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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
(6) Solve the equation:\frac{\log _{e} a}{\log _{e} 8}=\frac{\log _{e}(256)}{\log _{e}(64)} |
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| 2. |
A e8 |
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Answer» In the figure , ∠ABC = 65°∠BCD = 32° + 33° = 65° ∴ ∠ABC = ∠BCD [Alternate Interior angles ]∴ AB || CD ................................ (1) ∠ CEF = 148°∠ DCE = 32°∠ CEF + ∠ DCE = 180°148° + 32° = 180° [ Interior angles on the same side of the transversal ] ∴ CD || EF ........................................(2) From (1) and (2) , AB || EF thanks |
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| 3. |
How long will an express train travelling at 50 km/h take to cover a distance of 5 km between twostations?7. |
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Answer» Time = distance / speed=> time = 5 / 50 = 1/10 hours=> time = 6 minutes |
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| 4. |
Express the following in standard form:1) A Helium atom has a diameter of 0.0000 00 022 cm. |
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Answer» Atomic radius is expressed in Angstrom. So, diameter= 220 ÅPlease hit the like button if this helped you |
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| 5. |
Write two solutions of equation 4x-5=15 |
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Answer» it is a linear equation the solution will be x=5 4x - 5 = 15 4x = 15 + 5 = 20 x = 5 how |
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| 6. |
-(-m %2B 1)*(n - 1) %2B (-m %2B 1)*(m - n) %2B (m - n)*(n - 1) |
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| 7. |
570*15%=? |
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Answer» 570 × 15% = 570 × 15/100 = 57×15 / 10 = 57×3/2 = 171/2 = 85.5 |
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| 8. |
a^((2*n - 1)*(2*n %2B 1))*a^(2*n %2B 1) |
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| 9. |
Evaluate ((e+7x-5)dx as a limit of sums. |
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| 10. |
4. Why was the Emperor angry? |
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Answer» The emperor requests that Gulliver go back to the enemy's shores and do his best to destroy what is left, turning the empire into a province. Gulliver thinks that this action is going too far and declines the request. |
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| 11. |
570*15% |
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Answer» 570 × 15% = 570 × 15/100 = 57×15 / 10 = 57×3/2 = 171/2 = 85.5 |
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| 12. |
write any two solutions of equationre-y=8 |
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Answer» x=y+8if we take y=0then, the value of x=8and, we take y=5then, the value of x=13 x-y=81st equation is x=8+y2bd equation is -y=8-x => -y=-(x-8) =>y=x-8 |
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| 13. |
cos2 570 + cos233° = 1 |
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Answer» cos²57 = sin²(90-57)= sin² 33.cos²57+cos²33= sin²33+cos²33= 1. Please hit the like button if this helped you |
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| 14. |
570+29 \% \text { an } 1400 |
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Answer» 486.7(31percent of 1570)+406(29%of 1400)892.7 |
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| 15. |
AD, BE andIn right angled DABC, SA= 90CF are medians then prove thatDO SAD? +BE²4 CE ) = 3 Botolese me |
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| 16. |
(27+ 570)e8 |
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| 17. |
A train runs at the speed of 80 km/hour. Find the distance covered by train inhours?17. |
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Answer» Speed = 80 km/h Distance covered in 5 hrs = 80×5 = 400 km If you find this answer helpful then like it. when 1 hour = 80 km/h 5 hours = ? 1 hour = 80 km 8 hour = 80 × 5 8 hour = 400 km/h |
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| 18. |
Distance covered by a train travelling at a speed of 15 m/sec, in 3 hrs. |
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Answer» 3hr=3×60×60=10800secdistance=10800×15=162000m=162km |
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| 19. |
