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If one zero of the quadratic polynomial (k-1)x²+kx+1 is -4, then the value of k is(lockdown offer)​

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Answer:

Step-by-step explanation:

p(X)=(k-1)x²+ KX +1 and -4 is a zero than if we put x=-4 we can GET the VALUE of k.

p(-4)=(k-1)(-4)² + k × (-4) + 1 = 0

         16×(k-1) - 4k +1 =0

          16k - 16 - 4k + 1 =0

         12k -15 =0

          12k = 15

           k=15/12

k=5/4

hence, this is your answer.



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