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Log(x-2)²=2-log(x+1)² |
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Answer» Answer: x=0 Step-by-step explanation: 2 log (x-2) = 2 ( 1- log (x+2) ) log (x-2) = 1 - log ( x+2) log ( x-2) + log ( x+2) =1 log {( x-2) (x+2)} = 1 log {(x^2) (2^2)}=1 log { (x^2)4} =1 log { (x^2)4} = log 0 x^2= 0÷4 x^2= 0 x=0 |
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