If the speed of a train is 140 km/hr, find the distance covered in 41 hours. |
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Answer» 650km is the correct answer the correct answer is 650km 650km is the correct answer 650 is the correct answer Speed = 140 km/hrTime 4&1/2 hr = 9/2 hrDistance = speed × time = 140 × 9/2 = 70 × 9 = 630 km 650km is the best answer |
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| 20. |
a _ { 1 } = a _ { 2 } = 1 , a _ { n } = 2 a _ { n - 1 } + 3 a _ { n - 2 } , n > 2 |
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| 21. |
1 ^ { 2 } + 2 ^ { 2 } + 3 ^ { 2 } + \ldots + n ^ { 2 } = \frac { n ( n + 1 ) ( 2 n + 1 ) } { 6 } |
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Answer» not true proving of mathematical induction |
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| 22. |
1 ^ { 2 } + 2 ^ { 2 } + 3 ^ { 2 } + \ldots + n ^ { 2 } > \frac { n ^ { 3 } } { 3 } \text { for all } n \in N |
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| 23. |
((2^n*2^(2*n))*(2^(n %2B 1))^m)/((2^(2*m)*(2^(m %2B 1))^n))=1 |
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| 24. |
1 ^ { 3 } + 3 ^ { 3 } + 5 ^ { 3 } + ...... to n terms = n ^ { 2 } ( 2 n ^ { 2 } - 1 ) |
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| 25. |
कि 3-50) (- 690 |
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Answer» ( 3 - 5a) ( -6bc) 3 × (-6bc) - 5a × (-6bc) -15bc + 30 abc but here we have to take a=2,b=0.5 and c=0.1 |
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| 26. |
50.Mughal emperor Akbar divided his empire into(A) Eight provinces(B) Five provinces(C) Twelve provinces(D) Ten provinces |
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Answer» Emperor Akbar divided his empire into 12 provinces. Please hit the like button if this helped you |
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| 27. |
\left. \begin{array} { l } { \text { If } a \operatorname { cos } ^ { 3 } \theta + 3 a \operatorname { cos } \theta \operatorname { sin } ^ { 2 } \theta = m , a \operatorname { sin } ^ { 3 } \theta + 3 a \operatorname { cos } ^ { 2 } \theta \operatorname { sin } \theta = n } \\ { ( m + n ) ^ { 2 / 3 } + ( m - n ) ^ { 2 / 3 } = 2 a ^ { 2 / 3 } } \end{array} \right. |
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| 28. |
Find the SP when:23950, gain690(ii) CP=て9600, gain= 16(i)CP1540, loss = 4%(3) CP =き8640, loss-12riii) CP = |
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Answer» yes |
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| 29. |
C.P. when (i) S.P. = Rs 530, gain = 6%ii) SP. = Rs 690, Loss = 2 %.Find(2 |
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Answer» SP = (100 + Gain%)/100 * C.P.530 = 100 + 6/100 * C.P.924 = 106/100 * C.PC.P = 924 * 100/106C.P = 871. 69. |
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| 30. |
\operatorname { sin } 600 ^ { \circ } \operatorname { tan } ( - 690 ^ { \circ } ) + \operatorname { sec } 840 ^ { \circ } \operatorname { cot } ( - 945 ^ { \circ } ) = \frac { 3 } { 2 } |
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| 31. |
. ForSandeep sold a television at a loss of 8%. If hehow much did Sandeep buy it?had sold it for3360 more, he would have gained 690: |
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| 32. |
1 ^ { 2 } + 2 ^ { 2 } + 3 ^ { 2 } + 4 ^ { 2 } + \ldots + n ^ { 2 } = \frac { n ( n + 1 ) ( 2 n + 1 ) } { 6 } |
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| 33. |
what is the value of tan(-570°) |
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| 34. |
Write two solutions for the equation αy + x = 5. |
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Answer» y= 0 , x = 5y= 1/ , x = 4 |
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| 35. |
cp=450 and sp=570 ,then what will be profit? |
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Answer» profit = sp- cp = 570-450 = 120 is the correct answer 120 is right answer plz like my comment 120 is the right ans of the following profit= sp-cp=570-450=120 is the correct answer profit= sp- cp=570-450=120 is the correct answer profit=sp-cp = 570-450 =120 is correct answer. 120 answer. give like Profit=sp-cp=570-450=120 Answer✓ |
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| 36. |
)The value of sin 570 will be:IV)n22 |
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Answer» Sin570° =sin(360+210)° =sin210° =sin(180+30)° =-sin30° =-1/2 Like my answer if you find it useful! |
