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3x+6-2x+1=7x+7=7x=7-7x=1

sorry. its x=0

1) 3x + 6 - 2x +1 =7 (3-2)x + 7 = 7 x = 7-7 x = 0

2) 5(x-1) +2(x+3) +6 = 0 5x - 5 +2x + 6 +6 = 0 (5+2)x +1 +6 =0 7x = - 7 x = - 1

Huygens principle states that each point of a wavefront is the source of secondary wavelets (small waves) which spread in all directions with the speed of the wave. The new wavefront is formed by drawing a line tangent to all the wavelets

Thanks

Area of Sector is = (Theta/360) ✖ pi ✖ r^2 = (45/360)*(22/7)*12*12 = 88 sq. cm.

Area of circle = pi ✖ r^2 = (22/7) 12 ✖ 12 = 3168/7 sq.cm

area of Sector AOB = (3168/7) - 88 = 2552/7 sq cm..

difference between area of Sector AOB and area of Sector OAB = (2552/7) - 88 = 1936/7 sq.cm (ANS)

if you like the answer, Mark it as best bro..

if u like the answer,mark it as best

o is center of the circle then :-45°=[45×π÷180]=π/4r=12 then 1/2×12×12×π/418πsq cm

teeno rule se bataiye

y - 8 = 4y = 4+8y = 12

My dear friend, thank you very much

x*x*x*x - 2x*x*x - 7x*x + 8x + 12 = x*x*x*x - 2x*x*x - 7x*x + 14x - 6x + 12 = x*x*x(x-2)-7x(x-2)-6(x-2) = (x-2)(x*x*x-7x-6) = (x-2)(x*x*x+x*x-x*x-x-6x-6) = (x-2)(x+1)(x*x-x-6) = (x-2)(x+2)(x-3)(x+2)

zeroes are -2,2,3

Area of the sector = 1/2 x ( length of the corresponding arc) x radius

= (1/2) x 12 x 6

= 36 cm²

Area of sector -> (pi)r(square)(theta)/360Length of an arc of a sector of a circle with radius -> picircumference of a circle/radius of a circle -> 2(pi)r(theta)/360area of 1/4 of a circle -> (pi)r(square)/4

x=10\7 is the right answer

48x-80-40x+80×4=8048x-40x=80+80-80×48x=80×48x=320x=320÷8x=40

( 48x -80) -10(16x-32) =8048x-80 -160x+320=80-112x +320-160=0-112x+160x= 160÷112x= 1.42

wrong

Sorry for the error in the previous answer. This one is the correct solution.

calculations is wrong i think so

coz, ans is 6361.72 sq.cm

5x - (4y- (7x-3z+2y +4z - 3x - 9y + 6z))= 5x - (4y-(4x - 7y + 5z))= 5x - (4y-4x+7y-5z)= 5x - 4y + 4x - 7y + 5z= 9x - 11y + 5z

1). Chord PQ = RS so m(arc PQ) = m( arc RS) = 80 degree.2). m (arc QS) = 360- 80-80-70 = 130.3). m (arc QSR) = 130 + 80 = 210.

The trace of a matrix is sum of its diagonal element for that i = j

so the first element will be aij = (i+j)² = (2i)² = 4 the second element of trace is = (2+2)² = 16the third element of trace will be (3+3)² = 36

so, the trace = sum of all even no. squares => 2n(n+1)(2n+1)/3.

thanks

diameter=17mradius=17/2=8.5mcircumference=2πr=3.14×2×8.5then arc, RS =circumference/2=3.14×8.5m

26.69 is the correct answer of the given question

Increased by 30%hence250*30/100=75 rupees increasehence250+75=325rupees in one dayIn 6 days=6*325=1950 rupees

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ok

x=2 y=1

x=1. aayga bhai a right answar hai bhai

4x + 6 = 104x = 10 - 64x = 4x = 4/4x = 1

3x - 4y = 10, 4x +3y =5; 4(3x-4y=10); 3(4x+3y =5); 12x - 16y = 40; 12x + 9y = 15; 12x +9y = 15/25y = 30; y = 30/25=6/5; 3x -4(6/5)=10; 3x = 10+ 24/5 = 50+24/5=75/5; x = 75 /5×3=25/5=5

-10/7 is correct answer.

thanka

If a solid is recasted in any other solid the volume remains the same.so,vol.of sphere=vol. of cylinder•4/3πr cube= 2πr square ×h 4/3×22/7×42/10×42/10×42/10 = 2×22/7×6×6×hh= 98.784/36H=2.744 cm

(2+a)^50=(a+2)^5017th term=18th term50C17*a^17*2^33=50C18*a^18*2^32so a=50C17*2/50C18a=(50!/33!*17! *2)/(50!/32!*18!)so a=2*32!*18*17!/(33*32!*17!)so a=2*18/33=36/33=12/11

Area of Sector is Theta/360*pi*r^2 = 60/360*22/7*12*12 = 75.4 sq. cm.

Area of equilateral triangle.

Since the triangle is an equilateral triangle, then height is sqrt (12*12-6*6) = sqrt(144-36) = sqrt(108) = 10.39

Therefore area = 1/2 * 10.3923 * 12 = 10.39 * 6 = 62.35 sq. cm

Thus, the difference between areas of sector and triangle is = 75.4 - 62.35 = 13.05 sq. cm.

volume of cone= πr^2h /3=22/7 ×(7)^2×(12) /3= 3.14×49×12/3=1848/3= 616cm^3

vol of cone is 1/3πr^2×h=1/3×22/7×7×7×12=1/3×22×7×12=1848/3=616cm^3 is correct answer 100%

(b) 7cm or 1cmIf two circles touch internally then the distance between their centres is equal to the difference of their radii.4 - 3 = 1cmIf two circles touch externally then the distance between their centres is equal to the sum of their radii.4 + 3 = 7cmTherefore either 7cm or 1cm.

Here there is a mistake in the given area. the area should be 2400 cm^2

Two sevens are fourteen.