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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
write the standard form of quadratic equation. |
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Answer» Standard form is ax^2+bx+c= 0where a >0 |
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| 2. |
Find the surface area of each the following figure |
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| 3. |
10. A can do a certain work in 1s 2of the same work in 3 days, ita how3many days can both finish the work, working together?16 days and B can do411. A, B and C can |
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| 4. |
57 and the19. Mariam bought two fans for Rs 3605. She sold one avaBe 3605. She sold one at a profit of 15%loss of 9%. If Mariam obtained the same amount for each fan, find thfan.and the cost price |
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Answer» cost of two fan = 3605 profit = 15%loss = 9% so,cost of one fan=3605 ÷ 2 =1802.5 answer |
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| 5. |
9. What is the maximum length of a pencil that can be kept in a rectangular box of dimensions 8 cmx 6 cm x 2 cm? |
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| 6. |
Find the cost of painting the outside surface of asolid cylinder of diameter 7 m and height 25 m at4.8 per square metre. |
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| 7. |
A borrowed amount of 4000 amounts to 5400 in 5 years. How much will 5600 amount in 3 years at the same rate? |
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| 8. |
From the following figure; prove that(i) AB >BD(ii) AC > CD(ii) AB + AC > BC |
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Answer» We know that the side opposite to the largest angle is largest size in the triangle.. so, in ∆ADB , angle ADB =90 , means AB Is largest of all sides so, AB > BD also in ∆ADC , angle ADC =90 , means AC Is largest of all sides so, AC > CD now adding both we get AB+AC > BD+CD => AB + AC > BC. |
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| 9. |
3. The area of a rectangular plot is 880 m and its length is 44 m. Finda its perimeterb. the cost of fencing it at the rate of t 5 pe |
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Answer» Area = Length×breadth880=44 ×b b=20m a) Perimeter=2(l+b)=2(44+20)=2(64) =128 mb) Cost = 128×5 = 640 rs |
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| 10. |
x 6 cm x 2 cm?How many litres of water can a square container of side 20 cm and height 18 cm hold?0.ti 3 .1 1f its olumgi 1296 m find its hreadth |
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| 11. |
2Work 3.3 outin the blanks.900-0-5600-5600 =b. 2396 1d. 3940-10f. 37300- 1000-e. 16810-100=q. 21730- 10h a34i. 7000 - 1000-i. 42790-0- |
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Answer» 1000-0=10005600-5600=016810-100=1680021730-10=217207000-1000=60002396-1=239537300-1000=363009310-1=930942790-0=42790 10000158102172060002395303036300931942790 |
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| 12. |
il. The innmer diameter of a circular well is 3.5 m. It is 10 m deep. Find the cost ofhr dur o sink a well 225 m deep andplastering its inner curved surface at t 4 per square metre |
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| 13. |
Section-CFE ECA.BF BEIn figure DEll AC and DFIIAE. Prove that FE=EC |
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Answer» thanks |
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| 14. |
9. In 4 years, 6,000 amounts to8,000. In what time willて525 amount to 700 atthe same rate ? : 1 |
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| 15. |
in what time will rupees 5600 amounts to 6720 at 8% per annum |
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Answer» thanks Bhaiya |
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| 16. |
A shopkeeper sold an article at gain 5%.if he had sold it for 16.50 less ,he would have lost 5%.Find the cost price of the article |
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| 17. |
1-- In what time will15625 amount to17576 at 4% per annuum compound interest?2-16000 invested at 10% pa. compounded semi-annually amounts to18522, Find thetime period of the investment. |
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Answer» Principal=p=Rs15625Amount =A=Rs17576r=4%time =n p[(100+r)/100]^n=A[(100+4)/100]^n=17576/15625(104/100)^4=(26/25)^3(26/25)^n=(26/26)^3thereforen=3 |
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| 18. |
16000riod of the investment.invested at 10% pa. compounded semi-annually amounts toDur aholl eompound interest?19. 1600018522, Find the time |
