is 6 cm, therefore the length of the chord is ALSO 6 cm. Plss do mark me as the BRAINLIEST!!! |
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| 28. |
Solve for phi is son phi by 1 plus cos phi |
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Answer» Step-by-step EXPLANATION: sinπ/1+cosπ =sin180/1+cos 180 =0/1-1=0/0= not DEFINED |
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| 29. |
If f(x)= (x-1) (x-2) (x-3)..........(x-100) so find f(0)? |
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Answer» Answer: 5050 Step-by-step EXPLANATION: f(X)= (x-1) (x-2) (x-3)..........(x-100) f(0)= (-1) (-2) (-3)..........(-100) f(0) = 100(100+1)/2 f(0) = 50*101 = 5050 |
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| 30. |
Log(x-2)²=2-log(x+1)² |
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Answer» Answer: x=0 Step-by-step explanation: 2 log (x-2) = 2 ( 1- log (x+2) ) log (x-2) = 1 - log ( x+2) log ( x-2) + log ( x+2) =1 log {( x-2) (x+2)} = 1 log {(x^2) (2^2)}=1 log { (x^2)4} =1 log { (x^2)4} = log 0 x^2= 0÷4 x^2= 0 x=0 |
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| 31. |
Cross multiplication method to solve. 1.5x+0.1y=6.2. 3x+0.4y=11.2 |
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Answer» nothffurkrkr776or7r677lrrp6t7f67o6t |
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| 32. |
Multiplicative inverse of 5/14 |
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Answer» Given: A fraction 5/ 14. To Find: The multiplicative inverse of the given fraction. Solution: - We KNOW that multiplicative inverse is the no upon multiplication with which a no gives answer 1. - So LET US assume that the multiplicative inverse of 5/ 14 is x. ⇒ 5/ 14 × x = 1 ⇒ x = 14 /5 × 1 ⇒ x = 14 /5 - So, the multiplicative inverse of 5/ 14 is 14 /5. |
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| 33. |
A school of Kolkata has a section of underprivileged students in each class starting from class 5. The school helps the students with school uniform and books of English, Mathematics and Science. Three sets of books of English, Mathematics and Science containing 336, 240 and 96 books respectively have to be stacked in such a way that all the books are stored subject wise and the height of each stack is same. How many stacks will be there and write the moral value derived from it. |
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Answer» A school of Kolkata has a section of underprivileged students in each class starting from class 5. The school HELPS the students with school uniform and books of English, Mathematics and Science. THREE sets of books of English, Mathematics and Science containing 336, 240 and 96 books respectively have to be stacked in such a way that all the books are STORED subject wise and the height of each stack is same. How many stacks will be there and write the moral value derived from it. |
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| 34. |
Which of the following statements about a plane is not true?A. A plane can be thought of as flat.B. The surface of a plane is made up of points.C. A plane can be seen.D. A plane extends infinitely in all directions. |
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Answer» a PLANE EXTENDS INFINITELY in all DIRECTIONS |
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| 35. |
Solve. 20*22. Using property of square root |
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Answer» Answer: 11 Step-by-step explanation: 1sd |
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| 36. |
Right answer only please |
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Answer» Answer: yrr divide kro na ISKE liye bhi HMI log h kya .... ye tumhara learning TIME h so try kro na baane to tareeka PUCHO seedhe WITHOUT process answer mt maango...... follow me ♥️ |
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| 37. |
What is ladder method in factors |
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Answer» Answer: The greatest common factor (GCF) is the largest number that DIVIDES evenly into all of the NUMBERS you're COMPARING. It's EASY to find the GCF using the ladder method because all you have to do is look at the factors of each number on the LEFT side of the ladder and multiply them. |
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| 38. |
in triangle abc D and e are points on the sides ab and ac respectively such that the parallel to BC if AD/DB=3/4 & the AC = 15 cm find AE |
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Answer» Answer: 6 Cm Step-by-step explanation: PointS P and C2 LIE On SIDE AB and AC of TRIANGLE ABC respectively Such that ... If S divides PQ in the ratio 1 : 5 and length OfQR is 15 cm, FIND ST? ... AD interSectS BC in E. If lengthS Of AE, BC and ED are 18 Cm, 13.6 Cm and 6 Cm, ... |
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| 39. |
2(1+tanA) cot A11.=tan A2cosec- A plzz do it quickly ok hmmm |
