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If r is the ratio of the roots of the equation ax²+bx+c=0,show that (r+1)²ac=b²r. |
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Answer» Step-by-step EXPLANATION:
let one root = p => another root = rp sum of roots => p+rp = -b/a => p(r+1) = -b/a => p² = b² /(r+1)²a²..............(1) product of roots => p×rp = c/a => p² = c / RA.........................(2) from (1) and (2) c/ra = b²/(r+1)²a² => c/r = b²/(r+1)²a => ac(r+1)²= b²r => (r+1)²ac = b²r Proved hope this helps you |
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