1.

(sin)cosx

Answer»

Letu=cos(x)⇒du/dx=−sin(x)

Lety=sin(u)⇒dy/du=cos(u)

Butdy/du×du/dx = du/du×dy/dx = 1×dy/dx = dy/dx

⇒dy/dx=−sin(x)cos(u)

butu=cos(x)giving:

⇒dy/dx=−sin(x)cos(cos(x))


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