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If one zero of the quadratic polynomial (k-1)x²+kx+1 is -4, then the value of k is(lockdown offer) |
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Answer» Answer: Step-by-step explanation: p(X)=(k-1)x²+ KX +1 and -4 is a zero than if we put x=-4 we can GET the VALUE of k. p(-4)=(k-1)(-4)² + k × (-4) + 1 = 0 16×(k-1) - 4k +1 =0 16k - 16 - 4k + 1 =0 12k -15 =0 12k = 15 k=15/12 k=5/4 hence, this is your answer. |
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