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4. Given that HCF (306,657)=9, find LCM (306, 657).5. Check whether 6" can end with the digit 0 for any natural number n. |
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Answer» Step-by-step explanation: GIVEN that HCF = 9 and the numbers are 306 and 657 LCM = ? We know that LCM × HCF = PRODUCT of two numbers ⇒LCM × 9 = 306 × 657 ⇒LCM = 201042/9 = 22338 . |
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