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Answer» sorryyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyttttttffwjshduehsjehrudejdjrndurbdidjdiidejjeodjrjdjdudueueusjejdjeisiejejejeuejeusududududueudie8eiririrididuduududududjdjjdrjjdjdjdejdjjrjrjejdjehrejejjejerjejenrmdjrjxndjdjd7euuuuuuuujueeesddsdrdjjjjjjjjjhhddddedddehhhhhhsjejdidududididueudjdjsjdjdjdjdjsjdjdjd Step-by-step EXPLANATION: jdjdjdjhs |
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| 40. |
Plz solve this who knows the ans by showing steps.And dont spam plz |
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Answer» i-4+4=8 ii 9-3=6 mark me as BRAINLIEST |
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| 41. |
the product of two numbers is 1440.if one number is 24,find the other...sum of the numbers and difference of the numbers |
Answer» ANSWER:1440÷24 = 60 ANS Mark as brainlist please..... |
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| 42. |
@).let 2+92-3399-doacon frombe the Cevation of Parrotlangentsoriginto the de ofradice 3-units with its center in the firstQuadrad. Ifone the point of contact (Pec)theisOA is - ?9-22 |
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| 43. |
Priyanka has a recurring deposit account of Rs 1000 per month at 10% per annum . If she gets Rs 5550 as interest at the time of maturity find the total time for which the account is held? |
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Answer» Answer: Step-by-step explanation: Let the MATURITY PERIOD be n months, P be the money DEPOSITED every month which is Rs.1000 and r be the rate of interest per annum which is 10%. Now, the interest I received at the END of maturity is calculated by the FOLLOWING formula: I=P× 24 n(n+1) × 100 r
We are given I=5500, so substituting the values, we get ⇒5550=1000× 24 n(n+1) × 100 10
⇒n(n+1)= 100 5550×24 =1332 ⇒n 2 +n−1332=0 ⇒n 2 +37n−36n−1332=0 ⇒(n−36)(n+37)=0 ⇒n=36, −37 Since the maturity period cannot be negative, n=36. Therefore, the total time for which the account was held was 36 months which is the same as 3 years. So the maturity period was 3 years.Let the maturity period be n months, P be the money deposited every month which is Rs.1000 and r be the rate of interest per annum which is 10%. Now, the interest I received at the end of maturity is calculated by the following formula: I=P× 24 n(n+1) × 100 r
We are given I=5500, so substituting the values, we get ⇒5550=1000× 24 n(n+1) × 100 10
⇒n(n+1)= 100 5550×24 =1332 ⇒n 2 +n−1332=0 ⇒n 2 +37n−36n−1332=0 ⇒(n−36)(n+37)=0 ⇒n=36, −37 Since the maturity period cannot be negative, n=36. Therefore, the total time for which the account was held was 36 months which is the same as 3 years. So the maturity period was 3 years. |
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| 45. |
If one zero of the quadratic polynomial ƒ(x) = 0x^2−8kx − 9 is negative of the other, find the value of k. |
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Answer» Answer: it is LINEAR equation. |
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| 46. |
GUYS THIS IS A FILL UP : 1.The __________of any integer (-a)is a. 2.For any three integer a,b and c (axb)xc=__________ |
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Answer» Answer: 1. ABSOLUTE value 2. ABC |
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| 47. |
Anil borrowed * 18000 from Rakesh at 8% per annum simple interest for 2years. IfAnil had borrowed this sum at 8% per annum compound interest, what extra amountwould he has to pay? |
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Answer» Answer: In simple interest - ANNUM–18000 Interest –8% Time–2 years Thus the interest he have to pay – 18000×8\100×2= 2880(only interest) 18000+2880=20880(with interest for 2 years)
In compound interest - In the same VALUES . In 1ST YEAR – 18000×8\100=1440(only interest) 18000+1440=19440(Interest with annum) In 2nd year- 19440×8\100=1555.2 (only interest) 19440+1555.2=20995.2(with total money of 1st year) He have to pay more in compound interest by –20995.2–20880=115.2 |
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| 48. |
Find the simple interset on rs 1000 for 10 years at a rate of 2% per annum |
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Answer» Answer: Formula for SI= PRT/100 Principal= 1000 Rate of INTEREST= 2% TIME= 10 years = 1000×2×10/100 = 10×2×10 (after CUTTING the zeroes) =20×10 = 200 The SI= 200 Rs #STAYHOME STAYSAFE HOPE IT HELPS YOU. PLEASE MARK MY ANSWER AS BRAINLIEST. |
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| 49. |
80:400::100:?a).800 b).625c).625 d).650Please answer this question of Analogy. No useless answers. Best answer will be marked as brainliest. |
Answer» Qᴜᴇsᴛɪᴏɴ :-80:400::100: ? a).800 b).625 c).625 d).650 ᴄᴏɴᴄᴇᴘᴛ ᴜsᴇᴅ :-
Sᴏʟᴜᴛɪᴏɴ :-Logic :- (Divide by 4)² CHECKING First :- Divide by 4 First, → 80 ÷ 4 → 20 Square Now, → (20)² → 400 . So, we will Do same in Next . Divide by 4 First, → 100 ÷ 4 → 25 Square Now, → (25)² → 625 . (Ans.) (Option B).Hence, Correct Answer is 625. |
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| 50. |
Solve ...........quick......... pavitrha......... |
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Answer» Step-by-step EXPLANATION: |
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