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Answer» Principal (P) = Rs. 16000 Rate of interest = 10 % ⇒10/2 = 5 % compounded semi annually Amount (A) = Rs. 18522 Let the number of six monthly period be 'n' A = P(1 + R/100)ⁿ ⇒ 18522 = 16000(1 + 10/100)ⁿ ⇒ 18522/16000 = [(20 + 1)/20]ⁿ ⇒ 9261/8000 = (21/20)ⁿ ⇒ (21*21*21)/(20*20*20) = (21/20)ⁿ ⇒ (21/20)³ = (21/20)ⁿ ⇒ n = 3 Three periods of 6 months = 1 1/2 years. Like my answer if you find it useful! |
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| 19. |
7. Abatsman scored 75 runs which included 3 boundaries and 8 sixes. What per cent of his totalscore did he make by running between the wickets?8-12% of a sum of money is? 42. What is 20% of the same sum?/64 % ofa weight is 0.25 kg. What is 45% of this weight?ogont m |
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| 20. |
sin (x+a) ÷ cosx |
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Answer» PLEASE LIKE THE SOLUTION |
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| 21. |
9.If 5 fishermen can catch 5 fish in 5 minutes,how long will it take for 50 fishermen tocatch 50 fish at the same rate? |
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Answer» 50 minutes because 1 fisherman catch 1 fish in 1 minute |
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| 22. |
(sin)cosx |
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Answer» Letu=cos(x)⇒du/dx=−sin(x) Lety=sin(u)⇒dy/du=cos(u) Butdy/du×du/dx = du/du×dy/dx = 1×dy/dx = dy/dx ⇒dy/dx=−sin(x)cos(u) butu=cos(x)giving: ⇒dy/dx=−sin(x)cos(cos(x)) |
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| 23. |
(a) 5000(b) 4950(c) 4980(d) 4900 |
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| 24. |
15. A can solve 90% of the problems given in a book, and B can solve 70%. What is the probability thatatleast one of them will solve a problem selected at random from the book?rcentage of cases are they |
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Answer» Probability of A to solve the problem=9/100=0.9 and probability of B to solve the problem=70/100=0.7hence required probability=1-0.9*1-0.71-0.01=0.97 probability of A to solve the problem 9/100=0.9 and probability of B solve the problem 70/100=0.7 hence required probability=1-0.9*10.71-0.01=0.97 it is the correct answer. |
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| 25. |
A bataman acored 75 runs which ineluded a boundaries and B sixes. What per cent of his totalncore did he make by running between the wieketa? |
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| 26. |
jamy was playing with marbles she take 5 how many laft |
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Answer» question is incomplete answer is not completed Incomplete question 😎 |
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| 27. |
A Text Book of Mathematics |
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Answer» given the side of the rhombus = 10cm and one of the diagonal is = 16cm so, half of diagonal = 8cm now the other diagonal = 2*√10²-8² = 2*6 = 12cm so area = 1/2*d1*d2 = 1/2*16*12 = 96cm² |
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| 28. |
1) 12 farmers harvest the crops in the field in 20hours.Howmanyworkerswillberequiredto do the same work in 15 hours? |
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| 29. |
In the following APS, find the missing orin the boxes02. 2Text book problemw. DOD- |
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| 30. |
Mohita's mother is four times as old as Mohita. After five years, her mother will be three times asold as she will be then. What are their present ages ? |
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| 31. |
Thereare25radios,16of them are out of order. What per cent of radios areout of order? |
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| 32. |
A shopkeeper sold an article of Rs.754 and got profit of 16% what should be the puurchase price ofthe article?(1) Rs.620)(2) Rs.630(3) Rs.640(4) Rs.65 |
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Answer» Let the purchase price be ₹ XThen, (100+16)/100 * X = 754=> (116/100)*X = 754=> (29/25)X = 754=> X = (754*25)/29=> X = ₹ 650 Please hit the like button if this helped you |
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| 33. |
the total sarface area of a hemisphere of radios 10 cm. (Use r-3.14) |
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Answer» Total surface area = TSA = 3 π r2 = 3*3.14*10*10 = 942 cm² |
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| 34. |
