Saved Bookmarks
This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Q.4.Find the sum:-a) 71.15, 1.306, 77.702(bot 6.032, 8.45, 16.020 |
|
Answer» a) 150.158b)30. 102 questions no a= answer 150.158 and b=answer is 30.502 71.15+ 1.306+ 77.702____________ 150.158 6.032+ 8.45+ 16.02___________ 30.502 |
|
| 2. |
ABCD is a trapezium in which AB I DC, BD is a diagonal and E is the mid-poiline is drawn through E parallel to AB intersecting BC at F (see Fig. 8.30).is the mid-point of BC |
| Answer» | |
| 3. |
e given fig. AB || CD, find x.13590° |
| Answer» | |
| 4. |
axis, T)oint on the x-axis, which is equidistant from the poi(, aku(3,4tn he slope of a line, which passes through the origin, and the mid-point of the5 ine segment joining the points P (O, -4) and B (8.0) |
| Answer» | |
| 5. |
ABC, L is the mid point of BC and Mis the mid point of AL(C) In A ABCMintersects AC at N, LP | BN.Prove that: AN= =w |
|
Answer» Through D,Draw DK||BN.In triangleADK, M is the mid-point of ADand MN||DK.Therefore, N is the mid-point of AK.Hence, AN=NK.............(i)In triangleBCN,D is the mid-point ofBCand BN||DK.Therefore,K is the mid-point of NC.Hence, KC=NK.............(ii)From (i) and (ii),AN=NK=KC..............(iii)Now, AC=AN+NK+KCAC=AN+AN+ANAC=3ANtherefore, AN=1/3AC. |
|
| 6. |
ll she used 1,2 g o mgredients, now mucn ol each Item did She use?3 Jagan and Ravi share720 in the ratio 7:5 respectively. How much did each get? |
|
Answer» Hello ye ATQ kya hai according to question,ATQ but how as given both have total 720 rupee so we just add the ratio |
|
| 7. |
Ravi took a loan of Rs.12000 at 12% p.a.Find the amount to be paid by Ravi after3years at S.L.?1) Rs.16,230 2) Rs.14,3203) Rs.16,3204) |
|
Answer» Rs 12000+[(12000*12*3)/100]Rs12000+432000/100Rs 12000+4320Rs 163203) rs 16320 is the right answer |
|
| 8. |
Fill the kox i the numb ertde oumIoside bot you car choorCP |
| Answer» | |
| 9. |
2. Find the values of k for which the roots are real and equal in each of the followingequations:(i) kor? + 4x + 1 = 0(ii) kox? - 2/5x + 4 = 0 |
| Answer» | |
| 10. |
\left. \begin{array} { l } { 3 x - y = - 2 } \\ { 3 x + 4 y = - 17 } \end{array} \right. |
|
Answer» the answer is wrong |
|
| 11. |
\begin{array} { l } { 3 x + 2 y = 4 } \\ { 2 x - 3 y = 7 } \end{array} |
| Answer» | |
| 12. |
Give the classical definition of probability and point out its limitations. |
|
Answer» Ifnis the number of equally likely, mutually exclusive and exhaustive outcomes of a random experiment out of whichmoutcomes are favorable to the occurrence of an event A, then the probability that A occurs, denoted by P(A), is given by : P(A) =Number of outcomes favorable to A/Number of exhaustive outcomes= m/n |
|
| 13. |
9.Find the sum of first 8 multiples of 3.hich P(4 m divides the line segment joining the poi |
| Answer» | |
| 14. |
in fig., AB POI CD, AB = x units. CD =y units and PQ = z units. Prove that |
| Answer» | |
| 15. |
ct=a+b221 D, E and F are the mid poiABC. Find the ratio of a |
|
Answer» X/a + y/b = a+b ⇒y/b = a + b - x/a .................. i x/a² + y/b² = 2 ................ii ⇒x/a² + y/b x1/b = 2 ⇒x/a² + a+b/b- x/ab= 2 puttting i ⇒x(b-a)/a²b = (b-a)/b ⇒x = a² so x = a² using ii we get y = b² so x=a² and y=b²ANSWER |
|
| 16. |
the line and y-ais7,Find the distance between the lines 3x + 6 = 0 and x-7 = 0.AD is (AIf the co-ordinates of poi |
