1 ^ { 2 } + 2 ^ { 2 } + 3 ^ { 2 } + \ldots + n ^ { 2 } > \frac { n ^ { – InterviewSolution

1.	1 ^ { 2 } + 2 ^ { 2 } + 3 ^ { 2 } + \ldots + n ^ { 2 } > \frac { n ^ { 3 } } { 3 } \text { for all } n \in N
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