7.24 workers can build a wall in 15 days. How many days will 9 workers take to build a simillar wall ? |
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| 35. |
7, 24 workers can build a wall in 15 days. How many days will 9 workers take to build a simillar wall ? |
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| 36. |
9. A cricketer scored a total of 62 runs in 96 balls. He hit 3 sixes, 8 fours, 2 twos and bsingles. What percentage of the total runs came irn |
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| 37. |
h n eacan reap field in 30 days. How many men must be engaged to reap the same fieldin 24 days? |
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| 38. |
16. 24 workers can build a wall in 15 days.How many days will 9 workers take to build asimilar wall? |
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| 39. |
can plough a field in 6.5 h, how much time will 5 tractors take to plough the same field? |
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Answer» 3 tractors plough field in 6.5 hrs1 tractor plough field in 6.5*35 tractor can plough field in6.5*3/5 = 1.3*3 = 3.9 hrs |
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| 40. |
17· The price of a sweater is increased by 8%. If its increased price is1566, find theoriginal price |
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| 41. |
24 workers can build a wall in 15 days. How many days will 9 workers take to build asimilar wall?14. If 420 |
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| 42. |
sixteen workers take 12 hours to build the wall. how many hours will be 12 workers need to build the same wall? |
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| 43. |
Find CP if the loss percentage is 18% and theselling price is 287 |
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| 44. |
The price of a book is increased by 12%. If its increased price is Rs 145.60, find the original price. |
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| 45. |
be the centeit makes one completei.e., in position Q1 AB-r circumference of the circle-2 π ( 1)2 πI:ordinates of C, are (1+2 t, 1) and radius of the cirele, the required equation of the circle is(x-1-2r)2 + (y-1)2=1mple 14. Find the radius of the circleis a variable, find the locus of the centre of the alcentre and radius of the locus.ution. The given equation of the circle is(x cos α + y sin α-a)2 + (x sin α _ y cos α-b)x2 (cos2 α + sin2 α) + 3,2 (sin2 α + cos2 α) + α2 + b2-2x (a cos α + b sin α)-2y (a sin α_bcx2 + y2-2(a cos α + b sin α) x-2(α sin α-bcos+ (a2Centre is (a cos α + b sin α), (a sin α-b cos α)Radius = V g2 + f2-c |
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Answer» please specify your question what is your doubt |
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| 46. |
reprice of a sweater is increased by 8%. If its increased price isrighal price.1566, fin |
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Answer» uykggskgsgsggkkykydykkyskysyk |
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| 47. |
A Mobile was bought for the rs 640 and sold for rs450.find the gain or loss percentage |
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Answer» CP = Rs 640SP = RS 450As CP > SP, there is a lossLoss = SP - CP = 640 - 450 = 190Loss % = 190/640 × 100 = 29.6 % From which book have you taken this question? Please tell us so that we can provide you faster answer. |
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| 48. |
19Mohita sold two radios at t 4000 each. First radiowas sold at 5% profit and second at 5% loss.Find the profit and loss percentage. |
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| 49. |
3 times of a number added by 8, then the result is 19. Write irnequation form for this data. |
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Answer» (1)equation using two variablesnumber is 10x+yso 3 times of that number is 30x+3ynow that is added by 8 which is equal to 19so equation is30x+3y+8=19(2)equation using one variablenumber is xso 3 times of that number is 3xnow that is added by 8 which is equal to 19so equation is3x+8=19 |
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| 50. |
There are 180 working days in the first term of a school. If Kanika has 75% attendhow many days did Kanika attend the school in the first term? |
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Answer» Number of working days in first term = 180 Kanika has 75% attendance Therefore, Number of days Kanika attend the school= (75/100)*180= 15*18/2= 15*9= 135 days |
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