|
Answer» 3x+6=03x=-6x=-6/3=-2x-7=0x=7 The distance between(-2,0) and (7,0)= √(x1-x2)^2+(y1-y2)^2=√(-2-7)^2+(0)^2=√(-9)^2=√81=9units |
|
| 17. |
1If the distance between the points (4.k) and (1,0) is 5, then what can be the Ipossible values of k? |
|
Answer» Distance is 5 (4-1)(4-1) + (k-0)(k-0) = 5*5 3*3 + k*k = 25 k*k = 25 - 9 = 16 by taking square root k = -4,4 If you find this answer helpful then like it. |
|
| 18. |
\left. \begin{array} { l } { 3 x ^ { 2 } - 9 x - 5 } \\ { b \text { of } 2 x + y = 3 } \end{array} \right. |
|
Answer» 55. 2x+y = 3 |
|
| 19. |
\begin{array} { l } { 3 x - 4 y + 7 = 0 } \\ { k x + 3 y - 5 = 0 } \end{array} |
|
Answer» is it kx??? or 12 x please verify it I did it assuming it as a 12 xI did it with the help of elimination methodI tried to make the cofficient of x same in both the equation so I multiplied with 4 x= 4.719 |
|
| 20. |
as much soil as the5. Ravi used 1 bags of soil for his garden. He is digging another garden that will needoriginal. How much soil will he use in total? |
| Answer» | |
| 21. |
\left. \begin{array} { l } { - 7 x ^ { 3 } + 3 x ^ { 2 } + 11 x - 9 \text { for } x = - 2 } \\ { 4 y ^ { 2 } - 3 y + 8 \text { for } y = - 3 } \\ { 14 x ^ { 2 } y + 3 x y ^ { 2 } + 2 x y - 5 \text { for } x = 1 \text { and } y = ? } \end{array} \right. |
|
Answer» the value of a) when x = -2 , -7(-2)³+3(-2)²+11(-2)-9 = +56+12-22-9 = 37b) when y =-3, 4(-3)²-3(-3)+8 = 36+9+8 = 53.c) when x = 1 and y = 2 14(1)²(2)+3(1)(2)²+2(1)(2)-5 = 28+12+4-5 = 39 |
|
| 22. |
\left. \begin array l 3 x %2B 4 y = 11 \\ 5 x - 2 y = 1 \end array \right. |
| Answer» | |
| 23. |
\left. \begin{array} { l } { \text { The coefficient of } x ^ { 2 } \text { in } ( x - 13 ) ( x + 11 ) ( x - 9 ) \text { is } } \\ { ( x ) - 11 } \end{array} \right. |
|
Answer» a) is correct option thank you |
|
| 24. |
x \text { if } ( \frac { s } { 11 } ) ^ { - 5 } \times ( \frac { 8 } { 11 } ) ^ { x } = ( \frac { 8 } { 11 } ) ^ { - 2 } |
| Answer» | |
| 25. |
\frac { ( x + 1 ) ( x + 2 ) } { ( x + 11 ) ( x - 2 ) } = 1 |
| Answer» | |
| 26. |
Prove that l 1x11=(x+2) (x-1)2 |
| Answer» | |
| 27. |
\frac { 4 x ^ { 2 } - 11 x + 7 } { x - 1 } |
| Answer» | |
| 28. |
((3/5)^3*(1/7)^3)/(((3/5)^2*(1/7)^4)) |
|
Answer» 4.2 is the correct answer 21/5 is the right answer 21/5 is the right answer |
|
| 29. |
For each of the differential equations in Exercises from 11 to 15, find the pasolution satisfying the given condition:11.(x + y) dv +(x-y) dr = 0; y = 1 when x = 1 |
| Answer» | |
| 30. |
\left. \begin{array} { l } { \text { Factors of } x ^ { 3 } - 6 x ^ { 2 } + 11 x - 6 \text { is } } \\ { ( A ) ( x - 1 ) ( x + 2 ) ( x - 3 ) } \\ { ( C ) ( x + 1 ) ( x + 2 ) ( x + 3 ) } \end{array} \right. |
| Answer» | |
| 31. |
(d) Find a unit vector perpendicular to both thevectors a = 47-1 +3k and |
| Answer» | |
| 32. |
le 1. Find the transpose of each of the following matricesÎ-1 51 -1(ii) V3 5 62 3 -1 |
| Answer» | |
| 33. |
1. (i) State the order and the type of the followingmatrices :1 2 31-25 o(b) |
|
Answer» a --- 2×3b --- 4×1 it is the correct answer of this question a) order 2×3b)order 4×1,row matrix a_2×3b_4×1it is the right answer of this question a,2×3b,4×1is the right answer of question order of matrix a is 2*3order of matrix b is 4*1 a, 2(rows)*3(columns)b, 4(rows)*1(column) |