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| 37. |
Find the value ofk, ifr-2,y= l is a solution of the equation 2x + 3y-k |
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| 38. |
v)Some pat of a journey of 780 km was made by car willof 60 km/h and the remaining journey was made by train with aspeed of 100 km/. If total time required was 9 hours, find thetime taken by train ad distance covered by train. |
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Answer» speed × time = distancetime = distance/speed total distance = 780let distance covered by car with speed 60km = X speed of car while covering xkm distance= 60km time = 780km/60km = 13km distance covered= 13km×60km= 780 |
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| 39. |
8. What will come in place of questionmark in the following number series?8, 27, 125, ?, 1331 |
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Answer» 8 = 2³ 27 = 3³ 125 = 5³ 7³ = 343 11³= 1331 ? = 343 The sequence is cube of prime number |
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| 40. |
Illustration 6.4 Find the least value ofk for which the functionr+kx+ 1 is an increasing function in the interval 1 <x<2(NCERT) |
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Answer» f(x) = x^2+ kx + 1 f'(x) = 2x + k >= 0 if f(x) is increasing Or, k>= -2x Now x ε (1,2) thus, k>= -2 |
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| 41. |
Prove that the function f:N-N, by f(x)= XNN, by f(x) = x2+x+1 is one-one function but not onto. |
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| 42. |
Question 8(4.0 marks)If t8, then find the value of tuestion (0 |
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Answer» If you find this solution helpful, Please give it a 👍 |
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| 43. |
Question8.tan x =--, where x is in second quadrant.3 |
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Answer» since tanx = -4/3. is in the second quardrant => cotx = -3/4 so , sinx will be positive = 4/√4²+3² = 4/5 => cosecx = 5/4 and cosx will be negative = -3/5 => secx = -5/3 |
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| 44. |
Divide 12 into 2 parts such that sum of there squares is maximum |
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Answer» Let x = one of the numbersThen the other number = 12 - xSum of the squares is 74:x^2 + (12-x)^2 = 74Solve for x:x^2 + 144 - 24x + x^2 = 742x^2 - 24x + 70 = 0x^2 - 12x + 35 = 0Factor:(x-7)(x-5) = 0So the numbers are 5 and 7 |
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| 45. |
sa maximum.Find two positive numbers whose sum is 16 and the sum of whose cubes isinimumto he made into a box without top, by |
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| 46. |
Find the value of the sum-9x + (25) is equal to -e. 16xThe maximum stress the material can have been |
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Answer» 16x is the answer of the following |
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| 47. |
946 ka 32℅ |
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Answer» 946×32/100 = 302.72 |
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| 48. |
threetimesasodriethMohita's mother is four times as old as Mohita. After five years, her mother will beA Rishika is twice as old as Divya. If six years is subtracted from Divya's age and four years added11. The sum of the present ages of Sáurabh and Piyush is 60 years If the ratio of their present ages be12. in a party of 41 people, the number of women is 7 more than men. How many women are there inold as she will be then. What are their present ages?to Ríshika's age, then Rishika will be four times Divya's age. How old were they two years ago ?78, find their present ages. -the party?ˊ哭 |
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Answer» 12. w=m+7abdw+m=41m+7+m=412m=41-72m=34m=17 w=17+7=24 |
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| 49. |
. Find two numbers whose sum is 15 and the squarc of one muitiand the square of one multiplied by the cube ofother is maximum. |
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| 50. |
AP 10,7,4, 30 TH ELEMENT |
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Answer» thanks |
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