|
| 34. |
Find the matrix of co-factors for thefollowing matrices.1 3 74 -1 |
| Answer» | |
| 35. |
(1)With reference to the given figure, write the union set of ray PQ and ray QR. |
|
Answer» hii sanket i am vaibhav Divekar i have aso download this app |
|
| 36. |
6.7.Find 0.11 x 1.31111From the figure write the name of: -(a) All triangles so formed.(b) The three angles of AAED |
|
Answer» 6 triangles are there 6 is the correct answer of the given question i. 6 is the correct answer of the following question |
|
| 37. |
|41/3) 42(4) 38दो अंकों की अभाज्य संख्याएँ जिनके दोनों अंक भी| अभाज्य संख्याएँ हैं, की संख्या है।(1) 3(3) 6(4) 82.002x15+0.04705+0.02295 को सरल करनेर प्राप्त होता है।) 30.037(2) 30.730| 30.073(4) 30.1* प्रथम 10 गुणजों का योग है। |
|
Answer» 2.002×15+0.04705+0.02295 = 30.1 ha 24+[6-{5-2(4-3)}](1)22(2)23(3)24(4)27 24+[6-{5-2(4-3)}] उतर(1).22. (2) (23) ( 3) (24) (4) 27 |
|
| 38. |
State and prove inclusion and exclusionprinciple. |
| Answer» | |
| 39. |
3). अवयव सिद्धांताचा उपयोग करून (४ - 2) हा »' - 42 - 4 चा अवयव आहे की नाहीते ठरवा. |
| Answer» | |
| 40. |
3. Find the adjoint of the following matrices1-1 -2 37[2] (42-4 -5 25 |
| Answer» | |
| 41. |
In figure write all pairs of adjacent angles and all the linear pairs. |
|
Answer» Adjacent angles are AOD and DOC , DOC and COB while linear pairs are only 2. angle. AOD and DOB and , angle AOC and COB. |
|
| 42. |
8. Using Identity find the value of 97103 |
|
Answer» 97 x 103=(100-3)(100+3) ; (a-b)(a+b)=(a^2-b^2); a=100; b=3; (100)^2-(3)^2=10000-9=999 97×103(100-3)(100+3)(100)^2-(3)^210000-99901 sorry 9991is answerthat is right (100-3)×(100+3) after it the answer will be 9991 97×103(100-3)(100+3)(a-b)(a+b)=a^2-b^2(100)^2-(3)^210000-9=9991 |
|
| 43. |
suitable identityFind Value using(a) 95x105 |
|
Answer» 200 is a correct answer (100-5)(100+5)=100×100-5×510000-25=9975 |
|
| 44. |
3 Using identity, find the value of (2x + 3)2 |
|
Answer» Identity used ( a + b)² = a² + b² + 2ab So, ( 2x + 3)² = 4x² + 9 + 12x |
|
| 45. |
Solve the following simultaneou(1) 3 42 4 |
| Answer» | |
| 46. |
Find all possible pairs of integers that give a product of -50 |
|
Answer» 5 is correct answer ........ 5 is a correct answer,,...... 5 is the best answer. 5is the correct answer of the following question. -5×10-10×5..is the possible pair -5 and 10-10and 5...is right pair 5 is the answer............ |
|
| 47. |
Give an example of product of two irrational numbers is rational |
| Answer» | |
| 48. |
y systematic method\frac{20 x}{7}=60 |
|
Answer» (20x)/7 = 6020x = 60×7x = (60×7)/20x = 3 × 7 x = 21 |
|
| 49. |
1. Using appropriate properties find.2 3 5 3 1+Ñ…256 |
|
Answer» 2 is the correct answer |
|
| 50. |
Sum of the present ages of Mälisli ald Us 31. Manish's age 3 years ago was 4 tinghe age of Savita. Find their present ages.4n: |
|
Answer» Let, the age of manish =xAge of savita = y____, x+y = 31 ---1equation ______ 3 years ago, Manish's age = (x-3) yearsSavita's age = (y-3) years ___________According to the given information, (x-3) =4(y-3) x-3 =4y -12 x =4y -12 +3 x = 4y -9 Putting the value of x in equation 1, x +y =314y -9 +y =315y =31+9 5y =40 y =40/5y =8 Putting the value of y in 1equation, x+y =31x +8=31 x =31-8x =23 Age of manish =x =23 years Age of savita =y =8 years |
|